Irrigation Association Certified Irrigation Designer — Agriculture (CID)

USA · Irrigation Association · professional

89practice questions written to this syllabus
5subjects

Format

General Ag exam (150 MCQs, 4 h) plus a specialty exam — Drip/Micro (75 questions, 4 h) or Sprinkler (50 questions, 4 h) — all within 3 years.

Sections

Over the years

The clearest published content blueprint for irrigation design anywhere; useful to irrigation designers in any country.

Official source: https://www.irrigation.org/IA/FileUploads/IA/Certification/CertificationCandidateHandbook.pdf

Subjects this exam draws on

Fluid Mechanics & Open Channel Hydraulics14 questionsIrrigation Engineering (Soil-Water-Plant, Conveyance, Surface Methods)21 questionsSprinkler & Micro-Irrigation Systems37 questionsGroundwater, Wells & Pumps10 questionsProtected Cultivation & Greenhouse Engineering7 questions

Five practice questions, worked

Original questions written to this exam's published syllabus and pattern. Not past papers.

1. A 200 mm diameter pipe carries 50 L/s of water. What is the mean velocity?

  1. 1.25 m/s
  2. 15.9 m/s
  3. 0.398 m/s
  4. 1.59 m/s
Answer and working

D. 1.59 m/s

Q = 50 L/s = 0.05 m³/s; A = π(0.2)²/4 = 0.0314 m²; V = Q/A = 1.59 m/s. Using πD² without the 1/4 gives 0.398 m/s; converting 50 L/s to 0.5 m³/s gives 15.9 m/s. 1.25 m/s divides by D² and forgets π/4.

Fluid Mechanics & Open Channel Hydraulics · Continuity equation

2. A clay loam has volumetric field capacity 0.32 and wilting point 0.14. With a 1.2 m root zone and a management allowed depletion of 50 %, what is the readily available water?

  1. 192 mm
  2. 84 mm
  3. 216 mm
  4. 108 mm
Answer and working

D. 108 mm

TAW = 1000 × (0.32 − 0.14) × 1.2 = 216 mm. RAW = 0.5 × 216 = 108 mm. 216 mm is TAW, not RAW; 192 mm applies MAD to field capacity alone; 84 mm applies it to the wilting point water, which is unavailable.

Irrigation Engineering (Soil-Water-Plant, Conveyance, Surface Methods) · Soil-water-plant relations: field capacity, wilting point and MAD

3. On a centre pivot with sprinklers at equal spacing along the lateral, how must the discharge of each sprinkler vary with its distance r from the pivot to apply a uniform depth?

  1. In proportion to r
  2. Constant along the lateral
  3. In proportion to r²
  4. In inverse proportion to r
Answer and working

A. In proportion to r

Each sprinkler at radius r with spacing s serves an annulus of area about 2πr·s per revolution, so for equal depth its discharge must be proportional to r. Discharge proportional to r² would be the case only if the ring area grew with r², which it does not for a fixed spacing.

Sprinkler & Micro-Irrigation Systems · Sprinkler types and components

4. During a 48-hour pumping test the crew discharges the pumped water into a ditch 20 m from the well, over permeable sand. The likely effect on the results is:

  1. No effect, because the water has already been counted in Q and the ditch is outside the cone of depression
  2. Recirculation recharges the aquifer, flattening drawdown: T is overestimated or a false recharge boundary appears
  3. Drawdown increases because the ditch water blocks recharge, so T is underestimated
  4. The storativity result becomes negative, but transmissivity is unaffected because Q is unchanged throughout the test
Answer and working

B. Recirculation recharges the aquifer, flattening drawdown: T is overestimated or a false recharge boundary appears

Water returned near the test well infiltrates and partly supplies the pumping, flattening the late drawdown curve. Pumped water must be piped well away from the cone of depression.

Groundwater, Wells & Pumps · Pumping tests

5. A 2,000 m² greenhouse has a crop water use of 5 mm/d and a drip application efficiency of 90%. There are 6,000 plants, each on one 1.6 L/h dripper. How long must the system run each day?

  1. 63 min
  2. 69 min
  3. 1.2 min
  4. 694 min
Answer and working

B. 69 min

Volume = 2,000 × 0.005 / 0.9 = 11.11 m³/d. Flow = 6,000 × 1.6 = 9,600 L/h = 9.6 m³/h. Time = 11.11 / 9.6 = 1.157 h = 69 min. 63 min ignores efficiency; 1.2 min is hours mislabelled as minutes; 694 min is a factor-of-ten slip.

Protected Cultivation & Greenhouse Engineering · Micro-irrigation and fertigation in greenhouses

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