Philippines · Professional Regulatory Board for Foresters, Professional Regulation Commission · licensing · unverified source
Written examination on four subjects set in RA 10690; pass requires a general weighted average of 75%. Dates are set by the PRC master schedule.
The four subjects and the 75% rule are from the text of the Forestry Profession Act (RA 10690, 2015), read in the LawPhil law library rather than on a PRC page, so the row stays unverified. The Act also requires a forestry degree from a CHED-recognised school; the Board may revise syllabi with PRC approval. Item counts and weights per subject were not checked.
Official source: https://www.prc.gov.ph/
Original questions written to this exam's published syllabus and pattern. Not past papers.
1. Which statement about professional recognition of foresters is correct?
D. Some license foresters by law; others use chartered membership
The Philippines and several Canadian provinces and US states license or register foresters; the UK, Australia and others use chartered or registered membership of professional bodies.
Introduction to Forestry & the World's Forests · Branches of forestry and the forester's professional roles worldwide
2. Earlywood and latewood together form:
B. A growth ring
Seasonal changes in cambial activity produce growth rings, usually annual.
Forest Botany & Plant Systematics · Plant cell, tissues and secondary growth
3. Why should blazes be small and avoided on valuable trees and research plots?
D. They open wounds to pathogens
Blazes are wounds; minimise them.
Dendrology & Tree Identification · Field characters: bark, blaze, leaf arrangement, stipules, exudates
4. Which group consists of shade-intolerant (light-demanding) species?
B. Pines, larches, birches and poplars
Pioneer genera such as pines, larches, birches and poplars demand light; firs, hemlocks, beeches, yews and sugar maple are classically shade-tolerant.
Tree Physiology · Photosynthesis in trees: C3 pathway, light response, shade tolerance
5. A prescription calls for 200 kg N ha⁻¹ as urea (46% N). How much urea is needed per hectare?
A. 435 kg
200/0.46 = 435 kg. 92 kg multiplies by 0.46 instead of dividing.
Forest Soils & Soil Conservation · Forest soil fertility, fertilisation of plantations
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