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IIT JAM Differential Equations, Finite Differences & Numerical Analysis: practice questions

IIT JAM - Mathematical Statistics (MS) · India · IITs (JAM 2026 organised by IIT Bombay)

Original practice questions written to the published syllabus · not past papers
10worked here, free
22written to this exam in this subject
11syllabus units

What this subject covers

Ordinary differential equations, interpolation, numerical differentiation and integration and root-finding: what AIEEA-PG Group 07 names explicitly, and what growth models, life tables and iterative estimation (Newton-Raphson for maximum likelihood) rely on.

In the exams: AIEEA-PG Group 07 Units II-III (heavy: differential equations, finite differences, interpolation, numerical integration, Newton-Raphson named); AICE-JRF Computer Application Unit 10 numerical analysis (heavy)

Where the 22 questions fall

How our questions for IIT JAM spread across the units of Differential Equations, Finite Differences & Numerical Analysis. Difficulty: 3 easy, 14 medium, 5 hard.

Ordinary differential equations of first order: exact, linear and Bernoulli equations3
Higher-order linear equations: complementary function and particular integral3
Numerical differentiation2
Numerical integration: trapezoidal and Simpson's rules2
Difference equations2
Solution of non-linear equations: bisection and Newton-Raphson2
Solution of linear systems: Gaussian elimination and iterative methods2
Numerical solution of ODEs: Euler and Runge-Kutta methods2
Coordinate geometry of conics2
Calculus of finite differences and difference operators1
Interpolation: Newton forward and backward, Lagrange and divided differences1

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Ordinary differential equations of first order: exact, linear and Bernoulli equations · hard

With K = 1,000, N₀ = 100 and r = 0.5, the logistic solution N(t) = K/(1 + Ae^(−rt)) gives N(2) of about:

  1. 165
  2. 500
  3. 232
  4. 272
Answer and working

C. 232

A = (1,000 − 100)/100 = 9; N(2) = 1,000/(1 + 9e^(−1)) = 1,000/4.311 ≈ 232. 272 uses unchecked exponential growth 100e¹.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

2 · Higher-order linear equations: complementary function and particular integral · easy

A particular integral of y″ − 3y′ + 2y = e^(3x) is:

  1. e^(3x)/2
  2. e^(3x)/20
  3. xe^(3x)
  4. e^(3x)/6
Answer and working

A. e^(3x)/2

1/f(D) e^(3x) = e^(3x)/f(3) with f(3) = 9 − 9 + 2 = 2.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

3 · Higher-order linear equations: complementary function and particular integral · hard

A particular integral of y″ − 4y = e^(2x) is:

  1. e^(2x)/4
  2. e^(2x)
  3. xe^(2x)/4
  4. xe^(2x)/2
Answer and working

C. xe^(2x)/4

f(2) = 0 (resonance); y_p = x e^(2x)/f′(2), and f′(m) = 2m gives 4.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

4 · Calculus of finite differences and difference operators · medium

The relation between the shift operator E and the derivative D is:

  1. E = 1 + hD exactly
  2. E = hD
  3. E = log(hD)
  4. E = e^(hD)
Answer and working

D. E = e^(hD)

Taylor's theorem: f(x + h) = Σ hⁿDⁿf/n! = e^(hD)f; 1 + hD is only the first-order part.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

5 · Interpolation: Newton forward and backward, Lagrange and divided differences · medium

The Lagrange polynomial through (1, 2), (2, 3) and (4, 11) takes the value at x = 3:

  1. 7
  2. 5
  3. 8
  4. 6
Answer and working

D. 6

The quadratic is x² − 2x + 3; at 3: 9 − 6 + 3 = 6.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

6 · Numerical differentiation · medium

The standard approximation of f″(x) from three equally spaced values is:

  1. [f(x + h) − f(x − h)]/(2h)
  2. [f(x + h) − f(x)]/h²
  3. [f(x + h) + 2f(x) + f(x − h)]/h²
  4. [f(x + h) − 2f(x) + f(x − h)]/h²
Answer and working

D. [f(x + h) − 2f(x) + f(x − h)]/h²

It is the second central difference divided by h².

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

7 · Solution of non-linear equations: bisection and Newton-Raphson · medium

Newton–Raphson for x³ − x − 1 = 0 from x₀ = 1.5 gives x₁ of about:

  1. 1.3478
  2. 1.3247
  3. 1.4000
  4. 1.6250
Answer and working

A. 1.3478

f(1.5) = 0.875, f′(1.5) = 5.75; 1.5 − 0.875/5.75 ≈ 1.3478. 1.3247 is the root itself.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

8 · Numerical solution of ODEs: Euler and Runge-Kutta methods · medium

For y′ = y, y(0) = 1, h = 0.1, the classical RK4 method gives y₁ = 1.1051708. The error compared with e^0.1 is about:

  1. 10⁻³
  2. 10⁻²
  3. 10⁻⁵
  4. 10⁻⁷
Answer and working

D. 10⁻⁷

e^0.1 = 1.1051709; the difference is about 8 × 10⁻⁸.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

9 · Numerical solution of ODEs: Euler and Runge-Kutta methods · hard

For y′ = −50y, Euler's method is stable only if the step h is less than:

  1. 0.02
  2. 0.5
  3. 0.04
  4. 2
Answer and working

C. 0.04

Stability needs |1 − 50h| < 1, i.e. h < 2/50 = 0.04.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

10 · Coordinate geometry of conics · medium

The eccentricity of the hyperbola x²/16 − y²/9 = 1 is:

  1. 0.8
  2. 1.25
  3. 1.33
  4. 0.75
Answer and working

B. 1.25

e = √(1 + 9/16) = 5/4.

Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)

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Differential Equations, Finite Differences & Numerical AnalysisThe full study manual, free IIT JAMFormat, sections and how it has changed

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