IIT JAM - Mathematical Statistics (MS) · India · IITs (JAM 2026 organised by IIT Bombay)
Original practice questions written to the published syllabus · not past papersOrdinary differential equations, interpolation, numerical differentiation and integration and root-finding: what AIEEA-PG Group 07 names explicitly, and what growth models, life tables and iterative estimation (Newton-Raphson for maximum likelihood) rely on.
In the exams: AIEEA-PG Group 07 Units II-III (heavy: differential equations, finite differences, interpolation, numerical integration, Newton-Raphson named); AICE-JRF Computer Application Unit 10 numerical analysis (heavy)
How our questions for IIT JAM spread across the units of Differential Equations, Finite Differences & Numerical Analysis. Difficulty: 3 easy, 14 medium, 5 hard.
| Ordinary differential equations of first order: exact, linear and Bernoulli equations | 3 | |
| Higher-order linear equations: complementary function and particular integral | 3 | |
| Numerical differentiation | 2 | |
| Numerical integration: trapezoidal and Simpson's rules | 2 | |
| Difference equations | 2 | |
| Solution of non-linear equations: bisection and Newton-Raphson | 2 | |
| Solution of linear systems: Gaussian elimination and iterative methods | 2 | |
| Numerical solution of ODEs: Euler and Runge-Kutta methods | 2 | |
| Coordinate geometry of conics | 2 | |
| Calculus of finite differences and difference operators | 1 | |
| Interpolation: Newton forward and backward, Lagrange and divided differences | 1 |
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
With K = 1,000, N₀ = 100 and r = 0.5, the logistic solution N(t) = K/(1 + Ae^(−rt)) gives N(2) of about:
C. 232
A = (1,000 − 100)/100 = 9; N(2) = 1,000/(1 + 9e^(−1)) = 1,000/4.311 ≈ 232. 272 uses unchecked exponential growth 100e¹.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
A particular integral of y″ − 3y′ + 2y = e^(3x) is:
A. e^(3x)/2
1/f(D) e^(3x) = e^(3x)/f(3) with f(3) = 9 − 9 + 2 = 2.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
A particular integral of y″ − 4y = e^(2x) is:
C. xe^(2x)/4
f(2) = 0 (resonance); y_p = x e^(2x)/f′(2), and f′(m) = 2m gives 4.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
The relation between the shift operator E and the derivative D is:
D. E = e^(hD)
Taylor's theorem: f(x + h) = Σ hⁿDⁿf/n! = e^(hD)f; 1 + hD is only the first-order part.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
The Lagrange polynomial through (1, 2), (2, 3) and (4, 11) takes the value at x = 3:
D. 6
The quadratic is x² − 2x + 3; at 3: 9 − 6 + 3 = 6.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
The standard approximation of f″(x) from three equally spaced values is:
D. [f(x + h) − 2f(x) + f(x − h)]/h²
It is the second central difference divided by h².
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
Newton–Raphson for x³ − x − 1 = 0 from x₀ = 1.5 gives x₁ of about:
A. 1.3478
f(1.5) = 0.875, f′(1.5) = 5.75; 1.5 − 0.875/5.75 ≈ 1.3478. 1.3247 is the root itself.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
For y′ = y, y(0) = 1, h = 0.1, the classical RK4 method gives y₁ = 1.1051708. The error compared with e^0.1 is about:
D. 10⁻⁷
e^0.1 = 1.1051709; the difference is about 8 × 10⁻⁸.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
For y′ = −50y, Euler's method is stable only if the step h is less than:
C. 0.04
Stability needs |1 − 50h| < 1, i.e. h < 2/50 = 0.04.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
The eccentricity of the hyperbola x²/16 − y²/9 = 1 is:
B. 1.25
e = √(1 + 9/16) = 5/4.
Further reading: Boyce, DiPrima and Meade, Elementary Differential Equations (2017); Burden, Faires and Burden, Numerical Analysis (2016); Hildebrand, Introduction to Numerical Analysis (1987); Thornley and France, Mathematical Models in Agriculture (2007)
Ten here, 22 in the app. The Laisha app has every practice question we have written to IIT JAM in this subject, marked as you go, with timed papers, a jump-to-unanswered list and a certificate when you pass at 70 per cent.
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