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GATE Post-Harvest Engineering of Horticultural Crops: practice questions

GATE — Agricultural Engineering (AG) · India · IITs and IISc on rotation (2026: IIT Guwahati)

Original practice questions written to the published syllabus · not past papers
10worked here, free
68written to this exam in this subject
11syllabus units

What this subject covers

Keeping fruits and vegetables alive and saleable after harvest: cooling, handling, packhouses, controlled atmospheres and processing.

In the exams: GATE AG Section 6 (processing of fruits, vegetables and spices; CA/MA storage); ICAR AICE subject 41

What GATE asks from it

GATE — Agricultural Engineering (AG)

Section 6 names processing of fruits, vegetables and spices and storage systems including CA/MA. Expect numerical items on moisture balances in drying, water removed, respiration heat and refrigeration load, half-cooling time and seven-eighths cooling, juice concentration and blending balances, and gas composition in CA/MA. Conceptual one-mark items test climacteric behaviour, ethylene, chilling injury, precooling method choice and dryer types.

Where the 68 questions fall

How our questions for GATE spread across the units of Post-Harvest Engineering of Horticultural Crops. Difficulty: 9 easy, 27 medium, 32 hard.

Pre-cooling: hydro, forced-air and vacuum cooling12
Dehydration of fruits and vegetables11
Respiration and ripening physiology9
Controlled and modified atmosphere storage9
Juice extraction8
Packhouse design5
Grading, including machine vision4
Value addition3
Processing of spices and plantation crops3
Washing, sorting and waxing2
Minimal processing2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Respiration and ripening physiology · easy

When malic acid (C4H6O5) is the main respiratory substrate, the respiratory quotient is about

  1. 1.00
  2. 1.33
  3. 0.70
  4. 0.75
Answer and working

B. 1.33

C4H6O5 + 3 O2 -> 4 CO2 + 3 H2O, so RQ = 4/3 = 1.33. An RQ of 1.0 applies to hexose sugars and about 0.7 to fats, which need more oxygen per carbon. 0.75 inverts the ratio (O2/CO2 = 3/4).

Further reading: Kader (ed.), Postharvest Technology of Horticultural Crops (UC ANR 3311)

2 · Respiration and ripening physiology · medium

A leafy vegetable respires at 60 mg CO2/kg h at 20 degC and its Q10 is 2.5 over 0 to 20 degC. Its respiration rate at 0 degC is about

  1. 12.0 mg CO2/kg h
  2. 24.0 mg CO2/kg h
  3. 375 mg CO2/kg h
  4. 9.6 mg CO2/kg h
Answer and working

D. 9.6 mg CO2/kg h

Twenty degrees is two Q10 intervals: R(0) = 60 / 2.5^2 = 60 / 6.25 = 9.6. 12.0 comes from dividing by 2 x 2.5 = 5 instead of 2.5 squared; 24.0 applies only one interval.

Further reading: Kader (ed.), Postharvest Technology of Horticultural Crops (UC ANR 3311)

3 · Pre-cooling: hydro, forced-air and vacuum cooling · hard

A forced-air cooler must remove 50 kW from produce. The air may warm by 3 K passing through the pallets. Taking air specific heat as 1.005 kJ/kg K and density 1.27 kg/m3, the required airflow is about

  1. 16.6 m3/s
  2. 21.1 m3/s
  3. 4.4 m3/s
  4. 13.1 m3/s
Answer and working

D. 13.1 m3/s

Mass flow = 50/(1.005 x 3) = 16.58 kg/s; volume = 16.58/1.27 = 13.1 m3/s. Quoting 16.6 m3/s treats kg/s as m3/s; 21.1 multiplies by density instead of dividing.

Further reading: ASHRAE Handbook — Refrigeration

4 · Pre-cooling: hydro, forced-air and vacuum cooling · medium

Compared with room cooling, forced-air cooling of the same packed produce is faster mainly because

  1. the air supplied is much colder than the air used in room cooling
  2. it adds a film of water to the product surface, which then evaporates and cools it
  3. a pressure difference forces cold air through the carton vents past each item
  4. the packages are unstacked and spread out on the floor before cooling
Answer and working

C. a pressure difference forces cold air through the carton vents past each item

In room cooling air flows around stacks and heat must conduct out through packages; forced-air cooling pulls air through aligned carton vents so each item is swept by cold air. The air temperature is typically similar in both methods.

Further reading: Thompson et al., Commercial Cooling of Fruits, Vegetables, and Flowers (UC ANR 21567)

5 · Pre-cooling: hydro, forced-air and vacuum cooling · hard

Removing field heat from 1 t of produce (specific heat 3.8 kJ/kg K) cooled by 25 K, with a refrigeration system of coefficient of performance 3, requires about how much electrical energy (ignoring fans and losses)?

  1. 8.8 kWh
  2. 26.4 kWh
  3. 79 kWh
  4. 31.7 kWh
Answer and working

A. 8.8 kWh

Heat = 1 000 x 3.8 x 25 = 95 000 kJ = 26.4 kWh. Electricity = 26.4/3 = 8.8 kWh. 26.4 kWh is the heat itself; multiplying by COP gives 79 kWh; 31.7 treats MJ as kWh.

Further reading: ASHRAE Handbook — Refrigeration

6 · Washing, sorting and waxing · medium

In chlorinated wash water, the pH is normally held near 6.5 to 7.5 mainly because

  1. chlorine is inactive below pH 8, so the dose must be buffered up to that level
  2. high pH dissolves the natural fruit wax and lets the chlorine penetrate deep into the flesh
  3. hypochlorous acid, the most effective form, dominates at slightly acidic to neutral pH
  4. low pH stops all chlorine loss, so no top-up dosing is ever needed during a shift
Answer and working

C. hypochlorous acid, the most effective form, dominates at slightly acidic to neutral pH

HOCl is a far stronger sanitiser than the hypochlorite ion, which dominates at high pH. Going much below pH 6.5 increases chlorine gas release and corrosion, so a slightly acidic to neutral band is used.

Further reading: Kader (ed.), Postharvest Technology of Horticultural Crops (UC ANR 3311)

7 · Controlled and modified atmosphere storage · hard

0.5 kg of produce with respiratory quotient 1 consumes 10 mL O2/kg h in a sealed film package of area 0.12 m2. The film's CO2 permeance is 24 000 mL/(m2 day atm) and outside CO2 is negligible. The steady-state CO2 inside is about

  1. 16.7%
  2. 0.17%
  3. 4.2%
  4. 8.3%
Answer and working

C. 4.2%

CO2 output = O2 uptake x RQ = 0.5 x 10 x 24 = 120 mL/day. 120 = 24 000 x 0.12 x p, so p = 120/2 880 = 0.0417 atm = 4.2%. Using the O2 permeance (6 000) instead gives 16.7%. 0.17% omits the x 24 h per day; 8.3% uses only half the film area.

Further reading: Mahajan et al., MAP design literature; Kader

8 · Dehydration of fruits and vegetables · medium

If slice thickness is doubled, other conditions unchanged, the falling-rate drying time to a given moisture ratio (diffusion-controlled) becomes about

  1. twice as long
  2. four times as long
  3. half as long
  4. unchanged
Answer and working

B. four times as long

In Fick's solution time appears as D t / L^2, so for the same moisture ratio t is proportional to L^2; doubling thickness quadruples the time.

Further reading: Sahay and Singh, Unit Operations of Agricultural Processing

9 · Dehydration of fruits and vegetables · medium

Most spoilage bacteria cannot grow in a dried product whose water activity is below about

  1. 0.99
  2. 0.60
  3. 0.30
  4. 0.90
Answer and working

D. 0.90

Most bacteria need water activity above about 0.90; many yeasts and moulds grow down to about 0.80 to 0.88, and a few xerophilic moulds and osmophilic yeasts to about 0.60. 0.99 is nearly pure water, where almost everything grows, and 0.30 is far below the limit for any microbe.

Further reading: Fellows, Food Processing Technology

10 · Juice extraction · hard

A processor blends a 12 degBrix juice with a 65 degBrix concentrate to make 1 000 kg of a 20 degBrix base. The concentrate needed is about

  1. 151 kg
  2. 849 kg
  3. 178 kg
  4. 123 kg
Answer and working

A. 151 kg

Pearson square: juice parts = 65 - 20 = 45, concentrate parts = 20 - 12 = 8; concentrate = 1 000 x 8/53 = 151 kg. Check: 849.1 x 0.12 + 150.9 x 0.65 = 200 kg solids = 20%. 849 kg is the juice, not the concentrate. 178 kg divides the concentrate parts by the juice parts (1 000 x 8/45) instead of the total; 123 kg divides by 65.

Further reading: Fellows, Food Processing Technology

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Post-Harvest Engineering of Horticultural CropsThe full study manual, free GATEFormat, sections and how it has changed

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Post-Harvest Engineering of Horticultural Crops for other exams

ASRB NET · IndiaICAR AIEEA-PG · IndiaICAR AICE-JRF/SRF · India

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