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GATE Farm Machinery & Equipment I — Tillage, Sowing, Planting, Fertiliser: practice questions

GATE — Agricultural Engineering (AG) · India · IITs and IISc on rotation (2026: IIT Guwahati)

Original practice questions written to the published syllabus · not past papers
10worked here, free
44written to this exam in this subject
14syllabus units

What this subject covers

Machines that prepare the seedbed and put seed and fertiliser in the ground, and how to calibrate and cost them.

In the exams: GATE AG Section 2 Farm Machinery (~11 marks a year 2019–26; seed-drill calibration in 7 of 8 papers); ICAR AIEEA-PG Unit V; ICAR AICE subject 39 Unit 1; PRC ABE; state PSCs

What GATE asks from it

GATE — Agricultural Engineering (AG)

Numerical answer and MCQ items on seed-drill, planter and fertiliser-drill calibration (one of the most often repeated topics), rotary-tiller bite length, mouldboard plough draft and power, offset disc harrow force balance, field capacity, and machinery cost by straight-line, declining-balance and sum-of-years-digits depreciation with break-even custom hire.

Where the 44 questions fall

How our questions for GATE spread across the units of Farm Machinery & Equipment I — Tillage, Sowing, Planting, Fertiliser. Difficulty: 8 easy, 29 medium, 7 hard.

Forces on tillage tools, draft and hitching7
Cost analysis of implements6
Calibration of seed drills5
Seed-metering mechanisms: fluted roller, cup, plate and pneumatic4
Field capacity and field efficiency4
Harrows, cultivators and rotavators3
Seed drills and planters3
Fertiliser distributors3
Mouldboard plough2
Disc plough2
Paddy and vegetable transplanters2
Chisel plough and subsoiler1
Furrow geometry1
Furrow openers1

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Disc plough · medium

The disc angle of a disc plough is the angle between

  1. the plane of the disc and the vertical, measured in the vertical transverse plane
  2. the plane of the disc edge and the direction of travel, in the horizontal plane
  3. the disc axle and the tractor rear axle in side view
  4. the disc face and the furrow wall
Answer and working

B. the plane of the disc edge and the direction of travel, in the horizontal plane

Disc angle is measured horizontally from the direction of travel; tilt angle is measured between the disc plane and the vertical. Confusing the two is the usual error.

2 · Chisel plough and subsoiler · medium

Chisel shanks set too far apart for their working depth will most likely

  1. invert the soil completely
  2. reduce the draft to zero
  3. leave ridges of untilled soil between the shanks
  4. cause the plough to run shallower than set, since the soil lifts the frame
Answer and working

C. leave ridges of untilled soil between the shanks

The loosened zones from adjacent shanks must meet below the surface. If spacing is too large for the depth, untilled ridges remain between shanks.

3 · Forces on tillage tools, draft and hitching · medium

A 3-bottom mouldboard plough cuts 30 cm per bottom at 20 cm depth in soil with a unit draft of 7 N/cm². It is pulled at 5 km/h. What drawbar power is needed?

  1. 63.0 kW
  2. 17.5 kW
  3. 5.83 kW
  4. 175 kW
Answer and working

B. 17.5 kW

Draft = bottoms × width × depth × unit draft = 3 × 30 × 20 × 7 = 12,600 N. Speed = 5/3.6 = 1.389 m/s. Power = 12,600 × 1.389 = 17,500 W = 17.5 kW. Multiplying by 5 without converting km/h gives 63.0 kW; using one bottom gives 5.83 kW. 175 kW is a factor-of-ten slip.

4 · Forces on tillage tools, draft and hitching · medium

A tractor with a 2.0 m wheelbase exerts a horizontal drawbar pull of 12 kN at a drawbar height of 0.5 m. What weight is transferred from the front to the rear axle (simple static approximation)?

  1. 48 kN
  2. 3.0 kN
  3. 6.0 kN·m
  4. 9.0 kN
Answer and working

B. 3.0 kN

Taking moments about the rear wheel contact: ΔW = P·h/L = 12 × 0.5 / 2.0 = 3.0 kN. Inverting the ratio gives 48 kN; multiplying P by h alone gives 6.0 kN·m, a moment, not a force; using (L − h) as the arm gives 9.0 kN.

5 · Seed-metering mechanisms: fluted roller, cup, plate and pneumatic · medium

In a horizontal-plate planter, what is the function of the spring-loaded cut-off?

  1. Push the seed out of the cell into the tube
  2. Drive the plate from the ground wheel
  3. Cover the seed in the furrow
  4. Remove excess seeds so each cell carries one seed
Answer and working

D. Remove excess seeds so each cell carries one seed

The cut-off wipes surplus seeds from the cell; the knock-out or ejector pushes the seed from the cell into the tube.

6 · Seed-metering mechanisms: fluted roller, cup, plate and pneumatic · medium

Why do pneumatic (vacuum) meters handle ungraded seed better than cell plates?

  1. They meter by volume, so a fixed volume of seed is dropped regardless of size
  2. They use larger cells
  3. Seeds are held on holes by suction, so seed size need not match a cell
  4. They need no singulator
Answer and working

C. Seeds are held on holes by suction, so seed size need not match a cell

Suction holds a seed on each hole regardless of small variations in shape, and a singulator removes doubles, so exact grading matters less than for a fixed cell.

7 · Seed-metering mechanisms: fluted roller, cup, plate and pneumatic · medium

A planter's ground wheel is 50 cm in diameter and drives a 12-cell plate at 0.5 plate turns per wheel turn. Ignoring skid, what is seed spacing?

  1. 6.54 cm
  2. 13.09 cm
  3. 8.33 cm
  4. 26.18 cm
Answer and working

D. 26.18 cm

Spacing = πD/(i·N) = π × 0.5/(0.5 × 12) = 0.2618 m = 26.18 cm. Multiplying by i gives 6.54 cm; ignoring the drive ratio gives 13.09 cm; leaving out π (using D as the travel per turn) gives 8.33 cm.

8 · Furrow openers · medium

Which opener is best suited to sowing through heavy surface residue?

  1. Double-disc opener
  2. Shoe opener
  3. Hoe opener without coulter
  4. Runner opener
Answer and working

A. Double-disc opener

Discs cut through residue instead of dragging it; tined, hoe and shoe openers bunch residue and block.

9 · Fertiliser distributors · medium

Why must adjacent passes of a spinning-disc broadcaster overlap?

  1. To reduce the application rate
  2. Because the disc speed varies with engine load, so each pass throws a different width
  3. To stop segregation
  4. The spread pattern tapers toward the edges, so overlap evens out the total
Answer and working

D. The spread pattern tapers toward the edges, so overlap evens out the total

A single-pass pattern is heaviest in the centre and thins at the edges; spacing passes at the correct bout width overlaps the tails to give even coverage.

10 · Cost analysis of implements · medium

Owning a zero-till drill costs 60 000 per year fixed plus 900 per hectare variable. Custom hire costs 2400 per hectare. Above what annual area is owning cheaper?

  1. 25 ha
  2. 66.7 ha
  3. 18.2 ha
  4. 40 ha
Answer and working

D. 40 ha

Break-even area = FC/(custom rate − VC) = 60 000/(2400 − 900) = 40 ha. Ignoring variable cost gives 25 ha; adding VC to the hire rate gives 18.2 ha. 66.7 ha divides by the variable cost alone (60 000/900).

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Read the subject

Farm Machinery & Equipment I — Tillage, Sowing, Planting, FertiliserThe full study manual, free GATEFormat, sections and how it has changed

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Farm Machinery & Equipment I — Tillage, Sowing, Planting, Fertiliser for other exams

ICAR AIEEA-PG · IndiaRajasthan PSC · IndiaAgricultural and Biosystems Engineers Licensure Examination · PhilippinesASRB NET · IndiaNepal Engineering Council Registration Exam · Nepal

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