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GATE Surveying & Levelling: practice questions

GATE — Agricultural Engineering (AG) · India · IITs and IISc on rotation (2026: IIT Guwahati)

Original practice questions written to the published syllabus · not past papers
10worked here, free
89written to this exam in this subject
12syllabus units

What this subject covers

Measuring land, levels and volumes, from chain survey to total station and GNSS, and designing land grading.

In the exams: GATE AG Section 4 (surveying asked in 7 of 8 papers 2019–26); ICAR AIEEA-PG Unit VII; TNPSC Unit I; RPSC AAE Unit 1; NCEES PE surveying

What GATE asks from it

GATE — Agricultural Engineering (AG), Section 4 Soil and Water Conservation Engineering

Short numericals, often NAT: tape corrections (temperature, pull, sag, slope, wrong length and area), RLs by HI and rise-and-fall with the arithmetic check, reciprocal levelling, curvature and refraction, WCB to QB and included angles, traverse closing error and Bowditch corrections, stadia distance, trapezoidal and Simpson areas, prismoidal and trapezoidal volumes. Since 2021 the syllabus also names total station and GPS.

Where the 89 questions fall

How our questions for GATE spread across the units of Surveying & Levelling. Difficulty: 33 easy, 38 medium, 18 hard.

Theodolite traversing and closing error11
Chain and tape surveying, including tape corrections10
Levelling: rise-and-fall and height-of-instrument methods8
Reciprocal levelling8
Compass traversing and bearings7
Plane table surveying7
Contouring7
Earthwork volume computation7
Total station6
GPS/GNSS surveying6
Computation of area: trapezoidal and Simpson's rules6
Land grading and levelling design6

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Chain and tape surveying, including tape corrections · easy

In chain surveying, a well-conditioned triangle is one in which

  1. all three sides are equal
  2. one angle is exactly 90° so the offsets are square
  3. angles are 30°–120°
  4. every angle is less than 30°, giving a long thin triangle
Answer and working

C. angles are 30°–120°

The apex of a triangle is fixed by intersecting arcs; if an angle is very acute or very obtuse, the arcs meet at a flat angle and a small taping error moves the plotted point a long way. The usual rule is to keep angles between about 30° and 120°. An equilateral triangle is ideal but not required, and a right angle has no special merit.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

2 · Compass traversing and bearings · easy

In a prismatic compass, the zero of the graduated ring is placed at the south end because

  1. sighting is through a prism opposite the object, so a north sight must read 0° at that end
  2. the compass reads quadrantal bearings
  3. the magnetic needle points south in the northern hemisphere, so zero must be set at the south
  4. the graduated ring rotates with the line of sight, so its zero must trail the sight vane by 180°
Answer and working

A. sighting is through a prism opposite the object, so a north sight must read 0° at that end

The ring is fixed to the needle and read through the prism at the eye end, diametrically opposite the object vane; to read 0° on a northward sight the zero must sit at the south end, and the figures are written inverted to read correctly through the prism. It reads whole-circle, not quadrantal, bearings, and its ring does not rotate with the sight (that is the surveyor's compass).

Further reading: Punmia, Jain and Jain, Surveying Vol. I

3 · Theodolite traversing and closing error · easy

A vernier theodolite has main-scale divisions of 20 minutes and 60 vernier divisions. What is its least count?

  1. 1 minute
  2. 20 minutes
  3. 20 seconds
  4. 3 minutes
Answer and working

C. 20 seconds

Least count = value of one main-scale division / number of vernier divisions = 20′/60 = 1/3′ = 20″.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

4 · Theodolite traversing and closing error · medium

Taking the mean of face-left and face-right observations of a horizontal angle eliminates all of the following EXCEPT

  1. line of collimation not perpendicular to the horizontal axis
  2. horizontal axis not perpendicular to the vertical axis
  3. index error of the vertical circle
  4. error due to the vertical axis not being truly vertical
Answer and working

D. error due to the vertical axis not being truly vertical

Face changes reverse the sign of collimation, trunnion-axis and index errors, so they cancel in the mean. A tilted vertical axis tilts the horizontal axis the same way on both faces, so it does not cancel; careful levelling is the only remedy.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

5 · Theodolite traversing and closing error · medium

The transit rule for balancing a traverse is preferred over Bowditch's rule when

  1. the traverse is open
  2. a compass is used for the bearings
  3. distances are measured more precisely than angles
  4. angles are measured more precisely than distances
Answer and working

D. angles are measured more precisely than distances

The transit rule distributes corrections in proportion to the size of each latitude and departure, which assumes angles are good and lengths poorer (theodolite with tape). Bowditch assumes equal effect of angular and linear errors and is the usual rule for compass traverses. Neither can be applied to an open traverse.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

6 · GPS/GNSS surveying · hard

An RTK GNSS survey gives an ellipsoidal height of 18.6 m at a point where the geoid undulation N from the geoid model is −52.3 m. What is the orthometric height (height above the geoid)?

  1. 18.6 m
  2. -70.9 m
  3. 70.9 m
  4. -33.7 m
Answer and working

C. 70.9 m

H = h − N = 18.6 − (−52.3) = 70.9 m. Where the geoid lies below the ellipsoid (negative N), orthometric heights exceed ellipsoidal heights. Adding N gives -33.7 m; using the ellipsoidal height as if it were above mean sea level is the classic mistake.

Further reading: Ghilani and Wolf, Elementary Surveying

7 · Computation of area: trapezoidal and Simpson's rules · easy

Simpson's one-third rule can be applied directly only when the number of

  1. ordinates is odd (an even number of intervals)
  2. intervals is odd
  3. ordinates exceeds ten
  4. ordinates is even (an odd number of intervals)
Answer and working

A. ordinates is odd (an even number of intervals)

The rule fits a parabola over each pair of strips, so the number of strips must be even and the number of ordinates odd. With an even number of ordinates, the last strip is computed separately by the trapezoidal rule.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

8 · Computation of area: trapezoidal and Simpson's rules · medium

An area measured on a 1:2000 plan is 42.5 cm². What is the ground area?

  1. 17.0 ha
  2. 17000 ha
  3. 1.70 ha
  4. 0.085 ha
Answer and working

C. 1.70 ha

1 cm² on the plan = (20 m)² = 400 m². So 42.5 × 400 = 17,000 m² = 1.70 ha. Scaling by the RF once instead of squared is the classic slip. 17.0 ha is a factor-of-ten slip; 0.085 ha scales by 20 m once (42.5 × 20 = 850 m²) instead of squared.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

9 · Earthwork volume computation · medium

A 40 m long prismoid has end areas 12.0 and 24.0 m² and a mid-section area (computed from the mid-depth) of 17.5 m². What is its volume?

  1. 1413.3 m³
  2. 706.7 m³
  3. 720.0 m³
  4. 700.0 m³
Answer and working

B. 706.7 m³

V = (L/6)(A1 + 4Am + A2) = (40/6)(12 + 70 + 24) = 706.7 m³. Average end area gives 720.0 m³ (an overestimate for a prismoid); using L/3 doubles the answer because L here is the full length. 1413.3 m³ uses L/3; 700.0 m³ multiplies the mid-section area by the length.

Further reading: Punmia, Jain and Jain, Surveying Vol. I

10 · Land grading and levelling design · medium

When is the plane method of land-grading design NOT the best choice?

  1. On fields so irregular that a single plane would require excessive earth movement
  2. When the field is square
  3. On nearly uniform fields
  4. When least-squares fitting can be computed quickly by software instead of by hand calculation
Answer and working

A. On fields so irregular that a single plane would require excessive earth movement

A single best-fit plane is efficient for fairly uniform fields; where the surface is strongly irregular, profile, plan-inspection or contour-adjustment methods allow varying grades and cut far less earth.

Further reading: Schwab et al., Soil and Water Conservation Engineering

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Read the subject

Surveying & LevellingThe full study manual, free GATEFormat, sections and how it has changed

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Surveying & Levelling for other exams

ICAR AIEEA-PG · IndiaRajasthan PSC · IndiaTamil Nadu PSC · IndiaASRB NET · IndiaNCEES PE Agricultural and Biological Engineering · USA

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