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ICAR AIEEA-PG Refrigeration, Air-Conditioning & Cold-Chain Engineering: practice questions

ICAR AIEEA-PG — Agricultural Engineering & Technology (Major Subject Group 10) · India · National Testing Agency for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
68written to this exam in this subject
14syllabus units

What this subject covers

Refrigeration cycles, equipment and cold-store design, from COP to the heat load of a room full of potatoes.

In the exams: GATE AG Section 7 (refrigeration COP/TR in 4 of 8 papers 2019–26; composite cold-store walls recur); ICAR AIEEA-PG Unit VI; ICAR AICE subject 38 Unit 6

What ICAR AIEEA-PG asks from it

ICAR AIEEA-PG — Agricultural Engineering & Technology

Unit VI asks single-answer MCQs on refrigeration and air-conditioning, cold stores and heating and cooling load calculation: the four processes of the cycle, TR definition, refrigerant designation and ODP/GWP, absorption pairs, expansion devices, psychrometric processes, cold-store load components, insulation and vapour-barrier placement. Negative marking rewards precise definitions.

Where the 68 questions fall

How our questions for ICAR AIEEA-PG spread across the units of Refrigeration, Air-Conditioning & Cold-Chain Engineering. Difficulty: 31 easy, 35 medium, 2 hard.

Refrigerants: ODP and GWP7
Psychrometric air-conditioning processes6
Cold-store heat load: transmission, product and respiration6
Refrigerated transport and cold-chain logistics6
Vapour-compression refrigeration cycle5
Pressure-enthalpy charts5
Cold-store heat load: infiltration, occupancy and equipment5
Vapour-absorption refrigeration4
COP and tonnes of refrigeration4
Compressors4
Condensers and evaporators4
Expansion devices4
Insulation and vapour barriers4
Ice-bank systems4

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Vapour-compression refrigeration cycle · medium

Subcooling the liquid refrigerant leaving the condenser, with evaporating and condensing pressures unchanged, will

  1. Reduce the refrigerating effect because h4 rises when the liquid is cooled further
  2. Increase the refrigerating effect per kg without increasing compressor work per kg
  3. Increase compressor work per kg and lower COP, because the colder liquid needs more pumping
  4. Have no effect because throttling is isenthalpic
Answer and working

B. Increase the refrigerating effect per kg without increasing compressor work per kg

Subcooling lowers h3, and since h4 = h3 the refrigerating effect h1 − h4 grows. Suction state 1 is unchanged, so the work h2 − h1 is unchanged and COP rises. Throttling being isenthalpic is exactly why the lower h3 carries through to h4.

Further reading: Arora, Refrigeration and Air Conditioning

2 · Vapour-absorption refrigeration · medium

In the three-fluid (diffusion) absorption refrigerator, hydrogen is used to

  1. Act as the refrigerant, evaporating in the evaporator to absorb heat from the cabinet
  2. Equalise total pressure throughout the circuit so that no solution pump is needed
  3. Absorb ammonia in the absorber
  4. Cool the generator
Answer and working

B. Equalise total pressure throughout the circuit so that no solution pump is needed

Hydrogen fills the evaporator and absorber so that ammonia evaporates at a low partial pressure while total pressure is uniform; circulation is by a heat-driven bubble pump and gravity. Water, not hydrogen, is the absorbent, and ammonia is the refrigerant.

Further reading: Arora, Refrigeration and Air Conditioning

3 · Pressure-enthalpy charts · medium

At the evaporator pressure, saturated liquid enthalpy is 180 kJ/kg and saturated vapour enthalpy 390 kJ/kg. Liquid at 250 kJ/kg is throttled into the evaporator. The dryness fraction at evaporator inlet is

  1. 0.641
  2. 0.333
  3. 0.359
  4. 0.667
Answer and working

B. 0.333

x = (h4 − h_f)/(h_g − h_f) = (250 − 180)/(390 − 180) = 70/210 = 0.333. 0.667 is the liquid fraction; h4/h_g ignores the liquid enthalpy datum. 0.641 is h4/h_g (250/390), and 0.359 is (h_g − h4)/h_g (140/390).

Further reading: Arora, Refrigeration and Air Conditioning

4 · Compressors · medium

As the evaporating temperature of a reciprocating compressor falls with condensing temperature fixed, its volumetric efficiency

  1. Rises, because suction gas is denser
  2. Falls, as a higher pressure ratio makes clearance gas re-expand over more stroke
  3. Is unchanged, because swept volume is fixed
  4. Rises, because discharge temperature falls and the valves open earlier in each stroke
Answer and working

B. Falls, as a higher pressure ratio makes clearance gas re-expand over more stroke

η_v = 1 + C − C(p_d/p_s)^(1/n) falls as p_d/p_s rises. Suction gas actually becomes less dense at lower evaporating temperature, which also reduces mass flow.

Further reading: Arora, Refrigeration and Air Conditioning

5 · Expansion devices · easy

A thermostatic expansion valve is designed to maintain a nearly constant

  1. Evaporator pressure
  2. Superheat of vapour at the evaporator outlet
  3. Liquid level in the evaporator
  4. Condenser pressure
Answer and working

B. Superheat of vapour at the evaporator outlet

The bulb on the suction line senses outlet temperature, and the diaphragm balances bulb pressure against evaporator pressure plus spring: the controlled variable is superheat. Constant evaporator pressure is the automatic (constant-pressure) valve; liquid level is a float valve.

Further reading: Arora, Refrigeration and Air Conditioning

6 · Expansion devices · medium

A practical advantage of the capillary tube is that it allows a low-starting-torque compressor motor because

  1. High- and low-side pressures equalise through it while the compressor is off
  2. It adjusts its bore to the load
  3. It stores a large reserve of liquid refrigerant that it releases to the compressor on start-up
  4. It prevents flash gas at the evaporator inlet
Answer and working

A. High- and low-side pressures equalise through it while the compressor is off

With no valve to close, pressures balance during the off cycle, so the compressor starts against no pressure difference. It has no reserve, no adjustment, and flash gas still forms.

Further reading: Arora, Refrigeration and Air Conditioning

7 · Psychrometric air-conditioning processes · easy

During sensible heating of moist air, which property remains constant?

  1. Relative humidity
  2. Wet-bulb temperature
  3. Enthalpy
  4. Humidity ratio
Answer and working

D. Humidity ratio

No moisture is added or removed, so ω stays constant and the process is horizontal on the chart. Relative humidity falls because the saturation pressure rises; wet-bulb and enthalpy rise.

Further reading: ASABE D271

8 · Cold-store heat load: transmission, product and respiration · easy

By Siebel's relation, the specific heat above freezing of a fruit with 80% water is about

  1. 2.68 kJ/kg K
  2. 1.85 kJ/kg K
  3. 3.35 kJ/kg K
  4. 3.52 kJ/kg K
Answer and working

D. 3.52 kJ/kg K

c_p = 3.35 × 0.8 + 0.84 = 3.52 kJ/kg K. 1.85 is the below-freezing relation; omitting the 0.84 solids term gives 2.68.

Further reading: Singh and Heldman, Introduction to Food Engineering

9 · Insulation and vapour barriers · easy

In a cold-store wall, the vapour barrier should be placed

  1. On the cold (inner) side of the insulation
  2. In the middle of the insulation
  3. On both faces, with the inner one sealed more tightly
  4. On the warm (outer) side of the insulation
Answer and working

D. On the warm (outer) side of the insulation

Vapour moves from warm to cold. A barrier on the warm side stops it before it reaches layers cold enough to condense or freeze it. A tight barrier on the cold side traps any moisture that enters.

Further reading: ASHRAE Handbook — Refrigeration

10 · Refrigerated transport and cold-chain logistics · easy

In the cold chain, the step that removes field heat from produce immediately after harvest is called

  1. Pre-cooling
  2. Blanching
  3. Curing
  4. Controlled-atmosphere storage
Answer and working

A. Pre-cooling

Pre-cooling (forced-air, hydro, vacuum, room or ice cooling) brings produce quickly toward storage temperature. Curing heals wounds at warm temperatures; blanching is a heat treatment before freezing vegetables.

Further reading: ASHRAE Handbook — Refrigeration

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Read the subject

Refrigeration, Air-Conditioning & Cold-Chain EngineeringThe full study manual, free ICAR AIEEA-PGFormat, sections and how it has changed

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Refrigeration, Air-Conditioning & Cold-Chain Engineering for other exams

ASRB NET · IndiaGATE · IndiaICAR AICE-JRF/SRF · India

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