Tamil Nadu PSC — Agricultural Engineering (Code 164, degree standard) · India · Tamil Nadu Public Service Commission
Original practice questions written to the published syllabus · not past papersManaging water at the scale of reservoirs, canals and river basins, including floods and farmer participation.
In the exams: ICAR AICE subject 40 Units 7–8; ICAR AIEEA-PG Unit VII; electives in the ICAR 6th Deans' Committee B.Tech
How our questions for Tamil Nadu PSC spread across the units of Water Resources Management, Floods & Canal Systems. Difficulty: 25 easy, 12 medium, 6 hard.
| Diversion works | 12 | |
| Canal operation | 8 | |
| Reservoirs | 6 | |
| Minor irrigation | 5 | |
| Water resources of a country | 3 | |
| Flood estimation | 3 | |
| Water users' associations and participatory irrigation management | 3 | |
| Flood control measures | 2 | |
| Water quality management | 1 |
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
Contours 5 m apart enclose 2.0 km² and 3.2 km² of a reservoir basin. Using the cone (prismoidal) formula, what is the storage between them?
A. 12.88 Mm³
Cone formula: ΔV = (h/3)(A1 + A2 + √(A1A2)) = (5/3)(2.0 + 3.2 + 2.53) × 10⁶ = 12.88 Mm³. 13.00 is the trapezoidal formula, which slightly overestimates; 26.00 forgets to divide by 2 in the trapezoidal formula; 6.44 halves the right answer.
Further reading: Garg, Irrigation Engineering and Hydraulic Structures
What is valley storage, and why does it matter in assessing a flood-control dam?
A. The volume the natural channel and flood plain held before the dam; the net gain is reservoir volume minus it
Valley storage existed before the dam, so the flood benefit depends on the net gain. Seepage into banks is bank storage; space above MWL is freeboard; storage below the outlet is dead storage.
Further reading: Garg, Irrigation Engineering and Hydraulic Structures
Why do designers prefer proportional or slightly sub-proportional outlets near the tail of a distributary?
C. So that when the distributary runs low, head outlets do not take more than their share and starve the tail
Fair sharing of fluctuations protects the tail. A hyper-proportional outlet upstream takes extra when levels rise and the effect cascades. No outlet delivers when the channel is closed; downstream control would make the outlet non-modular.
Further reading: Garg, Irrigation Engineering and Hydraulic Structures
Under warabandi, how is each farmer's turn on a watercourse fixed?
C. A fixed time on a fixed day of a weekly cycle, in proportion to the farmer's landholding
Warabandi gives the whole outlet flow for a time proportional to area, at a fixed day and hour in a 7-day cycle. Application-based allotment is closer to Maharashtra's shejpali; equal hours ignores holding size.
Further reading: Garg, Irrigation Engineering and Hydraulic Structures
Using Ryves' formula Q = C·A^(2/3) with C = 6.8 (Q in m³/s, A in km²), what is the peak flood from a 500 km² catchment?
D. About 428 m³/s
Q = 6.8 × 500^(2/3) = 6.8 × 63.0 = 428 m³/s. 719 uses Dickens' exponent 3/4; 3,400 uses A to the power 1; 152 uses A^0.5.
Further reading: Subramanya, Engineering Hydrology
Which measure reduces flood damage to a house without changing the flood itself?
A. Raising the plinth above the expected flood level
Flood proofing, such as raising plinths, protects property against a given flood. Detention, channel widening and levees all change the flood flow or level.
Further reading: WMO/GWP Integrated Flood Management
Under India's classification by culturable command area, a scheme with a CCA of 1,500 ha is
C. a minor irrigation project
India: minor below 2,000 ha CCA, medium 2,000–10,000 ha, major above 10,000 ha. Command area development is a programme, not a size class.
Further reading: Planning Commission / Ministry of Jal Shakti (India)
A tank's 15 km² catchment receives 900 mm of rain, with a runoff coefficient of 0.25. After 30% losses to evaporation and seepage, the crops need a delta of 0.5 m. About how much area can be irrigated?
D. About 470 ha
Yield = 15 × 10⁶ × 0.9 × 0.25 = 3.375 Mm³; usable = 3.375 × 0.7 = 2.36 Mm³; area = 2.36 × 10⁶ ÷ 0.5 = 4.73 × 10⁶ m² ≈ 473 ha. 675 ignores losses; 1,890 omits the runoff coefficient; 330 applies the loss twice.
Further reading: Garg, Irrigation Engineering and Hydraulic Structures
What is the function of the sluice in an irrigation tank?
B. To release controlled amounts of stored water to the command
The sluice is the controlled outlet to the command. Flood passing is the surplus weir; supply is the supply channel.
Further reading: Garg, Irrigation Engineering and Hydraulic Structures
Which Indian state passed the Farmers' Management of Irrigation Systems Act in 1997, an early state law creating water users' associations?
B. Andhra Pradesh
Andhra Pradesh's 1997 Act created WUAs across its irrigation commands and was followed by other states' laws. The other states passed their own laws at different times.
Further reading: Government of Andhra Pradesh, 1997
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