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ICAR-IASRI MSc and PhD Spatial Statistics, Geostatistics & Remote Sensing for Agriculture: practice questions

ICAR-IASRI MSc and PhD (Agricultural Statistics, Computer Application, Bioinformatics) · India · ICAR-Indian Agricultural Statistics Research Institute with the IARI Graduate School

Original practice questions written to the published syllabus · not past papers
10worked here, free
92written to this exam in this subject
10syllabus units

What this subject covers

Statistics for data with a location: spatial autocorrelation, variograms and kriging, spatial regression, point patterns, area-frame sampling, accuracy assessment of crop maps and satellite-based area and yield estimation. Remote-sensing physics and GIS operations are taught in the Agricultural Engineering track; this is the statistics.

In the exams: AICE-JRF Agricultural Physics 'spatial statistics: variogram and interpolation' (present); national crop-estimation programmes (applied); light in national exams

What ICAR-IASRI MSc and PhD asks from it

ICAR-IASRI MSc and PhD programmes

Spatial autocorrelation, variogram estimation and modelling, kriging and co-kriging, spatial regression, area-frame designs, accuracy assessment and satellite-assisted crop area and yield estimation.

Where the 92 questions fall

How our questions for ICAR-IASRI MSc and PhD spread across the units of Spatial Statistics, Geostatistics & Remote Sensing for Agriculture. Difficulty: 24 easy, 48 medium, 20 hard.

Variograms and their models11
Kriging: ordinary, universal and co-kriging10
Image classification as a statistical problem10
Spatial autocorrelation: Moran's I and Geary's C9
Spatial regression: SAR and CAR models; geographically weighted regression9
Point-pattern analysis9
Accuracy assessment: error matrices and kappa; area estimation from maps9
Satellite-based crop area and yield estimation9
Spatial data types: geostatistical, areal and point-pattern8
Area-frame sampling with satellite stratification8

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Spatial data types: geostatistical, areal and point-pattern · easy

Soil pH is measured at 150 fixed grid points in a farm in order to map it everywhere. Which type of spatial data is this?

  1. Geostatistical data
  2. Point-pattern data, because each sample has coordinates
  3. Time-series data, because samples were taken in sequence
  4. Areal (lattice) data, because the farm is an area
Answer and working

A. Geostatistical data

pH exists everywhere and is sampled at chosen fixed locations, the geostatistical case. Point patterns have random event locations; areal data are values for fixed units covering the region.

Further reading: Cressie, Statistics for Spatial Data

2 · Spatial autocorrelation: Moran's I and Geary's C · hard

For the same layout of four plots in a row with yields 2, 4, 6 and 8 and binary neighbour weights between adjacent plots, what is Geary's C?

  1. 0.60
  2. 0.30
  3. 1.00
  4. 0.40
Answer and working

B. 0.30

Squared differences between adjacent plots are 4 each; over 6 ordered pairs the sum is 24. C = (n - 1) x 24 / (2 x 6 x 20) = 0.30, well below 1, so positive autocorrelation. 1.00 is the expectation under no autocorrelation; forgetting the factor 2 gives 0.60; using n instead of n - 1 gives 0.40.

Further reading: Cressie, Statistics for Spatial Data; Anselin, Spatial Econometrics

3 · Spatial autocorrelation: Moran's I and Geary's C · medium

Why are spatial weights matrices often row-standardised?

  1. So Moran's I always equals zero
  2. So the matrix becomes symmetric for every layout
  3. So units without neighbours are dropped
  4. So each unit's neighbours are averaged
Answer and working

D. So each unit's neighbours are averaged

Dividing each row by its sum makes weights sum to 1 per unit, so W x is the average of neighbours and coefficients are comparable between units with different numbers of neighbours. Row-standardised W is generally not symmetric.

Further reading: Cressie, Statistics for Spatial Data; Anselin, Spatial Econometrics

4 · Variograms and their models · medium

For a second-order stationary process the sill is 10 and the semivariance at 30 m is 6. What is the correlation between values 30 m apart?

  1. 4.0
  2. 6.0
  3. 0.4
  4. 0.6
Answer and working

C. 0.4

C(h) = C(0) - gamma(h) = 10 - 6 = 4, and the correlation is C(h)/C(0) = 4/10 = 0.4. 0.6 is gamma/sill; 4.0 is the covariance, not a correlation.

Further reading: Webster and Oliver, Geostatistics for Environmental Scientists

5 · Kriging: ordinary, universal and co-kriging · medium

When does co-kriging improve markedly on ordinary kriging of the target variable?

  1. When the secondary variable is uncorrelated with the target
  2. When both variables are measured at exactly the same points
  3. When a correlated secondary variable is much denser
  4. When the target variable has no spatial dependence
Answer and working

C. When a correlated secondary variable is much denser

Co-kriging gains from extra information about the target; it helps most when the secondary variable is correlated and denser. With identical sampling the gain is usually small.

Further reading: Webster and Oliver, Geostatistics for Environmental Scientists; Isaaks and Srivastava

6 · Image classification as a statistical problem · medium

The maximum likelihood classifier for satellite images assumes that each land-cover class:

  1. Occupies exactly the same number of pixels
  2. Is independent of all other bands
  3. Has equal mean reflectance in every band
  4. Is multivariate normal in the bands
Answer and working

D. Is multivariate normal in the bands

Each class is modelled as multivariate normal with its own mean vector and covariance matrix; this makes the rule the quadratic discriminant of multivariate statistics.

Further reading: Congalton and Green; Johnson and Wichern (discriminant analysis)

7 · Image classification as a statistical problem · hard

How do prior probabilities change maximum likelihood classification of pixels?

  1. Priors make all classes equally likely
  2. Pixels go to the class of highest posterior
  3. Priors are used only for unsupervised clustering
  4. Priors replace the class mean vectors entirely
Answer and working

B. Pixels go to the class of highest posterior

With priors, Bayes' rule multiplies each class likelihood by its prior; in doubtful pixels the more common class is favoured.

Further reading: Congalton and Green; Johnson and Wichern (discriminant analysis)

8 · Accuracy assessment: error matrices and kappa; area estimation from maps · medium

With rows = map and columns = reference, the user's accuracy for wheat is 80/100 = 0.80. What does it mean to a map user?

  1. 80 per cent of all pixels are correctly classified
  2. 80 per cent of mapped wheat is truly wheat
  3. 80 per cent of the real wheat area is mapped as wheat
  4. The kappa coefficient for wheat is 0.80
Answer and working

B. 80 per cent of mapped wheat is truly wheat

User's accuracy is the reliability of the map label (1 - commission error). The share of real wheat captured is producer's accuracy; overall accuracy covers all classes.

Further reading: Congalton and Green; Olofsson et al. (2014); Pontius and Millones (2011)

9 · Accuracy assessment: error matrices and kappa; area estimation from maps · medium

A rare crop occupies 2 per cent of a mapped region. Which design for reference samples ensures enough samples to estimate its accuracy?

  1. Simple random sampling of the whole region
  2. Stratified random sampling by map class
  3. Sampling only along roads for easy access
  4. Using the classifier's training pixels again
Answer and working

B. Stratified random sampling by map class

Stratifying by map class guarantees a minimum sample in each class (often about 50 or more); simple random sampling would yield very few rare-crop points. Roadside and training samples are not valid probability samples.

Further reading: Congalton and Green; Olofsson et al. (2014); Pontius and Millones (2011)

10 · Satellite-based crop area and yield estimation · medium

Insurance payouts in a block depend on a satellite-assisted yield estimate. What is the most important statistical safeguard?

  1. Releasing only the point estimate to avoid confusion
  2. Adjusting estimates to match farmers' claims
  3. Using the newest satellite without validation
  4. A documented probability design with stated uncertainty
Answer and working

D. A documented probability design with stated uncertainty

Where money depends on estimates, the design, models and uncertainty must be documented and auditable; unvalidated sensors and post-hoc adjustment undermine credibility.

Further reading: Gallego (2004); Cochran, Sampling Techniques

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Spatial Statistics, Geostatistics & Remote Sensing for AgricultureThe full study manual, free ICAR-IASRI MSc and PhDFormat, sections and how it has changed

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