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State dairy development department posts Dairy Effluent Treatment & Environmental Management: practice questions

State dairy development department posts · India · State public service commissions (e.g. Kerala PSC)

Original practice questions written to the published syllabus · not past papers
10worked here, free
43written to this exam in this subject
11syllabus units

What this subject covers

Characterising and treating dairy wastewater, sludge and emissions, and measuring the environmental footprint of milk.

In the exams: ICAR AICE subject 34 Unit 4 (BOD and COD in dairy waste) and subject 35b Unit 1 (EMS); ICAR AIEEA-PG group 16 (disposal of dairy waste)

Where the 43 questions fall

How our questions for State dairy development department posts spread across the units of Dairy Effluent Treatment & Environmental Management. Difficulty: 20 easy, 22 medium, 1 hard.

Sources and characteristics of dairy effluent7
Aerobic treatment: activated sludge and its variants6
Preliminary and primary treatment: screening, equalisation, dissolved air flotation5
Anaerobic treatment and biogas4
Discharge standards and permits4
Environmental management systems: ISO 140014
BOD, COD, fats-oil-grease and nutrient measurement3
Sludge handling and disposal3
Water recovery from cow water and condensate3
Life-cycle assessment and carbon footprint of dairy products2
Nutrient removal and tertiary treatment2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · BOD, COD, fats-oil-grease and nutrient measurement · easy

An effluent flow of 500 m³/day has a COD of 3,000 mg/L. What is the daily COD load?

  1. 6 kg/day
  2. 150 kg/day
  3. 1,500 kg/day
  4. 1,500,000 kg/day
Answer and working

C. 1,500 kg/day

Load = 500 m³ × 3,000 g/m³ = 1,500,000 g = 1,500 kg/day (mg/L equals g/m³).

Further reading: APHA, Standard Methods for the Examination of Water and Wastewater

2 · Sources and characteristics of dairy effluent · medium

A plant processing 500,000 L of milk a day loses 1% to drain. Taking milk BOD as 100,000 mg/L, what BOD load does this add?

  1. 5,000 kg/day
  2. 50 kg/day
  3. 50,000 kg/day
  4. 500 kg/day
Answer and working

D. 500 kg/day

5,000 L × 100 g/L = 500,000 g = 500 kg BOD/day.

Further reading: Tetra Pak, Dairy Processing Handbook

3 · Anaerobic treatment and biogas · easy

A reactor's influent COD is 4,000 mg/L and its effluent COD is 800 mg/L. What is the COD removal?

  1. 3,200%
  2. 5%
  3. 20%
  4. 80%
Answer and working

D. 80%

(4,000 − 800) ÷ 4,000 = 80%.

Further reading: Metcalf & Eddy, Wastewater Engineering

4 · Sources and characteristics of dairy effluent · hard

What does an effluent audit usually reveal about where the load comes from?

  1. Domestic sewage is the main source
  2. The load is spread evenly over every hour of operation
  3. A few events cause most of it
  4. Only CIP contributes
Answer and working

C. A few events cause most of it

Tank emptying, changeovers, desludging and spills dominate; targeting them gives most of the savings.

Further reading: Tetra Pak, Dairy Processing Handbook

5 · Discharge standards and permits · easy

In most countries, which kind of law is the main basis for controlling dairy effluent discharges?

  1. An energy conservation law
  2. A boiler safety law
  3. A food safety law
  4. A water-pollution control law
Answer and working

D. A water-pollution control law

Water-pollution control (or general environmental protection) legislation requires discharge permits and sets effluent standards. Food safety law governs the product, not the effluent; boiler and energy laws cover other utilities.

Further reading: Manual chapter: Discharge standards and permits

6 · Discharge standards and permits · medium

A dairy's permit limits BOD to 100 mg/L for discharge to surface water. If the plant discharges 800 m³ of treated effluent a day, what is the maximum BOD load it may release?

  1. 8 kg/day
  2. 80 kg/day
  3. 800 kg/day
  4. 80,000 kg/day
Answer and working

B. 80 kg/day

Load (kg/day) = concentration (mg/L) × flow (m³/day) ÷ 1,000 = 100 × 800 ÷ 1,000 = 80 kg/day. 80,000 is the load in grams per day mistaken for kilograms; 8 and 800 are decimal slips.

Further reading: Manual chapter: BOD, COD, fats-oil-grease and nutrient measurement

7 · Discharge standards and permits · medium

Why do trade effluent charges based on COD encourage plants to cut load?

  1. They reward dilution
  2. They apply only to sewage
  3. They are fixed fees
  4. Lower load means lower fees
Answer and working

D. Lower load means lower fees

Charges scale with volume and strength, so reducing COD saves money directly.

Further reading: Metcalf & Eddy, Wastewater Engineering

8 · Aerobic treatment: activated sludge and its variants · medium

Which aerobic option suits a rural dairy with plenty of land and low budget?

  1. An EGSB reactor
  2. A membrane bioreactor
  3. Aerated lagoons
  4. Ozonation
Answer and working

C. Aerated lagoons

Lagoons are cheap but need land and can smell if overloaded.

Further reading: Metcalf & Eddy, Wastewater Engineering

9 · Aerobic treatment: activated sludge and its variants · medium

What dissolved oxygen is typically maintained in an aeration tank?

  1. 20 mg/L
  2. 0 mg/L
  3. Above saturation
  4. Near 2 mg/L
Answer and working

D. Near 2 mg/L

About 2 mg/L supports aerobic activity without wasting blower energy.

Further reading: Metcalf & Eddy, Wastewater Engineering

10 · Water recovery from cow water and condensate · medium

Why can a milk powder plant become a net water exporter?

  1. Milk is 87% water
  2. Powder absorbs water
  3. It uses no CIP
  4. Boilers make water
Answer and working

A. Milk is 87% water

Water evaporated from milk can exceed fresh water drawn by the plant.

Further reading: Tetra Pak, Dairy Processing Handbook

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Read the subject

Dairy Effluent Treatment & Environmental ManagementThe full study manual, free State dairy development department postsFormat, sections and how it has changed

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