Forester / Deputy Ranger / Forest Guard recruitment · India · State forest departments and subordinate services selection boards
Original practice questions written to the published syllabus · not past papersForester / Deputy Ranger / Forest Guard recruitment is a government recruitment exam run by State forest departments and subordinate services selection boards, for candidates in India. Objective written test, physical efficiency test (walking) and medical standards.
Official site: moef.gov.in.
We have not been able to confirm these details against the exam body's own specification, so fees, dates and pass marks are left out on purpose. Check the current format, eligibility, fees and dates on the official site.
Measuring single trees, logs and stands: diameter, height, form, volume, biomass and growth, with the instruments and formulas used in the field.
Our 17 Forester / Deputy Ranger / Forest Guard recruitment questions in this subject: 17 easy, 0 medium, 0 hard, across 10 units.
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
These 10 were written to Forester / Deputy Ranger / Forest Guard recruitment and are not shown on any other exam's page.
A girth tape reads 157 cm at breast height. What is the tree's diameter?
C. 50.0 cm
Diameter = girth ÷ π = 157 ÷ 3.1416 = 50.0 cm. Dividing by 4 gives the quarter girth (39.3 cm), which is used only in the Hoppus volume rule; dividing by 2π gives the radius (25.0 cm).
On a leaning tree, breast height is located:
D. Along the stem from the uphill side, diameter taken across the stem axis
For a leaning tree the measurement follows the stem: breast height is measured along the stem axis and the diameter taken at right angles to it. A horizontal section through a leaning stem is an ellipse and overstates the diameter.
Using a percent clinometer on level ground 20 m from a tree, the reading to the top is +75% and to the base −8%. What is the tree height?
C. 16.6 m
H = D × (top% − base%) / 100 = 20 × (75 − (−8)) / 100 = 20 × 0.83 = 16.6 m. Subtracting 8 from 75 gives 13.4 m, which ignores that the base is below eye level; using the top reading alone gives 15.0 m.
As a rule of thumb, how far from a tree should an observer stand when measuring height with a clinometer?
D. At a distance roughly equal to the tree's height
At about one tree-height away the angle to the top is near 45°, where small angle errors cause small height errors. Standing very close makes the angle steep and errors large; standing very far makes the top hard to see.
A tree measures 42 cm dbh over bark. A bark gauge gives a single bark thickness of 1.5 cm. What is the diameter under bark?
C. 39.0 cm
Diameter under bark = over-bark diameter − 2 × single bark thickness = 42 − 3.0 = 39.0 cm, because a diameter crosses the bark twice. Subtracting once gives 40.5 cm.
A tree is 24 m tall and its live crown begins at 15 m. What is its crown ratio?
D. 37.5%
Crown length = 24 − 15 = 9 m; crown ratio = crown length ÷ total height = 9 ÷ 24 = 37.5%. 15 ÷ 24 = 62.5% is the clear-bole fraction; 9 ÷ 15 = 60% uses the wrong denominator.
A tree has dbh 30 cm, height 20 m and a breast-height form factor of 0.45. What is its volume?
B. 0.636 m³
V = g × h × f = 0.07069 × 20 × 0.45 = 0.636 m³. Omitting f gives the cylinder volume 1.414 m³; using π r² with r = 0.30 gives 2.545 m³.
On a sloping site, if a circular plot's radius is measured along the slope without correction, the plot will:
C. Be smaller than intended in horizontal area, underestimating stems per hectare
Plot area is defined in horizontal projection. A radius measured along the slope covers less horizontal distance, so the plot is smaller than its nominal area and trees per hectare (computed with the nominal expansion factor) are underestimated.
A tree stands exactly on the boundary of a fixed-area plot. It is counted as in the plot if:
C. The centre of its stem at breast height lies inside the boundary
The standard rule is the stem centre at breast height. Crown overhang or roots are not used.
An increment core at breast height shows 42 rings. Trees of this species on this site take about 6 years to reach breast height. What is the best estimate of total age?
A. 48 years
Total age = rings at sampling height + years to reach that height = 42 + 6 = 48 years. Using the ring count alone ignores the years before the tree reached breast height.
This plan follows where our questions actually fall, so the time goes where the marks are likely to be. It is our reading of the syllabus, not the exam body's weighting.
Read the manual chapters for these first and do every worked question you can find on them.
Aim for one sitting per unit, then mixed questions across them.
Learn the definitions, classifications and standard numbers; these units are more often recalled than worked.
Do these early in revision so they are fast on the day.
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