ICAR AICE-JRF/SRF (PhD) — Environmental Sciences (subject 71) and Agricultural Meteorology (subject 60) · India · National Testing Agency for ICAR
Original practice questions written to the published syllabus · not past papersRadiation, heat, moisture and motion in the atmosphere, and how weather and climate are measured and used on farms. ICAR AICE subject 60 Agricultural Meteorology examines it in depth.
In the exams: ICAR AICE-JRF/SRF subject 60 (whole paper); ICAR AIEEA-PG 3.1 Agricultural Meteorology; GATE ES Section 6 (meteorology for dispersion)
ICAR AICE-JRF/SRF (PhD) — Agricultural Meteorology (subject 60)
The whole paper: atmospheric structure, radiation laws and constants, energy balance, humidity measures and psychrometry, lapse rates and stability, clouds and precipitation, general circulation, monsoon dynamics, Köppen and Thornthwaite, instruments and observatories, heat units and photoperiodism, ET methods (Penman–Monteith, Hargreaves, pan) and agromet advisories, with numerical problems.
How our questions for ICAR AICE-JRF/SRF spread across the units of Atmospheric Science & Agrometeorology. Difficulty: 25 easy, 53 medium, 18 hard.
| Evapotranspiration estimation and crop water needs | 9 | |
| Weather instruments and observatories; automatic weather stations | 8 | |
| Crop-weather relations: growing degree days, photoperiod, thermal stress | 8 | |
| Weather forecasting for agriculture and agromet advisories | 8 | |
| Radiation laws: Planck, Stefan-Boltzmann, Wien, Kirchhoff, Beer-Lambert | 7 | |
| Solar radiation, albedo and the surface energy balance | 7 | |
| Latent and sensible heat; temperature inversions | 7 | |
| Pressure systems, winds and general circulation | 7 | |
| Monsoons, air masses, fronts and cyclones | 7 | |
| Layers of the atmosphere and their characteristics | 6 | |
| Atmospheric humidity: vapour pressure, relative humidity, dew point, VPD | 6 | |
| Clouds, precipitation processes and forms | 6 | |
| Climatic classification: Köppen and Thornthwaite | 6 | |
| Atmospheric stability and adiabatic processes | 4 |
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
Kirchhoff's law states that, for a body in thermal equilibrium,
C. its emissivity at a wavelength equals its absorptivity at that wavelength
Kirchhoff's law links emissivity and absorptivity at the same wavelength. The other statements are the Stefan–Boltzmann law, Wien's law and the Beer–Lambert law.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Which surface has the highest albedo?
A. Fresh snow
Fresh snow reflects about 80–90% of sunlight; green crops about 20–25%; water at high sun about 6%; forests about 10–20%.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Surface air temperature is 30 °C and the dew point is 18 °C. Using the approximation of 125 m per °C of dew-point depression, at what height will a rising parcel reach its lifting condensation level?
D. 1500 m
LCL ≈ 125 × (30 − 18) = 1500 m. 3750 m uses the air temperature alone; 2250 m uses the dew point alone; 12 m forgets the 125 m factor.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Using f = 2Ω sin φ with Ω = 7.292 × 10⁻⁵ s⁻¹, what is the Coriolis parameter at 30° latitude?
A. 7.292 × 10⁻⁵ s⁻¹
f = 2 × 7.292 × 10⁻⁵ × sin 30° = 2 × 7.292 × 10⁻⁵ × 0.5 = 7.29 × 10⁻⁵ s⁻¹. 1.46 × 10⁻⁴ is the polar value; 3.65 × 10⁻⁵ omits the factor 2; 0 is the equatorial value.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
What is the India Meteorological Department's normal date of southwest monsoon onset over Kerala?
A. 1 June
IMD's normal onset date over Kerala is 1 June, with a standard deviation of about seven days.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
What is the central concept of Thornthwaite's 1948 climate classification?
D. Potential evapotranspiration set against precipitation
Thornthwaite based his scheme on PE estimated from temperature and day length, and on the water balance of precipitation against PE. Köppen's scheme was designed around vegetation; frost days and wind are not his basis.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Why should a Thornthwaite moisture-index boundary always be quoted with the formula used?
C. The 1948 index weights aridity by 0.6 and the 1955 Thornthwaite–Mather one does not
Different formulations of Im exist (1948 with a 0.6 weighting of the aridity index; Thornthwaite–Mather 1955 without), so class boundaries and values are not interchangeable. The index is global, uses no wind, and remains in use.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Why was photoperiod insensitivity a key trait of Green Revolution rice and wheat varieties?
A. They flowered on time across latitudes and seasons, widening where they could grow
Insensitive varieties flower according to temperature and age, not day length, so they fit different latitudes and sowing dates. They still need water and are not inherently pest-resistant.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Reference ETo is 6.0 mm day⁻¹ and the mid-season crop coefficient is 1.15. What is crop evapotranspiration?
C. 6.9 mm day⁻¹
ETc = Kc × ETo = 1.15 × 6.0 = 6.9. Dividing gives 5.2; adding gives 7.15; 6.0 ignores Kc.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
Wind speed measured at 10 m is 3.2 m s⁻¹. Using FAO-56, u₂ = uz × 4.87/ln(67.8z − 5.42), what is the wind speed at 2 m?
D. 2.39 m s⁻¹
ln(678 − 5.42) = 6.511; u₂ = 3.2 × 4.87/6.511 = 2.39. 3.20 ignores the height correction; 0.64 scales linearly with height; 4.28 inverts the factor.
Further reading: See the manual sources: FAO-56, WMO Guide to Agricultural Meteorological Practices, and the textbooks named there
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