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GATE Chilling, Freezing & Frozen Food Technology: practice questions

GATE — Engineering Sciences (XE), Section G Food Technology · India · IITs and IISc on rotation (2026: IIT Guwahati)

Original practice questions written to the published syllabus · not past papers
10worked here, free
59written to this exam in this subject
11syllabus units

What this subject covers

Low-temperature preservation from the food's side: chilling and controlled atmospheres, freezing-point depression and ice crystallisation, freezing-time calculation, freezer types, frozen storage changes and thawing. The refrigeration cycle and cold-store design are in Agricultural Engineering's refrigeration-cold-chain.

In the exams: GATE XE-G Section 3 (chilling, freezing) and Section 4 (freezing and crystallisation); ICAR AICE 35.a Unit 2 (IQF products)

What GATE asks from it

GATE — Engineering Sciences (XE), Section G Food Technology

Section 3 names chilling and freezing as processing principles and controlled atmosphere storage; Section 4 names freezing and crystallisation among thermal operations, alongside heat transfer. Expect numericals on freezing-point depression, heat removed in freezing (Siebel-type estimates), Plank's freezing time for slabs, cylinders and spheres, and half-cooling times, plus reasoning on slow versus fast freezing, drip and recrystallisation.

GATE — Life Sciences (XL), Section U Food Technology

Same syllabus as XE-G. Questions often connect low temperature to microbiology (psychrotrophs, Listeria, non-proteolytic C. botulinum) and to chemistry (unfrozen water, oxidation in frozen storage, blanching enzymes).

Where the 59 questions fall

How our questions for GATE spread across the units of Chilling, Freezing & Frozen Food Technology. Difficulty: 15 easy, 32 medium, 12 hard.

Chilling and chilled storage of foods8
Freezing-point depression and unfrozen water8
Freezing-time prediction: Plank's equation and its refinements7
Ice nucleation, crystal growth and recrystallisation6
Air-blast, plate, cryogenic and IQF freezers6
Freezing of fruits, vegetables, meat, fish and ready meals6
Cold-chain requirements for chilled foods4
Changes during frozen storage: freezer burn, drip loss and oxidation4
Time-temperature tolerance and shelf life of frozen foods4
Thawing and tempering4
Supercooling, isochoric and other emerging freezing methods2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Chilling and chilled storage of foods · hard

Non-proteolytic Clostridium botulinum is a particular hazard in long-life, reduced-oxygen chilled foods because it

  1. grows only above 30 °C but forms toxin very quickly once the pack warms up
  2. is usually destroyed completely by chilling to 4 °C for about one day
  3. produces gas and odour that always warn the consumer before toxin forms
  4. can grow and form toxin down to about 3 °C
Answer and working

D. can grow and form toxin down to about 3 °C

Non-proteolytic strains grow at about 3 °C and above, often without obvious spoilage signs, so sous-vide and vacuum-packed chilled foods need limits on shelf life, temperature or other hurdles.

Further reading: Fellows, Food Processing Technology

2 · Chilling and chilled storage of foods · medium

Bananas stored at 5 °C develop dark skin and fail to ripen. This is

  1. chilling injury
  2. freezer burn of the peel
  3. cold shortening
  4. ethylene injury from warm storage
Answer and working

A. chilling injury

Tropical fruits suffer chilling injury below a critical temperature, about 10–13 °C for bananas, though no ice forms. Freezer burn and cold shortening concern frozen foods and meat.

Further reading: Fellows, Food Processing Technology

3 · Freezing-point depression and unfrozen water · hard

For the same food with initial freezing point −1.5 °C, the fraction of freezable water frozen at −3 °C is about

  1. 92 %
  2. 25 %
  3. 0 %
  4. 50 %
Answer and working

D. 50 %

1 − 1.5/3 = 0.50, so half the freezable water is ice just 1.5 K below the initial freezing point. 92 % is the value at −18 °C; 0 % would mean no freezing below Tf.

Further reading: Singh and Heldman, Introduction to Food Engineering

4 · Ice nucleation, crystal growth and recrystallisation · hard

Large frozen items such as whole tuna can crack when frozen very rapidly in liquid nitrogen because

  1. liquid nitrogen often reacts chemically with fish proteins and weakens the muscle structure
  2. rapid freezing removes all the water from the surface as vapour
  3. water expands on freezing and the rigid outer shell cannot accommodate the core
  4. the core contracts on freezing and pulls the surface inwards
Answer and working

C. water expands on freezing and the rigid outer shell cannot accommodate the core

The outer layer freezes first and becomes rigid; when the interior freezes and expands, stress cracks the shell.

Further reading: Sun (ed.), Handbook of Frozen Food Processing and Packaging

5 · Freezing-time prediction: Plank's equation and its refinements · hard

Plank's equation, infinite slab (P = 1/2, R = 1/8): fish 5 cm thick, ρ = 1,000 kg/m³, latent heat 250 kJ/kg, Tf = −1.5 °C, air at −30 °C, h = 20 W/m² K, frozen k = 1.5 W/m K. The freezing time is closest to

  1. 1.6 h
  2. 3.6 h
  3. 1.2 h
  4. 4.6 h
Answer and working

B. 3.6 h

t = (1,000 × 250,000/28.5)(0.5 × 0.05/20 + 0.125 × 0.05²/1.5) = 8.77 × 10⁶ × 1.458 × 10⁻³ = 12,792 s = 3.6 h. 1.6 h uses the half-thickness; 1.2 h uses sphere factors; 4.6 h uses the unfrozen conductivity 0.5 W/m K.

Further reading: Singh and Heldman, Introduction to Food Engineering

6 · Freezing-time prediction: Plank's equation and its refinements · hard

The same 5 cm fish slab (ρ = 1,000 kg/m³, λ = 250 kJ/kg, Tf = −1.5 °C, k = 1.5 W/m K) is frozen in a plate freezer with medium at −30 °C and h = 200 W/m² K. By Plank's equation the freezing time is closest to

  1. 487 min
  2. 18 min
  3. 49 min
  4. 0.8 min
Answer and working

C. 49 min

t = 8.77 × 10⁶ × (1.25 × 10⁻⁴ + 2.08 × 10⁻⁴) = 2,924 s ≈ 49 min. 487 min is ten times too long; 18 min keeps only the surface term and ignores internal conduction; 0.8 min confuses hours with minutes.

Further reading: Singh and Heldman, Introduction to Food Engineering

7 · Freezing-time prediction: Plank's equation and its refinements · easy

In Plank's equation, the shape factors for an infinite slab are

  1. P = 1/6 and R = 1/24
  2. P = 1/4 and R = 1/16
  3. P = 1 and R = 1
  4. P = 1/2 and R = 1/8
Answer and working

D. P = 1/2 and R = 1/8

Slab 1/2 and 1/8; cylinder 1/4 and 1/16; sphere 1/6 and 1/24.

Further reading: Singh and Heldman, Introduction to Food Engineering

8 · Freezing-time prediction: Plank's equation and its refinements · medium

For a thin product frozen in still air (very low h), doubling its thickness changes the freezing time by a factor of about

  1. 4
  2. 2
  3. 1
  4. 0.5
Answer and working

B. 2

With small h the external term Pa/h dominates, so time is roughly proportional to thickness: doubling a doubles t.

Further reading: Singh and Heldman, Introduction to Food Engineering

9 · Time-temperature tolerance and shelf life of frozen foods · hard

A frozen vegetable has practical storage lives of 360 days at −24 °C, 270 days at −18 °C and 90 days at −12 °C. It spends 100 days at −24 °C, 40 days at −18 °C and 20 days at −12 °C. Its remaining life at −18 °C is about

  1. 110 days
  2. 95 days
  3. 155 days
  4. 195 days
Answer and working

B. 95 days

Fraction used = 100/360 + 40/270 + 20/90 = 0.278 + 0.148 + 0.222 = 0.648; remaining 0.352 × 270 = 95 days. 110 days subtracts total days and ignores the different rates; 155 days leaves out the retail period at −12 °C; 195 days counts only the −24 °C period.

Further reading: Kennedy (ed.), Managing Frozen Foods

10 · Time-temperature tolerance and shelf life of frozen foods · medium

High quality life (HQL) of a frozen food is the storage time until

  1. a trained panel first detects a significant difference from a reference sample
  2. the product becomes unsafe to eat because of bacterial growth in the frozen state
  3. the product is no longer acceptable for sale or consumption
  4. all of its vitamin C has been lost
Answer and working

A. a trained panel first detects a significant difference from a reference sample

HQL is a 'just noticeable difference' (often 70 % correct in triangle tests); PSL is the longer limit of acceptability.

Further reading: Kennedy (ed.), Managing Frozen Foods

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Read the subject

Chilling, Freezing & Frozen Food TechnologyThe full study manual, free GATEFormat, sections and how it has changed

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Chilling, Freezing & Frozen Food Technology for other exams

ICAR AICE-JRF/SRF · IndiaGATE · IndiaICAR AIEEA-PG / PGS · India

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