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GATE Human Engineering, Ergonomics & Safety: practice questions

GATE — Agricultural Engineering (AG) · India · IITs and IISc on rotation (2026: IIT Guwahati)

Original practice questions written to the published syllabus · not past papers
10worked here, free
37written to this exam in this subject
8syllabus units

What this subject covers

Designing machines around the people who use them, and measuring the noise, vibration and work load they face.

In the exams: GATE AG Section 3 (ergonomics asked in all 8 papers 2019–26); ICAR AIEEA-PG Unit V; ICAR AICE subject 39 Unit 5; NCEES PE health and safety

What GATE asks from it

GATE — Agricultural Engineering (AG)

Human engineering and safety in the Farm Power section: numerical questions on adding decibel levels, change of level with distance or number of sources, noise dose, vibration transmissibility, natural frequency and damping ratio from logarithmic decrement, rms acceleration, anthropometric percentiles from mean and SD, and energy expenditure from oxygen uptake or heart rate. NAT answers are sensitive to using 10 log versus 20 log and rms versus peak.

Where the 37 questions fall

How our questions for GATE spread across the units of Human Engineering, Ergonomics & Safety. Difficulty: 8 easy, 18 medium, 11 hard.

Vibration: transmissibility and damping11
Noise: decibels and exposure9
Work physiology: energy expenditure, heart rate and oxygen uptake6
Anthropometry5
Design of controls and seats3
Dust and thermal stress1
Safety standards and ROPS1
Tools designed for women workers1

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Anthropometry · easy

The stature of a group of farm workers is normally distributed with mean 1640 mm and standard deviation 58 mm. The 95th percentile stature is closest to

  1. 1754 mm
  2. 1545 mm
  3. 1698 mm
  4. 1735 mm
Answer and working

D. 1735 mm

X95 = mean + 1.645 × SD = 1640 + 1.645 × 58 = 1735.4 mm. Mean + 1 SD (1698 mm) is only the 84th percentile; 1545 mm is the 5th percentile; z = 1.96 (1754 mm) is the 97.5th percentile, a common slip from two-sided confidence intervals.

2 · Design of controls and seats · easy

A tractor operator must identify the hydraulic lift lever by touch without looking at it. The most suitable coding method is

  1. labelling
  2. coding by the colour of the adjacent panel
  3. shape coding
  4. colour coding
Answer and working

C. shape coding

Shape (and texture or size) can be felt through gloves without looking. Colour and labels need vision and good lighting.

3 · Design of controls and seats · medium

Increasing the control-response (C/R) ratio of a control, other things equal,

  1. speeds gross movement but worsens fine adjustment
  2. has no effect on positioning time
  3. speeds gross movement and improves fine adjustment at the same time
  4. improves fine adjustment but slows gross movement to a target
Answer and working

D. improves fine adjustment but slows gross movement to a target

A high C/R ratio means large control movement for small response: slow travel, precise final positioning. A low ratio gives fast travel but overshoot. Total time is minimised at an intermediate ratio.

4 · Work physiology: energy expenditure, heart rate and oxygen uptake · medium

Using the regression EE (kJ/min) = 0.159 × HR − 8.72, the energy expenditure of a woman worker whose average working heart rate is 130 beats/min is

  1. 2.85 kJ/min
  2. 20.67 kJ/min
  3. 11.95 kJ/min
  4. 29.39 kJ/min
Answer and working

C. 11.95 kJ/min

EE = 0.159 × 130 − 8.72 = 20.67 − 8.72 = 11.95 kJ/min. Omitting the constant gives 20.67; adding it gives 29.39; 2.85 is the kcal/min value mislabelled as kJ/min.

Further reading: Varghese et al. regression used in Indian farm ergonomics

5 · Work physiology: energy expenditure, heart rate and oxygen uptake · hard

A pedal-operated thresher is driven with a mechanical power output of 60 W while the operator's energy expenditure is 21 kJ/min. The gross mechanical efficiency is about

  1. 17.1%
  2. 28.6%
  3. 4.8%
  4. 2.9%
Answer and working

A. 17.1%

21 kJ/min = 21 000/60 = 350 W; η = 60/350 = 17.1%. 28.6% divides 60 W by 210 instead of 350 (a slip in converting kJ/min to W); 2.9% is 60/21 = 2.86 with the units ignored; 4.8% divides 60 by 21 × 60 = 1260, multiplying by 60 instead of dividing. A value near 17% is plausible for pedalling.

6 · Noise: decibels and exposure · medium

Three identical pumps each produce 90 dB at the operator's position. With all three running, the level is about

  1. 94.8 dB
  2. 93.0 dB
  3. 99.5 dB
  4. 270.0 dB
Answer and working

A. 94.8 dB

L = 90 + 10 log 3 = 94.77 dB. 93 dB is the two-source answer; 270 is arithmetic addition; 99.5 wrongly uses 20 log 3.

7 · Noise: decibels and exposure · hard

Ten identical chaff cutters in a shed each produce 84 dB at a point. With all ten running, the level is

  1. 87 dB
  2. 840 dB
  3. 104 dB
  4. 94 dB
Answer and working

D. 94 dB

L = 84 + 10 log 10 = 94 dB. 87 is the two-source result; 104 uses 20 log 10; 840 is arithmetic addition.

8 · Vibration: transmissibility and damping · medium

A seat must isolate (transmit less than the input of) vibration at 5 Hz. Its natural frequency must be below about

  1. 7.07 Hz
  2. 2.50 Hz
  3. 3.54 Hz
  4. 5.00 Hz
Answer and working

C. 3.54 Hz

Isolation needs r = f/fn > √2, so fn < 5/√2 = 3.54 Hz. 5 Hz would be resonance; 7.07 Hz inverts the ratio; 2.5 Hz is sufficient but is not the limit.

9 · Vibration: transmissibility and damping · medium

A tractor driver is exposed to a frequency-weighted rms acceleration of 0.8 m/s² for 5 hours a day. The daily exposure A(8) is about

  1. 1.01 m/s²
  2. 0.63 m/s²
  3. 0.50 m/s²
  4. 0.80 m/s²
Answer and working

B. 0.63 m/s²

A(8) = aw √(T/8) = 0.8 × √(5/8) = 0.632 m/s². Linear scaling gives 0.50; ignoring duration gives 0.80; inverting the ratio gives 1.01.

10 · Vibration: transmissibility and damping · medium

A seat with stiffness 40000 N/m, effective mass 90 kg and damping coefficient 760 N·s/m has a damping ratio of about

  1. 0.40
  2. 0.20
  3. 0.28
  4. 0.10
Answer and working

B. 0.20

cc = 2√(km) = 2√(40000 × 90) = 3795 N·s/m; ζ = c/cc = 760/3795 = 0.200. Forgetting the factor 2 gives 0.40; the other options are formula slips. Putting the 2 inside the root, √(2km) = 2683, gives 0.28, and using 4√(km) gives 0.10.

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Read the subject

Human Engineering, Ergonomics & SafetyThe full study manual, free GATEFormat, sections and how it has changed

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Human Engineering, Ergonomics & Safety for other exams

ICAR AICE-JRF/SRF · IndiaICAR AIEEA-PG · IndiaRajasthan PSC · India

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