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GATE Hydrology & Water Resources for Environmental Scientists: practice questions

GATE — Environmental Science and Engineering (ES) · India · IITs and IISc on rotation (2026: IIT Guwahati)

Original practice questions written to the published syllabus · not past papers
10worked here, free
37written to this exam in this subject
12syllabus units

What this subject covers

The water cycle, surface and groundwater resources and the hydraulics that GATE ES Section 4 examines. Agricultural engineering already teaches watershed hydrology, groundwater and canal hydraulics to design level (subjects watershed-hydrology and groundwater-wells-pumps); this subject covers what an environmental scientist needs and the environmental framing: water balance, threats to water resources and channel and pipe flow basics.

In the exams: GATE ES Section 4 (a large numerical section); ICAR AIEEA-PG Water Science & Technology group; ICAR AICE subject 71 Unit 1 (watersheds)

What GATE asks from it

GATE -- Environmental Science and Engineering (Section 4)

A heavily numerical section: water balance, SCS-CN and rational method, unit hydrograph convolution, Muskingum coefficients, Darcy and seepage velocity, Thiem and Dupuit wells, hydrostatic forces, Bernoulli and continuity, Darcy-Weisbach, Manning, critical depth, hydraulic jump, venturi and weirs. Numerical-answer-type items demand exact unit handling.

Where the 37 questions fall

How our questions for GATE spread across the units of Hydrology & Water Resources for Environmental Scientists. Difficulty: 16 easy, 14 medium, 7 hard.

Continuity, momentum and energy equations; pipe flow and pipe networks4
Open-channel flow: specific energy, critical flow, hydraulic jump4
The hydrological cycle and water balance3
Precipitation, infiltration, evapotranspiration and runoff3
Hydrographs and the unit hydrograph3
Stage-discharge relationships and reservoir capacity3
Reservoir and channel routing3
Aquifers: confined, unconfined, porosity, transmissivity, storage3
Darcy's law and steady-state well hydraulics3
Fluid properties, hydrostatics, buoyancy3
Flow measurement in pipes and channels3
Global water resources: distribution, quality and threats2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Global water resources: distribution, quality and threats · easy

Where is most of the world's fresh water stored?

  1. Rivers and streams
  2. The atmosphere
  3. Ice and snow
  4. Freshwater lakes
Answer and working

C. Ice and snow

About 69% is ice and snow, about 30% groundwater, about 1% surface and other water.

2 · Hydrographs and the unit hydrograph · hard

A 3-hour unit hydrograph (for 1 cm) has ordinates [0, 20, 50, 30, 10, 0] m3/s at 3-hour intervals. Effective rainfall is 2.0 cm in the first 3 hours and 1.0 cm in the next 3 hours. What is the peak of the direct runoff hydrograph?

  1. 110 m3/s
  2. 120 m3/s
  3. 100 m3/s
  4. 150 m3/s
Answer and working

B. 120 m3/s

Convolution: DRH = 2 x UH(t) + 1 x UH(t - 3 h); ordinates [0.0, 40.0, 120.0, 110.0, 50.0, 10.0, 0.0]; peak 120. Multiplying the UH peak by 3 cm assumes both blocks peak together; 110 is the next ordinate, not the peak.

3 · Stage-discharge relationships and reservoir capacity · easy

The storage in a reservoir below the lowest outlet is called:

  1. Flood storage
  2. Dead storage
  3. Live storage
  4. Surcharge storage
Answer and working

B. Dead storage

Dead storage is unusable by gravity and partly reserved for sediment.

4 · Stage-discharge relationships and reservoir capacity · hard

Monthly inflows to a reservoir site are [10, 2, 1, 8, 12, 3, 1, 9] (million m3) and the demand is a constant 6 million m3/month. Using the sequent peak (cumulative deficit) method, what storage is required?

  1. 17 million m3
  2. 9 million m3
  3. 2 million m3
  4. 5 million m3
Answer and working

B. 9 million m3

Running deficit K_t = max(0, K_t-1 + demand - inflow): the maximum is 9. Summing all monthly shortfalls (17) ignores refilling between dry spells.

5 · Reservoir and channel routing · hard

Using C0 = 0.048, C1 = 0.429, C2 = 0.524, inflows I1 = 30 and I2 = 50 m3/s and outflow O1 = 25 m3/s, what is O2?

  1. 36.0 m3/s
  2. 40.0 m3/s
  3. 15.2 m3/s
  4. 28.3 m3/s
Answer and working

D. 28.3 m3/s

O2 = C0 I2 + C1 I1 + C2 O1 = 2.38 + 12.86 + 13.10 = 28.3. Swapping I1 and I2 gives 36.0.

6 · Darcy's law and steady-state well hydraulics · hard

A well pumps 1,728 m3/day from a confined aquifer. Steady drawdowns are 3.0 m at 10 m and 1.0 m at 100 m. Using Thiem, what is the transmissivity?

  1. 158 m2/day
  2. 633 m2/day
  3. 138 m2/day
  4. 317 m2/day
Answer and working

D. 317 m2/day

T = Q ln(r2/r1) / [2 pi (s1 - s2)] = 1,728 x 2.303 / (2 pi x 2) = 317. Using log10 gives 138.

7 · Continuity, momentum and energy equations; pipe flow and pipe networks · easy

Water flows at 0.05 m3/s through a pipe of diameter 0.1 m. What is the mean velocity?

  1. 0.50 m/s
  2. 1.59 m/s
  3. 0.00039 m/s
  4. 6.37 m/s
Answer and working

D. 6.37 m/s

V = Q / A = 0.05 / (pi x 0.05^2) = 6.37. Using d instead of d/2 in the area gives 1.59.

8 · Continuity, momentum and energy equations; pipe flow and pipe networks · medium

A pump delivers 0.1 m3/s against a head of 30 m with efficiency 0.75. What power does it require?

  1. 39.2 kW
  2. 4.0 kW
  3. 22.1 kW
  4. 29.4 kW
Answer and working

A. 39.2 kW

P = rho g Q H / eta = 1,000 x 9.81 x 0.1 x 30 / 0.75 = 39.2 kW.

9 · Open-channel flow: specific energy, critical flow, hydraulic jump · easy

Minimum specific energy in a rectangular channel equals:

  1. 1.5 times critical depth
  2. Critical depth
  3. 0.5 times critical depth
  4. 2 times critical depth
Answer and working

A. 1.5 times critical depth

E_min = 1.5 y_c. At this minimum the flow is critical, with Froude number 1.

10 · Flow measurement in pipes and channels · hard

A venturi meter (inlet 0.3 m, throat 0.15 m diameter, Cd = 0.98) shows a differential head of 0.5 m of water. What is the discharge?

  1. 0.0542 m3/s
  2. 0.0396 m3/s
  3. 0.0560 m3/s
  4. 0.0343 m3/s
Answer and working

C. 0.0560 m3/s

Q = Cd A1 A2 sqrt(2gh)/sqrt(A1^2 - A2^2) = 0.0560. Ignoring the approach-velocity term or using Cd = 0.6 gives the others.

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Hydrology & Water Resources for Environmental ScientistsThe full study manual, free GATEFormat, sections and how it has changed

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