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ICAR AICE-JRF/SRF Laboratory Animal Science & Medicine: practice questions

ICAR AICE-JRF/SRF (PhD) · India · NTA for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
48written to this exam in this subject
9syllabus units

What this subject covers

Biology, housing and health monitoring of laboratory animals, their common diseases, the 3Rs, ethics committees and experimental techniques.

In the exams: EAEVE Day One competence on the 3Rs; ACLAM and ECLAM specialist colleges

What ICAR AICE-JRF/SRF asks from it

ICAR AICE-JRF/SRF (PhD) and ASRB NET (India)

Factual one-liners on species biology (gestation, vitamin C in guinea pigs, rat has no gall bladder, hamster cheek pouches, gerbil stroke model), inbred strain definition and nomenclature, microbiological status terms (germ-free, gnotobiotic, SPF), the named diseases (Tyzzer's agent and lesion triad, MRM agent and cofactors, rabbit pasteurellosis forms), the 3Rs and Russell and Burch, and CPCSEA/CCSEA and IAEC rules.

Where the 48 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Laboratory Animal Science & Medicine. Difficulty: 24 easy, 22 medium, 2 hard.

Biology of laboratory species11
Housing of laboratory animals6
Health monitoring6
Tyzzer's disease5
Murine respiratory mycoplasmosis5
Experimental techniques5
Pasteurellosis4
The 3Rs: replacement, reduction and refinement3
Animal ethics committees: CPCSEA, IACUC and EU Directive 2010/633

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Biology of laboratory species · easy

Which rat is the classic spontaneous model of central diabetes insipidus because it cannot produce vasopressin?

  1. Brattleboro rat
  2. Gunn rat
  3. Zucker fatty rat
  4. Spontaneously hypertensive rat
Answer and working

A. Brattleboro rat

The Brattleboro rat has a vasopressin gene mutation causing central diabetes insipidus. The Gunn rat models unconjugated hyperbilirubinaemia, the Zucker rat obesity from a leptin receptor mutation, and the SHR essential hypertension.

Further reading: Standard laboratory animal science texts

2 · Housing of laboratory animals · medium

A room measures 4 m x 5 m x 3 m and receives 900 cubic metres of fresh air per hour. How many air changes per hour does it receive?

  1. 5
  2. 45
  3. 15
  4. 0.25
Answer and working

C. 15

Room volume = 4 x 5 x 3 = 60 cubic metres. Air changes per hour = 900 / 60 = 15. 45 comes from dividing by the floor area of 20 square metres and forgetting the height; 0.25 is 15 divided by 60, a per-minute figure; 5 comes from multiplying the height in again (900 / 180).

Further reading: NRC Guide, 8th ed.

3 · Health monitoring · medium

Using n = log(1 - C) / log(1 - p), how many animals must be sampled to have 95% confidence of detecting at least one infected animal when the prevalence is 30%, assuming a large population, random sampling and a perfect test?

  1. 8
  2. 3
  3. 9
  4. 30
Answer and working

C. 9

n = log(0.05) / log(0.70) = 8.40, which rounds up to 9 because you cannot sample part of an animal and must not fall below the confidence target. 8 comes from rounding down; 3 from multiplying 0.3 by 10; 30 confuses prevalence with sample size.

Further reading: ILAR/FELASA health-monitoring sampling principles

4 · Health monitoring · easy

Which test is the method of choice for detecting the mouse pinworm Syphacia obvelata?

  1. Perianal cellophane tape test
  2. Faecal flotation in saturated salt
  3. Serology for anti-pinworm antibody
  4. Direct pelage examination under a lens
Answer and working

A. Perianal cellophane tape test

Syphacia females lay eggs on the perianal skin, so the tape test finds them; eggs are seldom in faeces. Faecal flotation is used for Aspiculuris, whose eggs are passed in faeces; pelage examination is for fur mites.

Further reading: Fox et al., Laboratory Animal Medicine

5 · Tyzzer's disease · medium

Why does a negative routine bacterial culture of liver lesions not exclude Tyzzer's disease?

  1. The organism grows only at 25 degrees C and is missed at standard incubation temperature
  2. The organism is a virus, so bacterial culture is never appropriate for this disease
  3. Culture is always contaminated by faecal flora, which overgrows the agent within hours
  4. Clostridium piliforme is obligately intracellular and does not grow on cell-free media
Answer and working

D. Clostridium piliforme is obligately intracellular and does not grow on cell-free media

C. piliforme can be propagated only in embryonated eggs, cell culture or animals, so diagnosis relies on histology with special stains, PCR and serology. It is a bacterium, not a virus, and incubation temperature is not the issue.

Further reading: Fox et al., Laboratory Animal Medicine

6 · Murine respiratory mycoplasmosis · medium

An adult rat has 'snuffling' respiratory noise, porphyrin staining round the eyes and a head tilt. Which disease best accounts for all three signs?

  1. Tyzzer's disease with hepatic encephalopathy
  2. Sialodacryoadenitis with cervical swelling only
  3. Ringtail with secondary ascending infection
  4. Murine respiratory mycoplasmosis with otitis media
Answer and working

D. Murine respiratory mycoplasmosis with otitis media

MRM causes rhinitis (snuffling), stress-related porphyrin staining and otitis media, which produces head tilt. Sialodacryoadenitis causes cervical swelling and eye lesions but not the chronic otitis; Tyzzer's disease is an enteric-hepatic disease; ringtail is a tail lesion.

Further reading: Barthold et al., Pathology of Laboratory Rodents and Rabbits

7 · Pasteurellosis · medium

Which form of pasteurellosis results from spread of Pasteurella multocida up the Eustachian tube in rabbits?

  1. Otitis media and otitis interna with torticollis
  2. Dacryocystitis and conjunctivitis via the tear duct
  3. Pyometra and metritis in does
  4. Orchitis and epididymitis in bucks
Answer and working

A. Otitis media and otitis interna with torticollis

Ascent of the Eustachian tube leads to otitis media and, by extension, otitis interna with head tilt. Spread along the nasolacrimal duct gives dacryocystitis and conjunctivitis; genital forms arise from venereal or haematogenous spread.

Further reading: Fox et al., Laboratory Animal Medicine

8 · The 3Rs: replacement, reduction and refinement · medium

A study uses liver cells taken from rats humanely killed for another purpose instead of dosing live rats. In Russell and Burch's terms, what kind of replacement is this?

  1. Absolute replacement
  2. Reduction by tissue sharing only
  3. Refinement of the original procedure
  4. Relative replacement
Answer and working

D. Relative replacement

Relative replacement still uses animals or their tissues but avoids procedures on living sentient animals. Absolute replacement uses no animal material, such as human cells or computer models. Tissue sharing also reduces numbers, but the method itself is classed as relative replacement.

Further reading: Russell and Burch, 1959

9 · Animal ethics committees: CPCSEA, IACUC and EU Directive 2010/63 · medium

Which member is required on an Indian Institutional Animal Ethics Committee to represent the central committee (CCSEA, formerly CPCSEA)?

  1. A district magistrate
  2. A nominee of the central committee
  3. A representative of the state animal husbandry department
  4. A member of the state legislative assembly
Answer and working

B. A nominee of the central committee

The IAEC includes a nominee of the central committee, alongside scientists, a veterinarian, the scientist in charge of the animal house, an outside scientist and a socially aware non-scientist. The other officials are not required members.

Further reading: CCSEA (formerly CPCSEA) guidelines

10 · Experimental techniques · medium

A test compound is to be given by oral gavage to mice at 20 mg/kg in a dose volume of 10 mL/kg. What concentration should the dosing solution have, and what volume does a 25 g mouse receive?

  1. 0.2 mg/mL; 2.5 mL
  2. 2 mg/mL; 0.25 mL
  3. 20 mg/mL; 0.025 mL
  4. 2 mg/mL; 2.5 mL
Answer and working

B. 2 mg/mL; 0.25 mL

Concentration = dose / volume = 20 mg/kg / 10 mL/kg = 2 mg/mL. Volume = 10 mL/kg x 0.025 kg = 0.25 mL. 2.5 mL mistakes 25 g for 0.25 kg; 0.2 mg/mL and 20 mg/mL are factor-of-ten slips.

Further reading: Diehl et al., 2001

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Read the subject

Laboratory Animal Science & MedicineThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

More ICAR AICE-JRF/SRF practice

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Laboratory Animal Science & Medicine for other exams

EBVS European College diplomas · EuropeAVMA ABVS-recognised specialty boards · USAASRB NET and ARS / SMS / STO · India

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