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ASRB NET Farm Power Sources: practice questions

ASRB NET — Farm Machinery & Power / Land & Water Management Engineering / Agricultural Structures & Process Engineering · India · Agricultural Scientists Recruitment Board (ICAR)

Original practice questions written to the published syllabus · not past papers
9worked here, free
37written to this exam in this subject
8syllabus units

What this subject covers

Where the energy for farm work comes from, how much is available, and how mechanisation is measured.

In the exams: GATE AG Section 3 Sources of Power; ICAR AIEEA-PG Unit V; PRC ABE power and machinery (32%)

What ASRB NET asks from it

ASRB NET — Farm Machinery & Power

Farm power scenario, draught animal power and harnessing, mechanisation indices and energy analysis; theory-heavy MCQs.

Where the 37 questions fall

How our questions for ASRB NET spread across the units of Farm Power Sources. Difficulty: 7 easy, 18 medium, 12 hard.

Mechanisation indices12
Farm power availability (kW/ha)9
Biomass and biofuels as power sources4
Animal draught power and harnessing3
Mechanical power: engines and tractors3
Electrical power on the farm3
Human power and its limits2
Wind power as a farm power source1

9 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Human power and its limits · medium

In an energy audit, male labour is counted at 1.96 MJ per man-hour. What energy input is recorded for 12 men working 8 hours each?

  1. 15.68 MJ
  2. 23.52 MJ
  3. 52.3 MJ
  4. 188.16 MJ
Answer and working

D. 188.16 MJ

Man-hours = 12 × 8 = 96; energy = 96 × 1.96 = 188.16 MJ. 15.68 MJ counts only one worker; 23.52 MJ forgets the hours; 52.3 is the same energy in kWh, wrongly labelled MJ.

2 · Mechanical power: engines and tractors · medium

Why do diesel (compression-ignition) engines, rather than petrol engines, power nearly all tractors?

  1. Higher compression ratio gives higher thermal efficiency and good low-speed torque
  2. They need no fuel injection system
  3. They are lighter per kW than petrol engines, so the tractor compacts the soil less
  4. They run at higher speeds than petrol engines, giving more power per litre of displacement
Answer and working

A. Higher compression ratio gives higher thermal efficiency and good low-speed torque

Diesel engines use high compression ratios, giving higher thermal efficiency, and deliver high torque at low speed, suited to heavy continuous farm loads. They are heavier and slower-running than petrol engines and depend on fuel injection.

3 · Wind power as a farm power source · medium

Why are multi-blade, high-solidity rotors used on windmills that drive piston pumps for stock water?

  1. High starting torque at low wind speed and slow rotation suit a pump that starts under load
  2. They reach the highest tip speed ratios of any rotor
  3. They have the highest power coefficient of all rotor types, exceeding the Betz limit at low wind
  4. They need no tail vane or yawing mechanism
Answer and working

A. High starting torque at low wind speed and slow rotation suit a pump that starts under load

High solidity gives high torque at low speed (tip speed ratio about 1), which a reciprocating pump needs to start. Two- or three-blade low-solidity rotors run at high tip speed ratios and suit generators.

4 · Biomass and biofuels as power sources · medium

Producer gas from an air-blown biomass gasifier has a low calorific value (roughly 4–6 MJ/m³) mainly because:

  1. It contains mostly methane
  2. Its hydrogen content exceeds 80%
  3. It is produced at high pressure
  4. It contains a large fraction of nitrogen from the gasifying air
Answer and working

D. It contains a large fraction of nitrogen from the gasifying air

The combustible components are CO and H2 with some CH4, but air brings in nitrogen, which dilutes the gas along with CO2. Oxygen- or steam-blown gasifiers give richer gas.

5 · Farm power availability (kW/ha) · hard

A block has 400 ha net sown area, 25 tractors of 30 kW, 10 power tillers of 9 kW, 150 electric motors of 5 kW, 60 diesel engines of 4 kW, 300 draught animals (0.38 kW each) and 900 workers (0.05 kW each). What is the farm power availability?

  1. 4.58 kW/ha
  2. 4.97 kW/ha
  3. 2.84 kW/ha
  4. 1.88 kW/ha
Answer and working

B. 4.97 kW/ha

Total = 750 + 90 + 750 + 240 + 114 + 45 = 1,989 kW; ÷ 400 ha = 4.97 kW/ha. Excluding people and animals gives 4.58; counting tractors only gives 1.88; dividing by a gross cropped area of 700 ha gives 2.84.

6 · Farm power availability (kW/ha) · hard

A district of 10,000 ha net sown area has 2.0 kW/ha. The target is 4.0 kW/ha, to be met entirely with 35 kW tractors. About how many additional tractors are needed?

  1. 1143 tractors
  2. 58 tractors
  3. 1715 tractors
  4. 572 tractors
Answer and working

D. 572 tractors

Additional power = (4.0 − 2.0) × 10,000 = 20,000 kW; tractors = 20,000/35 = 571.4 → 572. Using the full 4 kW/ha ignores existing power (1143). In practice targets are met with a mix of sources. 58 uses 350 kW per tractor, a factor-of-ten slip (20,000/350 = 57.1); 1715 adds the existing 2.0 kW/ha to the target (60,000/35).

7 · Farm power availability (kW/ha) · medium

Custom hiring centres (machinery banks) mainly raise the farm power effectively available to smallholders by:

  1. Increasing the rated power of each tractor through engine upgrades at the centre
  2. Replacing all draught animals by law so that farmers must hire the centre's machines
  3. Letting many farmers use machines they could not justify owning, when they need them
  4. Lowering the calorific value of diesel
Answer and working

C. Letting many farmers use machines they could not justify owning, when they need them

Hiring spreads fixed costs over more farms and hours, improving access and timeliness without each farmer buying a machine. It does not change machine ratings.

8 · Mechanisation indices · medium

Two reports give very different 'levels of mechanisation' for the same state. What should you check first?

  1. Which report used the larger number of tractors
  2. Which report was published later, since later figures are always correct
  3. Whether the reports used kW or hp (metric or imperial), since that alone explains any difference
  4. The definition used (power share, operation-wise area, energy share or stock) and the area and data year
Answer and working

D. The definition used (power share, operation-wise area, energy share or stock) and the area and data year

There is no single agreed index: power-based, operation-based, energy-based and stock-based measures can differ widely. Compare like with like on definition, area basis and year before judging.

9 · Mechanisation indices · medium

Operation-wise mechanisation data show tillage and threshing almost fully mechanised, but rice transplanting and cotton picking largely manual. What use is this for policy?

  1. It shows that the district is fully mechanised and needs no further support
  2. It proves that kW/ha is the only measure that matters
  3. It identifies the operations where research, machinery development and subsidy will do most to raise the overall level
  4. It shows tractors should be removed from tillage
Answer and working

C. It identifies the operations where research, machinery development and subsidy will do most to raise the overall level

An overall index hides gaps. Operation-wise figures show bottlenecks such as transplanting and harvesting where targeted interventions pay off.

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Read the subject

Farm Power SourcesThe full study manual, free ASRB NETFormat, sections and how it has changed

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Farm Power Sources for other exams

ICAR AIEEA-PG · IndiaGATE · IndiaAgricultural and Biosystems Engineers Licensure Examination · PhilippinesRajasthan PSC · India

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