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ASRB NET Post-Harvest Engineering of Cereals, Pulses & Oilseeds: practice questions

ASRB NET — Farm Machinery & Power / Land & Water Management Engineering / Agricultural Structures & Process Engineering · India · Agricultural Scientists Recruitment Board (ICAR)

Original practice questions written to the published syllabus · not past papers
10worked here, free
54written to this exam in this subject
12syllabus units

What this subject covers

Moisture, drying, parboiling, milling, cleaning, size reduction and conveying of grains, pulses and oilseeds.

In the exams: GATE AG Section 6 (~14 marks a year 2019–26; psychrometry in all 8 papers, rice milling in 6 of 8); ICAR AIEEA-PG Unit VI; ICAR AICE subject 41; NCEES PE processing; PRC ABE bioprocess; ASRB NET ASPE

What ASRB NET asks from it

ASRB NET — Agricultural Structures & Process Engineering

Post-harvest operations, engineering properties, process equipment design and material handling at PG level, with emphasis on Indian practice: LSU and recirculating dryers, hot-soak parboiling, rubber-roll and disc huskers, dhal milling pretreatments, expellers and solvent plants.

Where the 54 questions fall

How our questions for ASRB NET spread across the units of Post-Harvest Engineering of Cereals, Pulses & Oilseeds. Difficulty: 17 easy, 29 medium, 8 hard.

Seed processing8
Equilibrium moisture content and sorption isotherms6
Pulse milling6
Oil expression and solvent extraction6
Grain dryers: bin, LSU, recirculating, fluidised-bed and solar5
Paddy and rice milling: husking, whitening, polishing and yields5
Parboiling and hydrothermal treatment4
Cleaning, grading and screening effectiveness4
Drying theory: constant and falling rate periods3
Wheat milling3
Moisture content: wet and dry basis2
Conveying: belt, bucket, screw and pneumatic2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Moisture content: wet and dry basis · medium

How much water must be added to 500 kg of wheat at 11% wet-basis moisture to temper it to 16% wet basis?

  1. 25.0 kg
  2. 22.3 kg
  3. 28.1 kg
  4. 29.8 kg
Answer and working

D. 29.8 kg

Dry matter = 500 × 0.89 = 445 kg. Final mass = 445/0.84 = 529.76 kg, so water to add = 29.8 kg. 25 kg (5% of 500) ignores that the total mass grows as water is added; 28.1 kg divides by the initial rather than the final (1 − M). 22.3 kg multiplies the dry matter by the 5-point rise (445 × 0.05).

Further reading: Sahay and Singh, Unit Operations of Agricultural Processing

2 · Moisture content: wet and dry basis · easy

A capacitance-type grain moisture meter works mainly because

  1. wet grain has a higher bulk density
  2. water has a much higher dielectric constant than dry grain matter
  3. wet grain absorbs near-infrared light
  4. water conducts electricity far better than dry grain, so resistance falls
Answer and working

B. water has a much higher dielectric constant than dry grain matter

Capacitance meters measure the dielectric constant (permittivity) of the sample; water's permittivity is far higher than that of dry matter. Conduction is the principle of resistance meters, and NIR absorption is a different instrument.

Further reading: Chakraverty, Post Harvest Technology of Cereals, Pulses and Oilseeds

3 · Drying theory: constant and falling rate periods · hard

A tray holds 50 kg of dry solid on 2 m² and dries at a constant rate R_c = 1.5 kg/m²·h down to the critical moisture X_c = 0.6 (db); the rate then falls linearly to zero at X_e = 0.05. The falling-rate time from 0.6 to 0.15 kg/kg (db) is closest to

  1. 15.6 h
  2. 25.6 h
  3. 9.2 h
  4. 12.7 h
Answer and working

A. 15.6 h

t_f = [W_s(X_c − X_e)/(A R_c)] ln[(X_c − X_e)/(X − X_e)] = (50 × 0.55/3) × ln(0.55/0.10) = 9.167 × 1.7047 = 15.63 h. Dropping the log term gives 9.2 h; using total rather than free moisture in the log gives 12.7 h; 25.6 h is the total including the constant-rate period.

Further reading: Earle, Unit Operations in Food Processing

4 · Grain dryers: bin, LSU, recirculating, fluidised-bed and solar · easy

The LSU dryer is best described as a

  1. rotary drum dryer heated through its shell
  2. continuous mixed-flow column dryer with alternate rows of inverted-V inlet and outlet ducts
  3. fluidised-bed dryer with a porous distributor plate
  4. batch in-bin dryer with a fully perforated floor and vertical stirring augers moving through the grain
Answer and working

B. continuous mixed-flow column dryer with alternate rows of inverted-V inlet and outlet ducts

Grain flows down by gravity past rows of inverted-V channels connected alternately to the hot-air plenum and the exhaust, and a fluted discharge roll sets the flow rate.

Further reading: Chakraverty, Post Harvest Technology of Cereals, Pulses and Oilseeds

5 · Parboiling and hydrothermal treatment · easy

Wheat is conditioned (tempered) with water before milling chiefly to

  1. reduce the protein content of the endosperm before flour is extracted
  2. gelatinise the starch
  3. kill stored-grain insects
  4. toughen the bran and mellow the endosperm so they separate cleanly
Answer and working

D. toughen the bran and mellow the endosperm so they separate cleanly

Toughened bran stays in large flakes and mellowed endosperm reduces easily with less energy. Conditioning does not gelatinise starch; that is parboiling.

Further reading: Posner and Hibbs, Wheat Flour Milling

6 · Pulse milling · easy

Dhal milling of pulses consists essentially of

  1. parboiling and polishing the whole seed
  2. grinding the seed into flour
  3. extracting oil from the cotyledons
  4. dehulling the seed and splitting it into cotyledons
Answer and working

D. dehulling the seed and splitting it into cotyledons

Dhal is the dehulled, usually split, cotyledon; flour and oil are different products.

Further reading: Chakraverty, Post Harvest Technology of Cereals, Pulses and Oilseeds

7 · Pulse milling · easy

Commercial dhal recovery falls short of the theoretical yield mainly because

  1. moisture is lost during pretreatment
  2. the cotyledons are sold as seed
  3. the husk regrows on the cotyledons during storage and must be removed a second time
  4. abrasion removes cotyledon as powder and produces brokens along with the husk
Answer and working

D. abrasion removes cotyledon as powder and produces brokens along with the husk

Abrasive dehullers cannot remove husk without also removing some cotyledon, and splitting creates brokens. Moisture change during pretreatment is balanced out when yields are corrected to the same moisture.

Further reading: Chakraverty, Post Harvest Technology of Cereals, Pulses and Oilseeds

8 · Oil expression and solvent extraction · easy

In solvent extraction of oilseeds, 'miscella' is

  1. the solution of oil in solvent leaving the extractor
  2. the solvent-free extracted meal
  3. the pressed cake before extraction
  4. the gums removed in degumming
Answer and working

A. the solution of oil in solvent leaving the extractor

Miscella is distilled to separate oil from solvent, which is condensed and reused. The meal goes to the desolventiser-toaster.

Further reading: Bailey's Industrial Oil and Fat Products

9 · Cleaning, grading and screening effectiveness · medium

To remove chaff and dust from grain with an aspirator, the air velocity should be set

  1. above the terminal velocity of the grain
  2. above the terminal velocity of light impurities but below that of the grain
  3. equal to the grain's terminal velocity
  4. below the terminal velocity of the impurities, so that no grain is ever lifted out
Answer and working

B. above the terminal velocity of light impurities but below that of the grain

Only particles whose terminal velocity is below the air velocity are lifted. Too high a velocity carries grain away; too low leaves the chaff.

Further reading: Sahay and Singh, Unit Operations of Agricultural Processing

10 · Seed processing · hard

By Harrington's rules of thumb, lowering seed moisture by 2 percentage points and storage temperature by 10 °C would multiply expected storage life by roughly

  1. 16
  2. 8
  3. 6
  4. 4
Answer and working

A. 16

Moisture: 2 × 2 = 4; temperature: each 5 °C fall doubles life, so 10 °C gives 4; combined 4 × 4 = 16. Adding the factors (4 + 4 = 8) is the common slip. 6 adds the moisture factor to a single temperature doubling (4 + 2).

Further reading: Harrington's rules for seed storage

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Read the subject

Post-Harvest Engineering of Cereals, Pulses & OilseedsThe full study manual, free ASRB NETFormat, sections and how it has changed

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Post-Harvest Engineering of Cereals, Pulses & Oilseeds for other exams

ICAR AIEEA-PG · IndiaGATE · IndiaICAR AICE-JRF/SRF · India

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