Nepal Engineering Council Registration Exam — Agricultural Engineering · Nepal · Nepal Engineering Council
Original practice questions written to the published syllabus · not past papersMoney and time in engineering decisions: discounting, costs, break-even, project appraisal, scheduling and starting a business.
In the exams: NCEES FE Engineering Economics 6–9 questions; NCEES PE engineering economics and project management; ICAR AICE subject 41 Unit 10; PRC ABE project management
How our questions for Nepal Engineering Council Registration Exam spread across the units of Engineering Economics, Project & Business Management. Difficulty: 26 easy, 28 medium, 8 hard.
| Entrepreneurship and marketing | 16 | |
| CPM and PERT | 11 | |
| Project appraisal and detailed project reports | 7 | |
| NPV, IRR, benefit-cost ratio and payback | 5 | |
| Linear programming | 5 | |
| Time value of money | 4 | |
| Fixed and variable costs | 4 | |
| Break-even analysis | 4 | |
| Depreciation methods | 3 | |
| Replacement analysis | 3 |
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
How does depreciation affect the cash flow of a profitable business?
A. It is not itself a cash flow, but it lowers taxable income and therefore the tax paid
Cash leaves when the asset is bought; depreciation only allocates that cost over time. Because tax law allows it as a deduction, it reduces taxable income and tax, so its cash effect is the tax saving, depreciation × tax rate.
An electric pump set has annual fixed costs of 60,000 and running cost 15 per hour; a diesel set has fixed costs of 20,000 and running cost 55 per hour. Which statement is correct?
B. The electric set is cheaper for any use above 1,000 hours of pumping a year
Equal annual cost: 60,000 + 15h = 20,000 + 55h, so h = 40,000/40 = 1,000 h. Above that, the electric set's lower running cost outweighs its higher fixed cost; below it, diesel is cheaper. Any first costs should be converted to annual amounts with the capital recovery factor before this comparison.
A processing plant has 500 lamps that fail at random. Replacing a lamp individually after failure costs much more per lamp than replacing all lamps together. Under the standard group-replacement rule, when should all lamps be replaced?
D. At the end of period t if individual replacements in period t + 1 would cost more than the average cost per period up to t
Group replacement trades away the remaining life of working lamps for a lower cost per lamp and fewer emergency replacements. The best interval minimises average cost per period; the rule stated finds that interval. Replacing every period ignores that working lamps are discarded too often.
In the economic (as opposed to financial) analysis of an irrigation project, how is a government subsidy on pump sets treated?
C. It is excluded as a transfer, and pump sets are valued at their economic cost
Taxes, subsidies and loan transactions move purchasing power between groups without using real resources, so economic analysis removes them and values inputs at their economic or shadow prices. The financial analysis, from the farmer's viewpoint, does include the subsidy.
Which item is normally part of the 'cost of project' in a detailed project report for a food-processing unit?
C. Margin money for working capital, the promoter's share of the working capital needed
The cost of project covers land, buildings, plant and machinery, preliminary and pre-operative expenses, contingencies and margin money for working capital. Raw material, interest and salaries during operation are operating costs shown in the profitability projections, not capital cost.
A project protected by import duties shows a financial IRR of 18 % but an economic IRR of 6 %. What does this most directly suggest?
C. That protection makes it pay its owner while it uses resources inefficiently for society
Financial and economic IRRs differ when market prices differ from economic values. Protection raises the price the owner receives above the border price, inflating financial returns; at border prices the project earns little. Neither rate must exceed the other in general.
To shorten a project by one day at least cost, which activity should be crashed first: critical activity P (cost slope 4,000 per day), critical activity Q (2,500 per day), critical activity R (6,000 per day) or non-critical activity S (1,000 per day)?
D. Q, the critical activity with the lowest cost slope
Only shortening a critical activity reduces project duration; crashing S spends money and saves nothing. Among critical activities, crash the one with the lowest cost slope first, then recompute the critical path because another path may become critical.
What does resource levelling do in project scheduling?
D. It uses the float of non-critical activities to smooth daily resource demand
Levelling uses the float of non-critical activities to reduce peaks and valleys in resource use without extending the project. Shortening critical activities with extra resources is crashing. If resources are too few even after levelling, resource-constrained scheduling extends the project.
In a transportation problem, total supply from the depots is 900 t and total demand at the markets is 750 t. What is done before solving?
A. Add a dummy market with a demand of 150 t and zero transport cost
Supply exceeds demand by 150 t, so a dummy destination with demand 150 t and zero cost absorbs the surplus; goods 'shipped' to it are simply not shipped. A dummy source is used when demand exceeds supply.
Which method for an initial transportation solution uses penalties, the difference between the two lowest costs in each row and column?
A. Vogel's approximation method
Vogel's method allocates first to the row or column with the largest penalty, which gives a starting solution close to optimal. The north-west corner rule ignores costs; MODI and stepping-stone are used to test and improve a solution, not to start one.
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