ICAR AICE-JRF/SRF (PhD) — Agricultural Engineering subjects 38–43 · India · National Testing Agency for ICAR
Original practice questions written to the published syllabus · not past papersAquifers, well hydraulics, well design and the pumps that lift the water — asked in some form in every GATE AG paper.
In the exams: GATE AG Section 5 (well hydraulics in 7 of 8, pumps in 5 of 8 papers 2019–26); ICAR AIEEA-PG Unit VII; ICAR AICE subjects 40 and 43; NCEES PE pumps; IA CID pumps 15–20%; RPSC AAE
ICAR AICE-JRF/SRF (PhD) — subjects 40 and 43
PG-depth concepts: leaky and unconfined (delayed-yield) aquifer responses, image-well theory, step-drawdown analysis and well efficiency, equivalence in resistivity sounding, recharge estimation methods and their assumptions, managed aquifer recharge, and groundwater assessment frameworks.
How our questions for ICAR AICE-JRF/SRF spread across the units of Groundwater, Wells & Pumps. Difficulty: 0 easy, 6 medium, 9 hard.
| Unsteady flow: Theis and Cooper-Jacob | 2 | |
| Recharge estimation and artificial recharge | 2 | |
| Specific speed and affinity laws | 2 | |
| Aquifer types and properties: T, S and Sy | 1 | |
| Darcy's law in aquifers | 1 | |
| Steady flow to wells: Thiem and Dupuit | 1 | |
| Pumping tests | 1 | |
| Well interference | 1 | |
| Well design: screen and gravel pack | 1 | |
| Groundwater exploration: resistivity | 1 | |
| NPSH and cavitation | 1 | |
| Solar pumping | 1 |
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
A clay has a porosity of 0.45 while a medium sand has a porosity of 0.32, yet the sand is the far better aquifer. The best explanation is:
C. Clay holds most pore water against gravity, so its specific yield and conductivity are very low
Fine pores hold water by surface tension and adsorption: specific retention is high and specific yield small, and the tiny pores give very low K. Porosity alone does not measure how much water an aquifer yields.
The same sand column is tested with water at 10 °C and then at 30 °C. Compared with the first test, the second test gives:
D. Higher hydraulic conductivity, same intrinsic permeability
K = kρg/μ. Warm water has lower viscosity, so K rises; k depends only on pore geometry and is unchanged.
A step-drawdown test yields s_w = BQ + CQ² with B = 1.2 × 10⁻³ day/m² and C = 2.0 × 10⁻⁷ day²/m⁵. At Q = 2,000 m³/day, the well efficiency is:
C. 75%
Aquifer loss BQ = 2.4 m, well loss CQ² = 0.8 m, s_w = 3.2 m. Efficiency = BQ/s_w = 2.4/3.2 = 75%. 25% is the well-loss fraction; 300% is the ratio of the two losses.
On a Cooper-Jacob plot for an observation well, the slope of drawdown against log time doubles part way through a test. The most likely cause is:
D. An impermeable (barrier) boundary within the cone of depression
When a barrier's influence arrives, an image pumping well adds an equal drawdown rate, doubling the semilog slope. Recharge boundaries and leakage flatten the curve; delayed yield also flattens it temporarily.
A well is to be completed in a fine, very uniform sand (Cu ≈ 1.5). The most appropriate design approach is:
C. Install an artificial pack of uniform, rounded siliceous grains, with slots retaining most of the pack
Fine uniform sands cannot form a natural graded filter because there is no coarse fraction to retain. An artificial pack, graded by pack-aquifer ratio, with slot retaining most of the pack, stabilises the formation.
In interpreting a VES, a thin conductive layer between two resistive layers can be resolved only in terms of its longitudinal conductance. This ambiguity is known as:
C. The principle of equivalence
Equivalence: different thickness-resistivity pairs with the same h/ρ (conductive layer) or h×ρ (resistive layer) produce the same curve. Suppression refers to an intermediate-resistivity thin layer that does not show at all.
Annual rainfall is 800 mm with chloride 2 mg/L (including dry deposition). Groundwater chloride is 40 mg/L and there are no other chloride sources. By chloride mass balance the recharge is:
C. 40 mm/year
R = P × Cl_p/Cl_gw = 800 × 2/40 = 40 mm/year. Inverting the ratio gives 16,000 mm; the method fails if fertiliser, irrigation water or evaporites add chloride. 400 mm/year is a factor-of-ten slip.
Geometrically similar pumps operating at corresponding (similar) points have:
B. The same specific speed
Specific speed combines N, Q and H so that it stays constant under similarity scaling; it characterises the impeller shape, not the size.
A pump with Thoma cavitation coefficient σ = 0.12 operates at 40 m head. Atmospheric minus vapour pressure head is 10.1 m and suction losses are 0.5 m. Ignoring any safety margin, the maximum static suction lift is:
A. 4.8 m
NPSHr = σH = 0.12 × 40 = 4.8 m. Require 10.1 − z − 0.5 ≥ 4.8, so z ≤ 4.8 m. Ignoring NPSHr or the suction losses overstates the lift. 9.6 m ignores NPSHr; 5.3 m ignores the suction losses; 5.8 m adds the losses instead of subtracting them.
Researchers have raised concern that subsidised off-grid solar pumps may accelerate groundwater depletion. The underlying reason is that:
C. Pumping has near-zero marginal cost once installed, so there is little incentive to limit extraction
After capital cost, energy is free; without volumetric limits farmers may pump more. Grid-connected designs that pay for surplus power have been proposed partly to reward pumping less.
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