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ICAR AICE-JRF/SRF Watershed Planning & Management: practice questions

ICAR AICE-JRF/SRF (PhD) — Agricultural Engineering subjects 38–43 · India · National Testing Agency for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
56written to this exam in this subject
10syllabus units

What this subject covers

Planning a whole watershed: delineating it, classifying its land, budgeting its water and choosing harvesting structures with the people who live there.

In the exams: GATE AG Section 4 Watershed Management; ICAR AIEEA-PG Unit VII; ICAR AICE subject 40 Unit 6; TNPSC Unit III; RPSC AAE Unit 2

What ICAR AICE-JRF/SRF asks from it

ICAR AICE-JRF/SRF (PhD) — subject 40 Soil and Water Conservation Engineering

Unit 6 watershed management at PG depth: prioritisation methods (compound parameter, sediment yield index, multi-criteria), hypsometric analysis, participatory institutions, evaluation design, economic analysis and the Common Guidelines.

Where the 56 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Watershed Planning & Management. Difficulty: 3 easy, 30 medium, 23 hard.

Watershed characterisation and morphometry10
Cost-benefit analysis of watershed projects8
Participatory watershed planning7
Watershed delineation5
Land capability classification5
Land irrigability classification5
Rainwater harvesting: check dams, percolation tanks and farm ponds5
Water budgeting4
National watershed programmes4
Roof-top rainwater harvesting3

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Watershed characterisation and morphometry · medium

The highest point on the divide of a watershed is at 1240 m and the outlet at 580 m. The basin length is 16.5 km. The relief ratio (dimensionless) is:

  1. 40.0
  2. 0.040
  3. 0.075
  4. 0.035
Answer and working

B. 0.040

Basin relief H = 1240 − 580 = 660 m. Rh = H / Lb = 660 / 16,500 m = 0.040. 40.0 is H in metres divided by Lb in kilometres, a unit slip. Using the highest elevation (0.075) or the outlet elevation alone (0.035) instead of the difference is wrong.

Further reading: Horton (1945); Strahler (1957); Schumm (1956); Miller (1953) — as summarised in Suresh, Soil and Water Conservation Engineering

2 · Watershed characterisation and morphometry · hard

A watershed has minimum elevation 580 m, maximum elevation 1240 m and mean elevation 820 m. Using the elevation-relief ratio to approximate the hypsometric integral, which is correct?

  1. HI ≈ 0.36, indicating a youthful (inequilibrium) stage
  2. HI ≈ 0.66, indicating a youthful (inequilibrium) stage
  3. HI ≈ 0.71, indicating a youthful (inequilibrium) stage
  4. HI ≈ 0.36, within Strahler's mature (equilibrium) range
Answer and working

D. HI ≈ 0.36, within Strahler's mature (equilibrium) range

E = (mean − min) / (max − min) = (820 − 580) / (1240 − 580) = 240/660 = 0.364. Strahler read values above about 0.6 as youthful (inequilibrium), about 0.35–0.6 as mature (equilibrium) and lower values as old (monadnock), so 0.36 is mature. 0.66 (mean ÷ max) is not the hypsometric integral; the interpretation is qualitative and also depends on lithology and tectonics.

Further reading: Strahler (1952, 1957); Pike and Wilson (1971) elevation-relief ratio

3 · Watershed characterisation and morphometry · hard

A 2,000 ha sub-watershed has three erosion intensity mapping units: 600 ha (weightage 17, delivery ratio 0.9), 900 ha (weightage 14, delivery ratio 0.8) and 500 ha (weightage 11, delivery ratio 0.7). Using SYI = [Σ(Ai × Wi × Di) / Aw] × 100 and the bands very high > 1300, high 1200–1300, medium 1100–1200, low 1000–1100, very low < 1000, the sediment yield index and priority are:

  1. 1,415 — very high
  2. 1,156 — very high
  3. 1,156 — medium
  4. 11.6 — very low
Answer and working

C. 1,156 — medium

Σ(Ai × Wi × Di) = 600×17×0.9 + 900×14×0.8 + 500×11×0.7 = 9,180 + 10,080 + 3,850 = 23,110. SYI = 23,110 / 2,000 × 100 = 1,155.5, which falls in the medium band (1100–1200). Leaving out the delivery ratio gives 1,415 and a false 'very high'; forgetting the factor 100 gives 11.6.

Further reading: AIS&LUS (Soil and Land Use Survey of India) priority delineation methodology

4 · Land irrigability classification · easy

In the US Bureau of Reclamation (USBR) land classification for irrigation, land classes 1, 2 and 3 are:

  1. non-arable classes pending further study
  2. arable classes of decreasing suitability for irrigated farming
  3. classes of increasing suitability, with class 3 the best
  4. classes based only on water quality
Answer and working

B. arable classes of decreasing suitability for irrigated farming

Classes 1, 2 and 3 are arable, with class 1 the most suitable and class 3 restricted. Class 4 is limited arable or special use, class 5 non-arable pending further study and class 6 non-arable.

Further reading: USBR land classification

5 · Water budgeting · hard

In a nearly closed river basin, where downstream users already use most of the flow, an upstream programme builds many new check dams and farm ponds. From a basin water budget perspective, the most likely effect is:

  1. a net increase in basin water supply equal to the storage created
  2. no change to downstream flows because check dams only recharge groundwater, which never reaches the river
  3. a reallocation of water from downstream to upstream users rather than a net creation of new water
  4. a reduction in basin evapotranspiration
Answer and working

C. a reallocation of water from downstream to upstream users rather than a net creation of new water

Harvesting structures capture runoff that would otherwise have flowed downstream; recharged water is then pumped and evapotranspired upstream. In a closed basin this shifts water between users. Storage created is not new supply, and increased irrigation upstream usually raises basin evapotranspiration.

Further reading: Brooks, Ffolliott and Magner, Hydrology and the Management of Watersheds

6 · Rainwater harvesting: check dams, percolation tanks and farm ponds · hard

A percolation tank has an average water-spread area of 2.0 ha and an average stored depth of 1.5 m. It fills 3 times in the rainy season, and evaporation takes 20% of the water captured. Assuming all remaining water percolates, the seasonal recharge is:

  1. 90,000 m³
  2. 24,000 m³
  3. 72,000 m³
  4. 18,000 m³
Answer and working

C. 72,000 m³

One filling = 20,000 m² × 1.5 m = 30,000 m³. 3 fillings = 90,000 m³. Recharge = 90,000 × (1 − 0.2) = 72,000 m³. 90,000 m³ ignores evaporation; 24,000 m³ counts only one filling; 18,000 m³ is the evaporation loss.

7 · Roof-top rainwater harvesting · hard

In the mass-curve (supply-side) method of sizing a rainwater tank, the required storage is found from:

  1. the maximum difference between the cumulative supply and demand curves during the period when demand exceeds supply
  2. the total annual roof yield
  3. the largest single monthly rainfall
  4. the product of the household's daily demand and the number of rainy days in the wettest year on the rainfall record
Answer and working

A. the maximum difference between the cumulative supply and demand curves during the period when demand exceeds supply

Plotting cumulative roof yield and cumulative demand month by month, the storage needed is the largest gap that must be carried over from surplus months to cover deficit months. Total annual yield sets the upper limit on supply but is not the tank size; the demand-side method uses dry days, not rainy days.

Further reading: Gould and Nissen-Petersen, Rainwater Catchment Systems for Domestic Supply

8 · Participatory watershed planning · medium

A Venn (chapati) diagram exercise in PRA shows:

  1. the seasonal pattern of rainfall, crop operations and labour demand through the year, month by month
  2. the location of eroded land and gullies
  3. the institutions that matter to villagers and how important and accessible each one is
  4. the cross-section of a check dam
Answer and working

C. the institutions that matter to villagers and how important and accessible each one is

Circles of different sizes represent institutions (importance) and their distance from a central circle representing the community shows accessibility. Seasonal patterns are shown on a seasonal calendar; eroded land on a resource map.

9 · Participatory watershed planning · medium

'Social fencing' in watershed management refers to:

  1. a physical fence built with community labour
  2. fencing of private fields by the richest farmers
  3. protection of treated or closed areas through rules agreed and enforced by the community itself
  4. a law passed by the state prohibiting grazing on treated land, enforced by the forest guards and police
Answer and working

C. protection of treated or closed areas through rules agreed and enforced by the community itself

Social fencing means the community agrees not to graze or cut in a regenerating area and enforces the rule itself, often with fines or watchers it appoints, instead of relying on physical fences or state orders that are hard to enforce.

10 · National watershed programmes · medium

China's Sloping Land Conversion Programme ('Grain for Green'), launched in 1999, aimed to:

  1. expand rice cultivation onto steep hillsides
  2. build large hydropower dams in the upper Yangtze to replace hill farming
  3. resettle all hill farmers to cities
  4. pay farmers to convert steep sloping cropland to forest or grassland
Answer and working

D. pay farmers to convert steep sloping cropland to forest or grassland

Grain for Green compensated farmers with grain and cash for converting steep, erodible cropland to trees or grass, to reduce erosion and flooding. It is one of the largest land-use conversion programmes in the world.

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Read the subject

Watershed Planning & ManagementThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

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Watershed Planning & Management for other exams

ICAR AIEEA-PG · IndiaTamil Nadu PSC · IndiaASRB NET · IndiaGATE · IndiaRajasthan PSC · India

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