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ICAR AICE-JRF/SRF Instrumentation, Sensors & Process Control: practice questions

ICAR AICE-JRF/SRF (PhD) — Agricultural Engineering subjects 38–43 · India · National Testing Agency for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
69written to this exam in this subject
11syllabus units

What this subject covers

Measuring temperature, pressure, flow, force and moisture, logging the data, and controlling processes automatically.

In the exams: ICAR AICE subjects 38 (Unit 7), 39 (Unit 8) and 41 (Unit 9); NCEES PE sensors and data acquisition; NCEES FE 4–6 questions

What ICAR AICE-JRF/SRF asks from it

ICAR AICE-JRF/SRF (PhD) — Dairy Engineering (Unit 7), Farm Machinery and Power Engineering (Unit 8), Processing and Food Engineering (Unit 9)

Definitions of static and dynamic characteristics; working principles of RTDs, thermistors, thermocouples, strain gauges, load cells, flow meters and moisture meters; bridge circuits; control modes and PID terms; short calculations on time constants, gauge factor, bridge output and moisture basis.

Where the 69 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Instrumentation, Sensors & Process Control. Difficulty: 20 easy, 32 medium, 17 hard.

Control modes: on-off, P, PI and PID14
Static and dynamic characteristics of instruments9
Moisture measurement9
Temperature transducers8
Force, torque and strain: strain gauges and load cells7
Pressure, flow and level measurement6
The generalised measurement system5
Signal conditioning3
Data acquisition and data loggers3
Programmable logic controllers3
IoT sensor networks2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · The generalised measurement system · easy

In the generalised measurement system, which functional element changes the magnitude of a signal without changing its physical nature?

  1. The variable-manipulation element, for example an amplifier raising a millivolt signal to volts
  2. The variable-conversion element, for example a diaphragm turning pressure into a displacement
  3. The primary sensing element, for example a thermocouple junction responding to temperature
  4. The data-presentation element, for example a chart recorder or digital display showing the value
Answer and working

A. The variable-manipulation element, for example an amplifier raising a millivolt signal to volts

Variable manipulation changes size, not kind: an amplifier makes a small voltage into a larger voltage. Variable conversion changes the kind of signal (pressure to displacement), the primary element senses the measurand, and the presentation element shows or stores the result.

2 · The generalised measurement system · easy

Which of these transducers is self-generating (active), producing an output without any external excitation supply?

  1. A platinum resistance thermometer, whose resistance rises steadily with the temperature
  2. A bonded foil strain gauge, whose resistance changes when the surface it is glued to strains
  3. A thermocouple, which produces an emf from the temperature difference between its junctions
  4. A capacitive polymer humidity sensor, whose capacitance changes as the polymer absorbs water
Answer and working

C. A thermocouple, which produces an emf from the temperature difference between its junctions

A thermocouple generates its own emf by the Seebeck effect. RTDs, strain gauges and capacitive sensors are passive: their resistance or capacitance changes, and an excitation voltage or current is needed to turn that change into a signal.

3 · The generalised measurement system · medium

Sixteen repeated readings of soil temperature have a standard deviation of 0.8 °C. What is the standard error of their mean?

  1. 0.05 °C
  2. 0.20 °C
  3. 0.80 °C
  4. 3.20 °C
Answer and working

B. 0.20 °C

Standard error = s/√n = 0.8/√16 = 0.8/4 = 0.20 °C. Dividing by n (0.05) overstates the benefit of averaging; 0.8 is the scatter of single readings, not of the mean; 3.2 multiplies by √n instead of dividing.

4 · Static and dynamic characteristics of instruments · medium

A thermometer with a first-order time constant of 10 s is moved from air at 20 °C into hot water at 80 °C. What does it read 15 s later?

  1. 57.9 °C
  2. 62.1 °C
  3. 33.4 °C
  4. 66.6 °C
Answer and working

D. 66.6 °C

y = 80 − (80 − 20)e^(−15/10) = 80 − 60 × 0.2231 = 66.6 °C. 57.9 °C is the reading at one time constant (10 s), 62.1 °C ignores the 20 °C starting point, and 33.4 °C adds the remaining fraction instead of the completed fraction.

5 · Temperature transducers · easy

What does the designation 'Pt100' on a resistance temperature detector mean?

  1. A platinum element whose resistance is 100 Ω at 100 °C
  2. A platinum element whose resistance is 100 Ω at 0 °C
  3. A platinum-coated thermocouple usable only up to 100 °C
  4. A platinum element with a 100 µV/°C output sensitivity
Answer and working

B. A platinum element whose resistance is 100 Ω at 0 °C

Pt100 is a platinum RTD with R0 = 100 Ω at 0 °C; at 100 °C it is about 138.5 Ω (α = 0.00385 /°C). It is a resistance device, not a thermocouple, and has no emf sensitivity.

6 · Temperature transducers · easy

Which thermocouple law allows a copper-wired voltmeter to be inserted into a thermocouple circuit without affecting the reading, provided both new junctions are at the same temperature?

  1. The law of intermediate temperatures
  2. The law of intermediate metals
  3. The law of homogeneous circuits
  4. The Peltier law of junction heating
Answer and working

B. The law of intermediate metals

The law of intermediate metals: a third metal inserted with both its junctions at the same temperature adds no net emf. The law of intermediate temperatures allows emfs over adjoining temperature intervals to be added; the homogeneous-circuit law says a single uniform wire produces no emf whatever its temperature gradient.

7 · Pressure, flow and level measurement · medium

An orifice meter gives 16 kPa differential at 40 L/s. If flow falls to 20 L/s, what differential will it show?

  1. 8 kPa
  2. 2 kPa
  3. 4 kPa
  4. 32 kPa
Answer and working

C. 4 kPa

Q ∝ √Δp, so Δp ∝ Q². Halving flow divides Δp by four: 16/4 = 4 kPa. 8 kPa assumes a linear relation, which is why obstruction meters have limited turndown. 2 kPa assumes Δp ∝ Q³; 32 kPa doubles instead of quartering.

8 · Signal conditioning · easy

What is the main advantage of the 'live zero' of 4 mA in a 4–20 mA signal from a field level transmitter?

  1. It lets the signal travel faster than a 0–20 mA signal over long cables
  2. It cancels the resistance of long cables, which a 0–20 mA loop cannot do
  3. A reading of 0 mA shows a broken wire or failed transmitter, not a zero level
  4. It doubles the measurement resolution of the analog-to-digital converter
Answer and working

C. A reading of 0 mA shows a broken wire or failed transmitter, not a zero level

With 4 mA as zero, any current well below 4 mA indicates a fault, and 4 mA can also power a two-wire transmitter. Immunity to cable resistance comes from current signalling in general, not from the live zero.

9 · Data acquisition and data loggers · medium

Why is a dual-slope (integrating) ADC favoured in precision digital voltmeters used near mains equipment?

  1. It converts in nanoseconds, so mains noise cannot change during the conversion
  2. It has the highest resolution available because it uses one comparator per step
  3. Integrating over a whole number of mains cycles averages out 50/60 Hz pick-up
  4. It needs no reference voltage, so drifts in the reference are of no concern
Answer and working

C. Integrating over a whole number of mains cycles averages out 50/60 Hz pick-up

A dual-slope converter integrates the input for a fixed time; if that time is a whole number of mains periods, the interference averages to zero. It is slow, not fast. One comparator per step is the flash converter, and the dual-slope method still uses a reference.

10 · Programmable logic controllers · medium

In a ladder-logic start/stop seal-in circuit for a conveyor motor, how are the stop button and the sealing contact arranged?

  1. Stop as a normally open contact in parallel with Start; the sealing contact in series with Stop
  2. Stop as a normally closed contact in series; the motor's normally open contact in parallel with Start
  3. Stop as a normally closed contact in parallel with Start; the sealing contact also wired as normally closed
  4. Stop and Start both normally open in series; the sealing contact in series with both of them
Answer and working

B. Stop as a normally closed contact in series; the motor's normally open contact in parallel with Start

The normally open output contact in parallel with Start keeps the coil energised after Start is released (seal-in). The normally closed Stop in series breaks the rung when pressed, and the circuit also drops out on power loss, so it does not restart unexpectedly.

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Read the subject

Instrumentation, Sensors & Process ControlThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

More ICAR AICE-JRF/SRF practice

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Instrumentation, Sensors & Process Control for other exams

NCEES PE Agricultural and Biological Engineering · USAICAR AIEEA-PG · IndiaNCEES FE Other Disciplines · USA

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