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ICAR AICE-JRF/SRF Applied Animal Nutrition I: Ruminants: practice questions

ICAR AICE-JRF/SRF (PhD) · India · NTA for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
29written to this exam in this subject
11syllabus units

About ICAR AICE-JRF/SRF

ICAR AICE-JRF/SRF (PhD) is a PhD, fellowship and lectureship exam run by NTA for ICAR, for candidates in India. Computer-based, 2 hours, 120 questions: Part A 20 (general agriculture, animal husbandry, current events), Part B 50 (core group), Part C 50 (specialised subject). +4 / -1, maximum 480.

Source: icar.org.in.

Checked against the exam body's published information. Formats and fees change; confirm the current edition there before you book.

Applied Animal Nutrition I: Ruminants in ICAR AICE-JRF/SRF

Deeper rumen manipulation (ionophores, protected nutrients, methane inhibitors, biohydrogenation and trans-10, cis-12 CLA), NE and MP systems (NRC, NASEM, INRA, ICAR 2013), DCAD calculation, LP concepts such as shadow prices, silage biochemistry and RFV, area-specific mineral mixture logic and clinical nutrition.

The rumen and how to feed cattle, buffalo, sheep and goats through each stage of life, including ration formulation by the Pearson square and least-cost methods.

Our 29 ICAR AICE-JRF/SRF questions in this subject: 0 easy, 12 medium, 17 hard, across 11 units.

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

These 10 were written to ICAR AICE-JRF/SRF and are not shown on any other exam's page.

Question 1 · medium

Butyrate produced by fermentation of calf starter is important for the young ruminant mainly because it:

  1. closes the oesophageal groove reflex when milk is fed
  2. stimulates growth and development of the rumen papillae
  3. provides the main substrate for lactose synthesis later
  4. inhibits methanogenic archaea and so spares rumen energy
Answer and working

B. stimulates growth and development of the rumen papillae

Butyrate (and to a lesser extent propionate) from fermentation of solid feed drives papillae development. The oesophageal groove closes by a suckling reflex, not by butyrate; lactose is made from glucose derived mainly from propionate.

Question 2 · medium

Why is cobalt deficiency in grazing ruminants expressed clinically as a vitamin B12 deficiency?

  1. Cobalt is the dietary vitamin precursor that the liver converts into B12 for later storage
  2. Rumen microbes need cobalt to make vitamin B12, cofactor in propionate metabolism
  3. Cobalt is needed by the abomasum to secrete intrinsic factor for absorbing dietary B12
  4. Cobalt blocks copper uptake, and the copper shortage then lowers the B12 stored in liver
Answer and working

B. Rumen microbes need cobalt to make vitamin B12, cofactor in propionate metabolism

Vitamin B12 (cobalamin) contains cobalt and is made only by microbes. In cobalt deficiency the rumen cannot make B12, so methylmalonyl-CoA mutase fails, propionate is poorly used and the animal wastes (pine). The liver does not make B12 itself.

Question 3 · medium

Which fatty acid intermediate of incomplete rumen biohydrogenation is accepted as a direct inhibitor of milk fat synthesis in the udder?

  1. cis-9, trans-11 conjugated linoleic acid
  2. vaccenic acid (trans-11 octadecenoic acid)
  3. stearic acid (octadecanoic acid)
  4. trans-10, cis-12 conjugated linoleic acid
Answer and working

D. trans-10, cis-12 conjugated linoleic acid

Under low-fibre or high-unsaturated-fat diets, biohydrogenation shifts to a pathway producing trans-10 isomers; trans-10, cis-12 CLA directly depresses mammary lipogenesis. cis-9, trans-11 CLA (rumenic acid) and vaccenic acid come from the normal pathway; stearic acid is the end product.

Question 4 · hard

Goats in a new region develop alopecia, goitre and poor growth on a diet rich in Leucaena leaves, whereas goats in another region on the same diet stay healthy. The best explanation is that the healthy goats:

  1. carry rumen bacteria that degrade DHP, the goitrogenic mimosine metabolite
  2. have been given iodine so the mimosine is chelated and excreted harmlessly
  3. lack the rumen enzymes that would convert the leaf tannins into toxins
  4. eat the leaves only in the dry season when the mimosine content is zero
Answer and working

A. carry rumen bacteria that degrade DHP, the goitrogenic mimosine metabolite

Mimosine is converted in the rumen to 3,4-DHP and 2,3-DHP, which are goitrogenic. Ruminants in some regions carry DHP-degrading bacteria (Synergistes jonesii), which can be transferred by rumen-fluid inoculation. Iodine does not chelate mimosine, and Leucaena leaves contain mimosine in all seasons.

Question 5 · hard

Using NEL (Mcal/kg) = 0.0929 × fat% + 0.0547 × protein% + 0.0395 × lactose%, what is the energy content of milk with 4.0 percent fat, 3.3 percent protein and 4.8 percent lactose?

  1. 0.74 Mcal/kg
  2. 0.37 Mcal/kg
  3. 1.12 Mcal/kg
  4. 0.55 Mcal/kg
Answer and working

A. 0.74 Mcal/kg

0.0929 × 4.0 = 0.372; 0.0547 × 3.3 = 0.181; 0.0395 × 4.8 = 0.190; total 0.74 Mcal/kg. 0.37 counts fat only; 0.55 omits lactose; 1.12 is not a sum of these terms.

Question 6 · hard

In modern metabolisable protein (MP) systems, MP is defined as:

  1. crude protein in the diet minus the protein lost as nitrogen in the faeces
  2. true protein absorbed in the intestine: microbial protein plus digestible RUP
  3. rumen-degradable protein plus non-protein nitrogen supplied in the ration
  4. crude protein in the diet multiplied by its biological value in growth trials
Answer and working

B. true protein absorbed in the intestine: microbial protein plus digestible RUP

MP is the true protein digested and absorbed in the small intestine, made up of microbial true protein and digestible undegradable dietary protein (plus a small endogenous fraction in some systems). CP minus faecal N is apparent digestible CP (DCP), an older measure.

Question 7 · hard

A sensitivity (ranging) analysis on a least-cost ration shows that groundnut cake stays in the solution only while its price is between 30 and 46 units per kg. If its price rises to 50 units, the program will most likely:

  1. keep the same amount of cake and cut the energy minimum to make up the cost
  2. replace some or all of it with another protein source and raise the ration cost
  3. keep the cake in the ration at the same level, since its CP content is fixed
  4. remove every other protein feed so that the cake share can rise to fill the gap
Answer and working

B. replace some or all of it with another protein source and raise the ration cost

Above the upper bound of its cost range, the feed leaves (or partly leaves) the optimal basis and is replaced by the next cheapest way to meet the constraints, at a higher total cost. Nutrient constraints are not relaxed by price changes.

Question 8 · hard

Mature cows in a herd weigh 650 kg. A heifer born at 40 kg is to reach 55 percent of mature weight by 15 months (456 days). What average daily gain is needed?

  1. 0.78 kg/day
  2. 1.50 kg/day
  3. 21.17 kg/day
  4. 0.70 kg/day
Answer and working

D. 0.70 kg/day

Target = 0.55 × 650 = 357.5 kg; gain needed = 357.5 − 40 = 317.5 kg; ÷ 456 days = 0.70 kg/day. 0.78 forgets birth weight; 21.17 kg/day divides by 15 months instead of 456 days; 1.50 kg/day would make the heifer fat.

Question 9 · medium

Lucerne and berseem are harder to ensile than maize because they have:

  1. high sugar content and very low buffering capacity
  2. high lignin content that blocks the lactic bacteria
  3. low water-soluble sugar and high buffering capacity
  4. low crude protein and too much starch in the leaves
Answer and working

C. low water-soluble sugar and high buffering capacity

Legumes are rich in protein and minerals that buffer acid, and low in WSC, so pH falls slowly; they are wilted and often given additives or mixed with cereals. Maize has high sugar and low buffering capacity.

Question 10 · hard

Dark brown silage with a tobacco-like smell has been heat-damaged. Which laboratory measure best quantifies the loss of protein availability?

  1. Water-soluble carbohydrate content
  2. Acid detergent insoluble nitrogen (ADIN)
  3. Neutral detergent soluble ash
  4. Silage pH measured on fresh sample (by electrode)
Answer and working

B. Acid detergent insoluble nitrogen (ADIN)

Heating causes Maillard reactions that bind protein to carbohydrate in an indigestible form recovered in the ADF fraction; ADIN measures it. pH and WSC do not quantify heat damage.

A study plan for Applied Animal Nutrition I: Ruminants in ICAR AICE-JRF/SRF

This plan follows where our questions actually fall, so the time goes where the marks are likely to be. It is our reading of the syllabus, not the exam body's weighting.

  1. First, the heavy units (52% of the 29 questions): Evaluation of silage and hay (4, 14%); Nutrient requirements and feeding standards (ICAR 2013, NRC and NASEM) (4, 14%); Rumen ecosystem and function (4, 14%); Least-cost ration formulation (3, 10%).

    Read the manual chapters for these first and do every worked question you can find on them.

  2. Then the middle band: Rumen manipulation (3, 10%); Area-specific mineral mixtures (2, 7%); Clinical nutrition (2, 7%); Feeding of dry animals (2, 7%).

    Aim for one sitting per unit, then mixed questions across them.

  3. Then the lighter units: Feeding of heifers (2, 7%); Ration formulation by the Pearson square (2, 7%); Feeding of calves (1, 3%).

    Learn the definitions, classifications and standard numbers; these units are more often recalled than worked.

  4. Leave time for the hard ones: Clinical nutrition (2 hard of 2), Ration formulation by the Pearson square (2 hard of 2), Feeding of calves (1 hard of 1).

    Come back to these after a first pass, untimed, and read every explanation, including for the options you rejected.

  5. Finish timed. Sit the subject as a timed set without notes, mark it, and send each wrong answer back to its unit above.

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