LAISHA
Open Laisha

ICAR AICE-JRF/SRF Milk & Milk Products Technology: practice questions

ICAR AICE-JRF/SRF (PhD) · India · NTA for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
26written to this exam in this subject
11syllabus units

About ICAR AICE-JRF/SRF

ICAR AICE-JRF/SRF (PhD) is a PhD, fellowship and lectureship exam run by NTA for ICAR, for candidates in India. Computer-based, 2 hours, 120 questions: Part A 20 (general agriculture, animal husbandry, current events), Part B 50 (core group), Part C 50 (specialised subject). +4 / -1, maximum 480.

Source: icar.org.in.

Checked against the exam body's published information. Formats and fees change; confirm the current edition there before you book.

Milk & Milk Products Technology in ICAR AICE-JRF/SRF

Deeper chemistry and process questions: casein micelle and kappa-casein cleavage, whey protein denaturation, heat-stable enzymes and UHT defects, D and z values, lactose crystallisation in condensed milk, WPNI, yield equations (Van Slyke), mass balance standardisation and HACCP application.

Milk composition and quality testing, adulteration, heat processing, indigenous and fermented dairy products, dairy standards, packaging and quality control.

Our 26 ICAR AICE-JRF/SRF questions in this subject: 0 easy, 13 medium, 13 hard, across 11 units.

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

These 10 were written to ICAR AICE-JRF/SRF and are not shown on any other exam's page.

Question 1 · hard

Which statement about the freezing point of milk is correct?

  1. It varies widely between cows because it follows the fat content of each cow's milk
  2. It falls further below zero when water is added to milk, which is exactly how cryoscopes detect watering
  3. It is set mainly by casein micelles, so it changes sharply when casein content changes
  4. It is nearly constant, around -0.52 to -0.54 degrees C, because it follows the osmotic pressure of blood
Answer and working

D. It is nearly constant, around -0.52 to -0.54 degrees C, because it follows the osmotic pressure of blood

Milk is isotonic with blood, so its freezing point depression is nearly constant and set by lactose and soluble salts. Added water raises it towards zero, not lower. Fat and colloidal casein contribute almost nothing to freezing point depression.

Question 2 · medium

Which fatty acid is characteristic of ruminant milk fat and underlies the Reichert-Meissl value?

  1. Linoleic acid (C18:2)
  2. Lauric acid (C12:0)
  3. Butyric acid (C4:0)
  4. Palmitic acid (C16:0)
Answer and working

C. Butyric acid (C4:0)

Butyric acid is found in useful amounts only in ruminant milk fat, and it is steam-volatile and water-soluble, which is what the RM value measures. Lauric acid is high in coconut oil; palmitic acid is abundant in milk fat but also in many other fats.

Question 3 · medium

A UHT process holds milk for 4 s at 140 degrees C. The target spore has D140 = 0.8 s. How many decimal reductions are achieved?

  1. 5
  2. 0.2
  3. 50
  4. 3.2
Answer and working

A. 5

Log reductions = time/D = 4/0.8 = 5. 3.2 is 4 x 0.8; 0.2 is 0.8/4; 50 misplaces the decimal in D (4/0.08).

Question 4 · medium

Why is sweetened condensed milk seeded with very fine lactose powder during cooling?

  1. To lower viscosity so the product pours easily from the can
  2. To supply nutrients that speed up the lactic fermentation
  3. To form many tiny lactose crystals so the product does not feel sandy
  4. To raise the sugar ratio above 64.5% and prevent mould growth
Answer and working

C. To form many tiny lactose crystals so the product does not feel sandy

Lactose is supersaturated in the cooled product; seeding creates many small crystals below the threshold of grittiness. It does not change the sucrose ratio.

Question 5 · hard

Why does ghee develop a granular texture when cooled slowly?

  1. High-melting glycerides crystallise slowly into large grains in liquid fat
  2. Residual casein particles act as grains that settle as the ghee cools
  3. Lactose crystallises out of the fat phase during slow cooling
  4. Residual moisture droplets freeze into small ice crystals inside the solid fat during slow cooling
Answer and working

A. High-melting glycerides crystallise slowly into large grains in liquid fat

Graininess is a fat crystallisation phenomenon; slow cooling favours large crystals of high-melting triglycerides. Ghee has almost no water, protein or lactose left.

Question 6 · medium

During churning of cream into butter, which change takes place in the emulsion?

  1. Casein micelles coagulate and trap the fat as a protein gel
  2. Water-in-oil emulsion of cream inverts to oil-in-water emulsion of butter
  3. Oil-in-water emulsion of cream inverts to water-in-oil emulsion of butter
  4. Fat globules melt completely and recrystallise as a single phase
Answer and working

C. Oil-in-water emulsion of cream inverts to water-in-oil emulsion of butter

Agitation breaks membranes, partly crystalline globules clump, and the phase inverts; buttermilk is released. Butter is not a protein gel.

Question 7 · hard

A cooperative wants to mechanise khoa production while keeping its traditional texture. Which equipment is most suited?

  1. A scraped-surface heat exchanger or conical vat with rotating scrapers
  2. A falling-film evaporator followed by a spray dryer, giving a free-flowing khoa powder
  3. A plate heat exchanger operated at 72 degrees C for 15 seconds
  4. A cheddaring machine followed by a mechanical press
Answer and working

A. A scraped-surface heat exchanger or conical vat with rotating scrapers

Khoa needs open-pan style concentration with constant scraping to prevent burning; scraped-surface and scraper-vat systems reproduce this. Spray drying gives powder, not khoa.

Question 8 · medium

What is the basis of the protocooperation between the two yoghurt bacteria?

  1. The lactobacillus makes diacetyl; the streptococcus converts diacetyl to acetaldehyde
  2. The streptococcus releases bacteriocins that kill phages attacking the lactobacillus
  3. The lactobacillus releases peptides and amino acids; the streptococcus supplies formic acid and CO2
  4. The streptococcus ferments only galactose while the lactobacillus ferments only glucose, producing ethanol and CO2
Answer and working

C. The lactobacillus releases peptides and amino acids; the streptococcus supplies formic acid and CO2

Proteolytic L. bulgaricus supplies amino acids to S. thermophilus, which supplies formic acid and CO2 to the lactobacillus; together they acidify faster than either alone.

Question 9 · hard

Using the Van Slyke formula, Y = (0.93F + C - 0.1) x 1.09 / (1 - W), estimate Cheddar yield per 100 kg milk with 3.6% fat, 2.5% casein and cheese moisture of 37%.

  1. About 9.9 kg
  2. About 16.9 kg
  3. About 10.4 kg
  4. About 6.3 kg
Answer and working

A. About 9.9 kg

0.93 x 3.6 = 3.348; + 2.5 - 0.1 = 5.748; x 1.09 = 6.265; / 0.63 = 9.94 kg. Dividing by 0.37 (moisture instead of 1 - W) gives 16.9 kg; 6.3 kg omits the moisture correction; 10.4 kg drops the 0.93 fat-recovery factor.

Question 10 · medium

What does an ATP bioluminescence swab of a cleaned surface detect?

  1. Mineral scale remaining after the acid step
  2. Detergent residues left after the final rinse
  3. Viable Listeria monocytogenes only, counted within a few minutes on the surface
  4. Organic residue from food soil and microbes, not specific organisms
Answer and working

D. Organic residue from food soil and microbes, not specific organisms

ATP comes from any biological material, so the swab checks cleanliness rapidly but cannot identify or count specific bacteria.

A study plan for Milk & Milk Products Technology in ICAR AICE-JRF/SRF

This plan follows where our questions actually fall, so the time goes where the marks are likely to be. It is our reading of the syllabus, not the exam body's weighting.

  1. First, the heavy units (54% of the 26 questions): UHT processing (5, 19%); Dahi and other fermented products (3, 12%); Dairy quality control (3, 12%); Ghee (3, 12%).

    Read the manual chapters for these first and do every worked question you can find on them.

  2. Then the middle band: Milk composition (3, 12%); Adulteration of milk (2, 8%); Milk quality tests (2, 8%); Pasteurisation (2, 8%).

    Aim for one sitting per unit, then mixed questions across them.

  3. Then the lighter units: Codex and national standards for dairy products (1, 4%); Dairy packaging (1, 4%); Paneer and khoa (1, 4%).

    Learn the definitions, classifications and standard numbers; these units are more often recalled than worked.

  4. Leave time for the hard ones: Pasteurisation (2 hard of 2), Dairy packaging (1 hard of 1), Paneer and khoa (1 hard of 1).

    Come back to these after a first pass, untimed, and read every explanation, including for the options you rejected.

  5. Finish timed. Sit the subject as a timed set without notes, mark it, and send each wrong answer back to its unit above.

Last updated · How Laisha writes and checks its pages · Report a mistake

Ask Laisha about this

Opens Laisha's chat with your question ready to send. Sign in or start free.

Unlock every question — ICAR AICE-JRF/SRF Milk & Milk Products Technology

US$10 a month · one price worldwide · cancel any time

  • Every practice question in this subject, with full working
  • Timed exam papers and progress by unit
  • Ask Laisha to explain any answer — up to 1,000 questions a month
Free or Smarter
FreeSmarter
Grow guides, pest pages, articlesRead allRead all
Ask Laisha5 a dayUp to 1,000 a month
Exam practiceThe sample on each pageEvery question, timed papers
Crop calendar and pest alerts—For your own fields
Calculators and tools—All
Uploads and reports—100 a month, real files
10 days free for every new account, no card.