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ICAR AICE-JRF/SRF Rheology & Texture of Dairy Foods: practice questions

ICAR AICE-JRF/SRF (PhD): Dairy Chemistry, Dairy Microbiology, Dairy Technology, Dairy Engineering · India · NTA for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
109written to this exam in this subject
11syllabus units

What this subject covers

Flow and deformation of milk, cream, yoghurt, cheese, butter and ice cream, and how instruments measure texture.

In the exams: ICAR AICE subject 37 Unit 5 and subject 38 Unit 1

Where the 109 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Rheology & Texture of Dairy Foods. Difficulty: 31 easy, 50 medium, 28 hard.

Newtonian and non-Newtonian fluids; power-law and Herschel-Bulkley models12
Stress, strain and rheological classification10
Viscometers and rheometers10
Mechanical models: Maxwell, Kelvin-Voigt and Burgers10
Dynamic oscillatory measurements10
Texture profile analysis10
Rheology of cheese, butter, yoghurt and ice cream10
Effect of processing and stabilisers on rheology10
Viscoelasticity: creep and stress relaxation9
Large deformation and fracture9
Relating instrumental and sensory texture9

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Newtonian and non-Newtonian fluids; power-law and Herschel-Bulkley models · medium

In an up-and-down shear-rate loop on a stirred yoghurt, what indicates thixotropy?

  1. The down-curve lies above the up-curve
  2. The down-curve lies below the up-curve
  3. The two curves coincide exactly at every shear rate
  4. The flow curve passes through the origin
Answer and working

B. The down-curve lies below the up-curve

Structure broken on the way up gives lower stress on the way down, so the down-curve lies below and encloses a hysteresis area. A down-curve above the up-curve indicates rheopexy; coincident curves mean no time dependence; passing through the origin only shows there is no yield stress.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

2 · Viscometers and rheometers · hard

For a power-law fluid with n = 0.5 in a tube viscometer, the Rabinowitsch-Mooney correction multiplies the apparent (Newtonian) wall shear rate by (3n + 1)/(4n). What is the factor?

  1. 1.25
  2. 0.80
  3. 1.00
  4. 0.625
Answer and working

A. 1.25

(3 × 0.5 + 1)/(4 × 0.5) = 2.5/2 = 1.25: the true wall shear rate is higher than 4Q/(πR³) for a shear-thinning fluid. 0.80 inverts the factor; 1.00 applies only when n = 1; 0.625 omits n in the denominator.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

3 · Viscometers and rheometers · medium

A plant's QC laboratory reports yoghurt viscosity with a single-spindle rotational viscometer. What must accompany each reading for it to be meaningful?

  1. Only the temperature of the sample
  2. The yoghurt's fat and protein contents
  3. Spindle, speed, temperature, time and sample handling
  4. The cone angle and the gap at the tip
Answer and working

C. Spindle, speed, temperature, time and sample handling

A single-point spindle reading is an apparent viscosity whose value depends on spindle geometry, speed, temperature, reading time and how the sample was stirred. Temperature alone is not enough; composition does not define the test; cone angle and gap apply to cone-and-plate instruments.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

4 · Viscoelasticity: creep and stress relaxation · medium

Why are creep and relaxation tests on dairy gels run at small deformation?

  1. To make the test finish in less time
  2. To stay within the linear viscoelastic region
  3. Because large stresses melt the fat phase
  4. To make the gel behave as a Newtonian fluid
Answer and working

B. To stay within the linear viscoelastic region

Inside the linear region the response is proportional to load and describes the intact material; larger deformations break bonds so results reflect damage. Small deformation does not shorten the test, does not affect fat melting, and does not turn a gel Newtonian.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

5 · Dynamic oscillatory measurements · medium

During a heating sweep, a cheese's tan δ rises from 0.3 at 20 °C to 1.2 at 70 °C. What has happened?

  1. It has become more elastic on heating
  2. It has changed from solid-like to liquid-like as it melted
  3. It has entered the shear-thickening region
  4. It has lost moisture and become brittle
Answer and working

B. It has changed from solid-like to liquid-like as it melted

tan δ above 1 means viscous response dominates, so the cheese has softened and begun to flow as fat melted and the protein network loosened. More elasticity would lower tan δ; shear-thickening is a steady-shear property; drying would stiffen, not liquefy, the cheese.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

6 · Rheology of cheese, butter, yoghurt and ice cream · medium

Butter softens noticeably when worked and partly regains firmness on standing. What is this called?

  1. Work softening
  2. Rheopexy
  3. Syneresis
  4. Cold agglutination
Answer and working

A. Work softening

Working breaks bonds in the fat crystal network, and some re-form at rest: work softening. Rheopexy is thickening under shear; syneresis is whey expulsion; cold agglutination is clustering of fat globules in cold raw milk.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

7 · Effect of processing and stabilisers on rheology · medium

Why is high-methoxyl pectin used in acidified milk drinks?

  1. It adsorbs to casein and prevents aggregation at low pH
  2. It forms a gel with calcium at neutral pH
  3. It lowers the viscosity of the drink to that of water
  4. It raises the pH to near neutral during storage
Answer and working

A. It adsorbs to casein and prevents aggregation at low pH

At acid pH the negatively charged pectin adsorbs onto positively charged casein and keeps particles apart by steric and charge repulsion, preventing sedimentation. Calcium gelling is a low-methoxyl pectin property; pectin raises rather than lowers viscosity; it does not change pH.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

8 · Effect of processing and stabilisers on rheology · medium

How does homogenisation of yoghurt milk change gel firmness?

  1. It reduces firmness by removing casein from the milk
  2. It has no effect because fat is outside the gel
  3. It increases firmness, as protein-coated globules join the network
  4. It reduces firmness by raising the pH at gelation
Answer and working

C. It increases firmness, as protein-coated globules join the network

Homogenised globules are coated with casein and whey protein and behave as active network particles. Casein is redistributed, not removed; fat does take part once coated; homogenisation does not change gelation pH.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

9 · Relating instrumental and sensory texture · easy

Perceived firmness of cheese on the first bite is most closely related to which instrumental measure?

  1. Compression hardness or fracture stress
  2. Kinematic viscosity of the whey
  3. Loss tangent of the cheese after melting
  4. Springiness alone
Answer and working

A. Compression hardness or fracture stress

First-bite firmness relates to the force needed to deform and fracture the sample. Whey viscosity and melt tan δ describe other states; springiness measures recovery, not firmness.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

10 · Dynamic oscillatory measurements · medium

In an oscillatory test, the stress of a purely viscous liquid is out of phase with the strain by:

  1. 90°
  2. 0°
  3. 45°
  4. 180°
Answer and working

A. 90°

Stress in a viscous liquid follows strain rate, which leads strain by 90°. 0° is a pure elastic solid; 45° is a material with equal G′ and G″; 180° does not occur in a passive material.

Further reading: Steffe, Rheological Methods in Food Process Engineering; Rao, Rheology of Fluid, Semisolid, and Solid Foods

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Rheology & Texture of Dairy FoodsThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

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