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ICAR AICE-JRF/SRF Fermentation Technology & Food Biotechnology: practice questions

ICAR AICE-JRF/SRF (PhD) — Food Processing Technology, Food Safety & Quality, Processing and Food Engineering · India · ICAR through the National Testing Agency

Original practice questions written to the published syllabus · not past papers
10worked here, free
51written to this exam in this subject
14syllabus units

What this subject covers

Microorganisms and enzymes put to work: starter cultures, the microbiology of fermented foods, industrial fermenter design and operation, downstream recovery, and the modern biotechnology (recombinant enzymes, precision fermentation, single-cell protein) that is reshaping ingredients.

In the exams: GATE XE-G and XL-U Section 2 (fermented foods and beverages); ICAR AICE 35.a Unit 6 (food microbiology and biotechnology)

Where the 51 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Fermentation Technology & Food Biotechnology. Difficulty: 8 easy, 31 medium, 12 hard.

Batch, fed-batch and continuous fermentation kinetics10
Fermenter design, aeration and agitation9
Downstream processing: separation and purification of fermentation products8
Recombinant DNA technology and GM foods4
Precision fermentation and its regulation4
Starter culture production, preservation and bacteriophage control3
Production of food enzymes, organic acids, amino acids and flavours by fermentation3
Lactic acid bacteria, yeasts and moulds as starter cultures2
Fermented dairy foods: curd, yoghurt and cheese microbiology2
Single-cell protein and single-cell oil2
Fermented vegetables: sauerkraut, kimchi and pickles1
Fermented cereal and legume foods: idli, dosa, tempeh, miso and soy sauce1
Fermented meat and fish products1
Vinegar fermentation1

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Lactic acid bacteria, yeasts and moulds as starter cultures · medium

Nisin, a bacteriocin used as a food preservative, is produced by which organism and acts mainly against which bacteria?

  1. Lactococcus lactis; Gram-positive bacteria including spore-formers
  2. Penicillium roqueforti; moulds and yeasts on cheese surfaces
  3. Streptococcus thermophilus; Gram-negative bacteria such as Salmonella
  4. Bacillus subtilis; all bacteria, Gram-positive and Gram-negative alike
Answer and working

A. Lactococcus lactis; Gram-positive bacteria including spore-formers

Nisin, a lantibiotic from some Lactococcus lactis strains, acts on the membranes of Gram-positive bacteria and inhibits outgrowth of spores of Clostridium and Bacillus. The outer membrane protects Gram-negative bacteria unless it is disrupted; nisin has no useful antifungal action.

Further reading: Hutkins, Microbiology and Technology of Fermented Foods

2 · Starter culture production, preservation and bacteriophage control · hard

Why does rotating starter strains help control phage in a plant?

  1. Rotation changes the pH of the milk, which inactivates phage
  2. Phage built up on one strain cannot attack the next
  3. New strains secrete enzymes that digest phage DNA in the whey
  4. Rotation lets the same strain rest and recover between uses
Answer and working

B. Phage built up on one strain cannot attack the next

Phages are usually host-specific; by alternating strains with different phage sensitivity, a phage population that rises against one strain finds no host in the next vats and declines. The other explanations are not the mechanism.

Further reading: Hutkins, Microbiology and Technology of Fermented Foods

3 · Fermented dairy foods: curd, yoghurt and cheese microbiology · medium

What causes the eyes and sweet nutty flavour of Swiss-type cheeses?

  1. Propionibacteria turning lactate into propionate, acetate and CO₂
  2. Clostridium tyrobutyricum fermenting lactate to butyric acid and hydrogen
  3. Penicillium roqueforti producing methyl ketones from fatty acids
  4. Leuconostoc producing carbon dioxide from citrate in the first hours
Answer and working

A. Propionibacteria turning lactate into propionate, acetate and CO₂

Propionibacteria convert lactate into propionic and acetic acids and CO₂ during warm-room ripening, forming the eyes. Clostridial fermentation is the late-blowing defect; methyl ketones flavour blue cheese; Leuconostoc gives small openings in some Dutch-type cheeses.

Further reading: Hutkins, Microbiology and Technology of Fermented Foods

4 · Vinegar fermentation · medium

Why do industrial vinegar processes stop or recharge before all ethanol is used?

  1. Over-oxidation of acetic acid to CO₂ begins
  2. Yeast restarts alcoholic fermentation once ethanol is exhausted
  3. Acetic acid bacteria then switch to making lactic acid instead
  4. Ethanol below 1% makes the vinegar legally an alcoholic beverage
Answer and working

A. Over-oxidation of acetic acid to CO₂ begins

With no ethanol left, over-oxidising strains oxidise acetic acid to CO₂ and water, losing product; a small residual ethanol is kept and fresh mash added. The other explanations are incorrect.

Further reading: Hutkins, Microbiology and Technology of Fermented Foods

5 · Fermenter design, aeration and agitation · medium

Solid-state fermentation is used for koji and some fungal enzymes. What is its main engineering difficulty?

  1. Supplying enough water, since the substrate is fully submerged
  2. Removing heat and controlling moisture in the bed
  3. Preventing foam from overflowing the top of the vessel
  4. Keeping the culture free of oxygen throughout growth
Answer and working

B. Removing heat and controlling moisture in the bed

With little free water, heat from mould respiration is hard to remove and temperature and moisture gradients form; this limits bed depth and scale. Substrates are moist, not submerged; foaming is a submerged-culture problem; koji moulds need oxygen.

Further reading: Stanbury, Whitaker and Hall, Principles of Fermentation Technology; Doran, Bioprocess Engineering Principles

6 · Batch, fed-batch and continuous fermentation kinetics · easy

In the Monod equation, what is Ks?

  1. The maximum specific growth rate
  2. The yield of biomass per unit of substrate
  3. The substrate concentration at which μ = μmax/2
  4. The rate of substrate feeding in fed-batch culture
Answer and working

C. The substrate concentration at which μ = μmax/2

μ = μmax·S/(Ks + S); when S = Ks, μ = μmax/2. Ks is analogous to Km in enzyme kinetics. μmax is the maximum rate, Y the yield, and feed rate is an operating variable.

Further reading: Stanbury, Whitaker and Hall, Principles of Fermentation Technology; Doran, Bioprocess Engineering Principles

7 · Batch, fed-batch and continuous fermentation kinetics · hard

A chemostat has μmax = 0.5 h⁻¹, Ks = 0.2 g/L, feed substrate 10 g/L, yield 0.5 g/g and dilution rate 0.25 h⁻¹. What is the steady-state biomass?

  1. 5.0 g/L
  2. 2.5 g/L
  3. 4.9 g/L
  4. 9.8 g/L
Answer and working

C. 4.9 g/L

S = Ks·D/(μmax − D) = 0.2 × 0.25/0.25 = 0.2 g/L. X = Y(S_R − S) = 0.5 × (10 − 0.2) = 4.9 g/L. 5.0 ignores residual substrate; 2.5 multiplies by D; 9.8 forgets the yield.

Further reading: Stanbury, Whitaker and Hall, Principles of Fermentation Technology; Doran, Bioprocess Engineering Principles

8 · Batch, fed-batch and continuous fermentation kinetics · medium

A chemostat is run with dilution rate D. What happens if D exceeds the maximum growth rate attainable at the feed concentration?

  1. The culture switches to a stationary phase but stays in the vessel
  2. The biomass concentration rises steadily without limit
  3. The substrate concentration in the vessel falls to zero
  4. The cells wash out of the vessel
Answer and working

D. The cells wash out of the vessel

At steady state μ = D; if D is greater than the highest μ the organism can reach, cells leave faster than they are produced and wash out, while substrate rises to the feed level. Biomass cannot rise without limit in a continuous flow.

Further reading: Stanbury, Whitaker and Hall, Principles of Fermentation Technology; Doran, Bioprocess Engineering Principles

9 · Downstream processing: separation and purification of fermentation products · medium

Which chromatographic method separates proteins mainly by molecular size?

  1. Ion-exchange chromatography
  2. Affinity chromatography
  3. Gel filtration, also called size exclusion
  4. Hydrophobic-interaction chromatography
Answer and working

C. Gel filtration, also called size exclusion

In gel filtration, large molecules are excluded from the pores of the beads and elute first; small ones enter the pores and elute later. Ion exchange separates by charge, affinity by specific binding, and hydrophobic interaction by surface hydrophobicity.

Further reading: Stanbury, Whitaker and Hall, Principles of Fermentation Technology; Doran, Bioprocess Engineering Principles

10 · Recombinant DNA technology and GM foods · hard

How does CRISPR-Cas9 genome editing introduce a change at a chosen site?

  1. A restriction enzyme cuts every GAATTC site in the genome
  2. Agrobacterium T-DNA integrates at the site of the guide RNA
  3. Cas9 inserts a whole plasmid at random sites in the genome
  4. A guide RNA directs Cas9 to cut there, and cellular repair makes the change
Answer and working

D. A guide RNA directs Cas9 to cut there, and cellular repair makes the change

The guide RNA base-pairs with the target next to a PAM sequence, Cas9 makes a double-strand break, and non-homologous end joining (small insertions or deletions) or homology-directed repair with a template makes the edit. Random plasmid insertion and restriction digestion are not genome editing; T-DNA integration is not guided.

Further reading: Codex CAC/GL 44-2003 and related guidelines; Stanbury, Principles of Fermentation Technology

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Fermentation Technology & Food BiotechnologyThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

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