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ICAR AICE-JRF/SRF Tree Physiology: practice questions

ICAR AICE-JRF/SRF (PhD) — Subject 59 Forestry · India · National Testing Agency for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
63written to this exam in this subject
11syllabus units

What this subject covers

How trees grow, take up water and nutrients, fix carbon, allocate it to wood, roots and reproduction, and respond to drought, heat, cold and shade.

In the exams: ICAR AICE-JRF 59 Unit 3 (growth substances) and Unit 12 (enhanced CO2); ICAR AIEEA-PG Group 09 Unit I plant physiology basics

Where the 63 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Tree Physiology. Difficulty: 8 easy, 38 medium, 17 hard.

Elevated CO2 and temperature effects on tree growth8
Water relations: transpiration, cohesion-tension, xylem embolism7
Respiration and carbon allocation7
Photosynthesis in trees: C3 pathway, light response, shade tolerance6
Dormancy, phenology and cold hardiness6
Mineral nutrition and mycorrhizae5
Cambial activity, wood formation and growth rings5
Plant growth regulators and their role in propagation5
Reproductive physiology: flowering, pollination, seed development5
Stress physiology: drought, salinity, flooding, frost5
Shoot and root growth patterns: determinate and indeterminate growth4

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Water relations: transpiration, cohesion-tension, xylem embolism · medium

A branch has maximum conductivity 5.0 units; after drought its conductivity is 2.0 units. What is the percentage loss of conductivity (PLC)?

  1. 60%
  2. 40%
  3. 250%
  4. 30%
Answer and working

A. 60%

PLC = (5.0 − 2.0)/5.0 × 100 = 60%. 40% is the remaining conductivity; 250% inverts the ratio.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

2 · Water relations: transpiration, cohesion-tension, xylem embolism · medium

P50 in a xylem vulnerability curve is:

  1. The pressure that half of all tracheids can withstand in pits
  2. The proportion of vessels embolised at midday in summer
  3. The water potential at which 50% of conductivity is lost
  4. The water potential at which stomata are 50% closed
Answer and working

C. The water potential at which 50% of conductivity is lost

P50 summarises embolism resistance; more negative P50 means more resistant xylem.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

3 · Photosynthesis in trees: C3 pathway, light response, shade tolerance · hard

Tree rings from a drought-prone site show δ¹³C becoming less negative over a period. The most likely physiological interpretation is:

  1. Lower intrinsic water-use efficiency because stomata opened more widely
  2. A switch from C3 to C4 photosynthesis by the trees at the site
  3. Higher intrinsic WUE through tighter stomatal control
  4. Greater photorespiration, which enriches wood in the lighter carbon isotope
Answer and working

C. Higher intrinsic WUE through tighter stomatal control

Less discrimination against ¹³C occurs when internal CO₂ is lower relative to ambient, usually through stomatal limitation, indicating higher A/gs.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

4 · Respiration and carbon allocation · medium

Using Q₁₀ = 2, what is a respiration rate of 2.0 µmol m⁻² s⁻¹ at 15 °C when temperature rises to 20 °C?

  1. 3.00 µmol m⁻² s⁻¹
  2. 4.00 µmol m⁻² s⁻¹
  3. 2.83 µmol m⁻² s⁻¹
  4. 2.50 µmol m⁻² s⁻¹
Answer and working

C. 2.83 µmol m⁻² s⁻¹

2.0 × 2^(5/10) = 2.0 × 1.414 = 2.83. 3.00 assumes half of a doubling is linear; 4.00 is the 10 °C value.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

5 · Mineral nutrition and mycorrhizae · medium

Green leaves contain 2.0% N and freshly fallen leaves 0.9% N (on a comparable basis). What is the N resorption efficiency?

  1. 45%
  2. 110%
  3. 1.1%
  4. 55%
Answer and working

D. 55%

(2.0 − 0.9)/2.0 × 100 = 55%. 45% is the fraction remaining in litter; 1.1 is the difference in percentage points.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

6 · Shoot and root growth patterns: determinate and indeterminate growth · easy

In determinate (preformed) shoot growth, the leaves of next year's shoot are:

  1. Formed in the bud during the previous season
  2. Initiated and expanded throughout the current season
  3. Formed only after the summer solstice
  4. Formed in the roots and moved to the bud
Answer and working

A. Formed in the bud during the previous season

Preformed shoots expand in one spring flush; indeterminate shoots continue to form leaves during the season.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

7 · Dormancy, phenology and cold hardiness · easy

Growth inhibition of a bud that cannot be overcome by favourable conditions until a chilling requirement is met is called:

  1. Ecodormancy
  2. Paradormancy
  3. Endodormancy
  4. Quiescence
Answer and working

C. Endodormancy

Lang's endodormancy is internal to the bud; ecodormancy (quiescence) is imposed by environment; paradormancy by other organs.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

8 · Dormancy, phenology and cold hardiness · medium

Suppression of lateral buds by the terminal bud in the same shoot is an example of:

  1. Endodormancy
  2. Paradormancy
  3. Ecodormancy
  4. Seed dormancy
Answer and working

B. Paradormancy

Inhibition by another organ (apical dominance) is paradormancy.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

9 · Elevated CO2 and temperature effects on tree growth · medium

Tree-ring studies worldwide show a rise in intrinsic water-use efficiency with rising CO₂. What have they generally found for growth?

  1. Growth doubling in every forest biome
  2. Little matching growth gain
  3. Growth declines matching the WUE rise
  4. Growth increases only in heartwood
Answer and working

B. Little matching growth gain

Higher iWUE has often not translated into faster growth, suggesting nutrients, drought or warming limit responses.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

10 · Elevated CO2 and temperature effects on tree growth · easy

Atmospheric CO₂ was about 280 ppm before industrialisation. Roughly what level had it reached by the mid-2020s?

  1. About 300 ppm
  2. About 350 ppm
  3. Over 600 ppm
  4. Over 420 ppm
Answer and working

D. Over 420 ppm

Global mean concentration passed 420 ppm in the early 2020s.

Further reading: See the manual sources: Pallardy, Physiology of Woody Plants; Tyree and Zimmermann; Lambers et al.; Smith and Read; Hartmann and Kester

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Tree PhysiologyThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

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Tree Physiology for other exams

ICAR AIEEA-PG · IndiaNational Postgraduate Entrance Exam · China

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