ICAR AICE-JRF/SRF (PhD) — Subject 59 Forestry · India · National Testing Agency for ICAR
Original practice questions written to the published syllabus · not past papersThe animals of forests and grasslands: mammals, birds, reptiles and amphibians, their habitats, behaviour and population ecology, and how populations are counted.
In the exams: ICAR AICE-JRF 59 Unit 10 (wildlife biology, ornithology, herpetology, census methods); IFoS Forestry Paper II Section B (forest protection and wildlife biology); ICAR AIEEA-PG Group 09 (wildlife); GATE EY; Wildlife Institute of India MSc entrance
How our questions for ICAR AICE-JRF/SRF spread across the units of Wildlife Biology & Ecology. Difficulty: 0 easy, 18 medium, 22 hard.
| Mark-recapture estimation | 6 | |
| Radio telemetry and home-range estimation | 6 | |
| Habitat: food, water, cover and space | 5 | |
| Population dynamics: natality, mortality, carrying capacity | 5 | |
| Census methods: total counts, line transects, pellet counts, camera traps | 5 | |
| Biodiversity monitoring and occupancy surveys | 5 | |
| Mammals of forests and grasslands | 2 | |
| Herpetology: reptiles and amphibians | 2 | |
| Animal behaviour relevant to management | 2 | |
| Wildlife: definitions, values and distribution | 1 | |
| Ornithology: forest birds and their ecology | 1 |
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
Chytridiomycosis, which has caused amphibian declines worldwide, is caused by:
D. A fungus
Batrachochytrium dendrobatidis.
100 ha produce 1,500 kg/ha of dry forage, 50% usable. Each animal needs 2 kg/day for a 180-day dry season. The area supports about:
C. 208 animals
1,500 x 0.5 x 100 / (2 x 180) = 208. 417 ignores the 50% use limit.
Resource selection functions estimate habitat preference by comparing:
A. Used with available habitat
Use relative to availability.
Under logistic growth with r = 0.4, K = 1,000 and N = 250, the growth rate dN/dt is:
D. 75 per year
0.4 x 250 x (1 - 0.25) = 75.
Line transects give 30 detections on 10 km with f(0) = 20 per km. Using D = n f(0)/(2L), density is:
D. 30 per km2
30 x 20 / (2 x 10) = 30. Forgetting the 2 gives 60.
With M = 50, C = 40 and R = 10, Chapman's estimate (M+1)(C+1)/(R+1) - 1 is about:
B. 189
51 x 41 / 11 - 1 = 189.
For open populations with births and deaths over long periods, the appropriate model is:
A. Jolly-Seber
Open-population model estimating survival and recruitment.
Under a 5% of body mass guideline, the heaviest collar for a 40 kg animal is:
A. 2 kg
Maximum collar mass = 40 x 0.05 = 2 kg.
Detection probability per survey is 0.4. The probability of detecting a present species in three surveys is:
A. 0.784
1 - 0.6^3 = 0.784. 0.064 is 0.4^3, all three detecting.
Dynamic occupancy models extend single-season models by estimating:
B. Colonisation and extinction
Changes between seasons.
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