ASRB NET — Farm Machinery & Power / Land & Water Management Engineering / Agricultural Structures & Process Engineering · India · Agricultural Scientists Recruitment Board (ICAR)
Original practice questions written to the published syllabus · not past papersASRB NET — Farm Machinery & Power / Land & Water Management Engineering / Agricultural Structures & Process Engineering is a specialist certification exam run by Agricultural Scientists Recruitment Board (ICAR), for candidates in India. NET: 150 MCQs, 150 marks, 2 hours, −1/3 per wrong answer, English/Hindi, PG level. Combined NET/ARS/SMS/STO recruitment runs prelims, mains and interview.
Official site: pw.live.
We have not been able to confirm these details against the exam body's own specification, so fees, dates and pass marks are left out on purpose. Check the current format, eligibility, fees and dates on the official site.
Soil dynamics and tractor mechanics at PG level: traction prediction, draft prediction, weight transfer, ballast and stability; theory-heavy MCQs.
How soil resists tools and supports wheels: draft, slip, tractive efficiency, weight transfer and stability.
Our 22 ASRB NET questions in this subject: 0 easy, 13 medium, 9 hard, across 11 units.
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
These 10 were written to ASRB NET and are not shown on any other exam's page.
Below its critical depth, a narrow vertical tine mainly
A. displaces soil sideways and compacts it rather than loosening it
Godwin and Spoor showed crescent (upward) failure above critical depth and lateral failure below it. Below critical depth draft keeps rising but loosening is poor and the soil is compacted around the tine.
For a wheel on a saturated clay with φ close to zero, which change raises the maximum soil thrust most?
C. Increasing the contact area, for example by fitting dual wheels or tracks
With φ ≈ 0, H = A·c: thrust depends on area, not load. Ballast mostly increases sinkage and rolling resistance; higher inflation pressure reduces area.
Using the Wismer-Luth wheel numeric Cn = CI·b·d/W and MRR = 1.2/Cn + 0.04, find the rolling resistance of a towed wheel (b = 0.4 m, d = 1.5 m, W = 15 kN) on soil with CI = 1000 kPa.
A. 1.05 kN
Cn = 1000 × 0.4 × 1.5/15 = 40. MRR = 1.2/40 + 0.04 = 0.070. RR = 0.070 × 15 = 1.05 kN. Leaving out the 0.04 term gives 0.45 kN; forgetting to multiply by W leaves a ratio. 2.10 kN doubles the load as if for two wheels.
Why is the front axle of a mechanical front-wheel-drive tractor geared so that its theoretical speed is slightly higher than that of the rear axle?
A. So the front wheels pull rather than brake the tractor, avoiding power circulation and tyre scrubbing
A small positive lead makes the front tyres always contribute thrust. Negative lead makes them brake, causing power windup (circulating power) between axles, extra tyre wear and fuel use; excessive lead also causes scrubbing.
Why is dynamic rearward overturning more dangerous in practice than a calculation based on static equilibrium would suggest?
D. When the rear wheels cannot rotate, axle torque reaction rotates the body about the rear axle faster than an operator can react
If the wheels are held (stuck, or a fixed load), the engine torque acts to rotate the tractor body backwards about the axle. The front can pass the balance point in a very short time. Static formulas assume steady conditions.
Why does wet soil compact more than dry soil under the same wheel load?
C. Water lubricates particle contacts and lowers pre-compression stress, so less stress causes plastic deformation
As moisture rises toward field capacity and beyond, the stress the soil can carry without further compaction falls. Saturated soils can resist compaction briefly because water cannot escape, but they smear and puddle.
A field was subsoiled in autumn but the pan re-formed within one season. Which is the most likely reason?
D. Loosened soil was trafficked, especially when wet, and recompacted
Freshly loosened soil is weak and recompacts easily. Subsoiling should be followed by traffic control and, where possible, biological stabilisation by deep-rooted crops.
Why should operators avoid breaking the hardpan when working lowland rice fields?
C. The hardpan provides the firm layer for traction and reduces percolation losses of ponded water
The plough sole under puddled soil supports cage-wheel lugs and limits deep percolation, keeping water ponded for rice. Deepening the soft layer makes the field harder to traverse.
A tractor has GTR = 0.546 and MRR = 0.079 at 12 % slip (from the Brixius equations). What is the tractive efficiency?
C. 75.3 %
NTR = 0.546 − 0.079 = 0.467. TE = (NTR/GTR)(1 − s) = (0.467/0.546) × 0.88 = 75.3 %. Leaving out the slip term gives 85.5 %; multiplying NTR by (1 − s) without dividing by GTR mixes a ratio with an efficiency. 88.0 % is (1 − s) alone; 41.1 % multiplies NTR by (1 − s).
What is the effect of increasing the lug height of a cage wheel in a deep puddled layer?
C. Lugs reach firmer soil and engage more soil, generally raising pull at the cost of more mud lifted and more power
Taller lugs penetrate further to firmer layers and shear more soil, raising thrust; they also lift and throw more mud and increase input power. Optimum design balances these.
This plan follows where our questions actually fall, so the time goes where the marks are likely to be. It is our reading of the syllabus, not the exam body's weighting.
Read the manual chapters for these first and do every worked question you can find on them.
Aim for one sitting per unit, then mixed questions across them.
Learn the definitions, classifications and standard numbers; these units are more often recalled than worked.
Come back to these after a first pass, untimed, and read every explanation, including for the options you rejected.
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