Agricultural and Biosystems Engineers Licensure Examination (ABELE) · Philippines · Professional Regulatory Board of Agricultural and Biosystems Engineering, PRC
Original practice questions written to the published syllabus · not past papersAgricultural and Biosystems Engineers Licensure Examination (ABELE) is a licensing and registration exam run by Professional Regulatory Board of Agricultural and Biosystems Engineering, PRC, for candidates in Philippines. Paper-based, 2 days (Day 1 6 hours; Day 2 5 hours + 4 hours). Non-programmable calculator only; the Dec 2025 programme bans the Casio fx-991ES/ES Plus by name.
Source: prc.gov.ph.
Checked against the exam body's published information. Formats and fees change; confirm the current edition there before you book.
Bioprocess engineering items on postharvest handling of fruits and vegetables, packhouse operations, drying and processing, with terminology from Philippine Agricultural Engineering Standards.
Keeping fruits and vegetables alive and saleable after harvest: cooling, handling, packhouses, controlled atmospheres and processing.
Our 18 Agricultural and Biosystems Engineers Licensure Examination questions in this subject: 6 easy, 6 medium, 6 hard, across 5 units.
Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.
These 10 were written to Agricultural and Biosystems Engineers Licensure Examination and are not shown on any other exam's page.
A precooler must remove heat at an average rate of 83.3 kW. In tonnes of refrigeration (1 TR = 3.517 kW) this is about
A. 23.7 TR
TR = 83.3/3.517 = 23.7. Multiplying instead of dividing gives 293; 12.66 MJ/h is the TR expressed per hour, so dividing kW by it mixes units. 6.6 divides by 12.66; 27.6 divides by 3.02, the TR in thousands of kcal/h, as if it were kW.
100 kg of broccoli (specific heat 3.9 kJ/kg K) is package-iced to cool it from 20 degC to 2 degC. Assuming the ice melts at 0 degC and ignoring the warming of melt water and all heat gains (latent heat of fusion 334 kJ/kg), the ice melted is about
D. 21.0 kg
Heat = 100 x 3.9 x 18 = 7 020 kJ; ice = 7 020/334 = 21.0 kg. Using the latent heat of vaporisation gives 2.8 kg; omitting the specific heat gives 5.4 kg. 23.4 kg uses a 20 K drop (cooling to 0 degC) instead of 18 K.
Cartons on a forced-air cooling tunnel are cooling unevenly and fan static pressure is high. The most likely cause is
B. too small or misaligned vents
Small or misaligned vents restrict airflow, raising static pressure and leaving some cartons poorly ventilated. Excessive vent area lowers static pressure (though it weakens cartons); humidity does not affect static pressure.
Ergonomic design of a hand-sorting table requires that
B. the belt be within the worker's comfortable reach and the produce rotate as it passes
Workers must see every surface and reach every item, so belt width is limited to arm's reach and roller conveyors rotate the produce. Good, colour-rendering light and controlled speed improve accuracy.
A diverging-roller grader separates fruit according to
B. size (diameter)
The gap between rollers widens along the grader, so smaller fruit drop through first. Weight graders use cups over load cells; colour needs optical sorting.
A line produces 1 600 cartons per hour and each pallet holds 80 cartons. Pallets produced per hour are
A. 20
1 600/80 = 20 pallets per hour. This sets the size of the precooling and cold-store capacity downstream. 128 000 multiplies instead of dividing; 2 is a factor-of-ten slip.
An advantage of a U-shaped packhouse layout over a straight-line layout is that
C. receiving and dispatch share one side, easing supervision and dock use
A U-shape puts both docks on one side, sharing facilities and making supervision easier; the straight line gives the most complete separation of raw and finished produce, so a U-layout needs careful zoning.
Cartons for a packhouse that uses forced-air cooling should be designed so that
A. they fit the pallet footprint without overhang, with vents aligned when stacked
Aligned vents let air pass through the stack, and a carton footprint matched to the pallet (for example 1 200 x 1 000 mm) avoids overhang, which weakens stacks. Unvented cartons defeat forced-air cooling.
One tonne of refrigeration equals about
B. 3.517 kW
1 TR = 12 000 Btu/h = 3.517 kW (211 kJ/min). 12.66 is the MJ/h equivalent written as kW. 0.285 kW is the reciprocal of 3.517.
A dump tank's free chlorine falls rapidly during the first hour of each shift even though dosing is constant. The most likely cause is
C. chlorine demand from soil and organic matter brought in with the produce
Organic matter reacts with free chlorine, so demand is highest when dirty field produce first enters. Continuous monitoring and controlled dosing, with water replacement, keep free chlorine at target.
This plan follows where our questions actually fall, so the time goes where the marks are likely to be. It is our reading of the syllabus, not the exam body's weighting.
Read the manual chapters for these first and do every worked question you can find on them.
Aim for one sitting per unit, then mixed questions across them.
Learn the definitions, classifications and standard numbers; these units are more often recalled than worked.
Come back to these after a first pass, untimed, and read every explanation, including for the options you rejected.
Do these early in revision so they are fast on the day.
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