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ICAR AICE-JRF/SRF Forest Management & Yield Regulation: practice questions

ICAR AICE-JRF/SRF (PhD) — Subject 59 Forestry · India · National Testing Agency for ICAR

Original practice questions written to the published syllabus · not past papers
10worked here, free
27written to this exam in this subject
11syllabus units

What this subject covers

Organising a forest to meet objectives over time: sustained yield, the normal forest, rotation, growing stock and the methods for regulating the cut in even-aged and uneven-aged forests.

In the exams: IFoS Forestry Paper II Section A (forest management and management systems); ICAR AICE-JRF 59 Unit 9; ICAR AIEEA-PG Group 09 (forest management); PRC Forest Resource Management; SAF Certified Forester; Korea Forestry Engineer written subject Forest Management

What ICAR AICE-JRF/SRF asks from it

ICAR AICE-JRF/SRF (PhD) — Forestry, Unit 9

MCQs on sustained yield, normal forest, rotation, estimation of growing stock, density and site quality, regulation of yield by area, volume, increment and number of trees, working plan and joint forest management, and economic criteria (IRR, NPV, cost-benefit).

Where the 27 questions fall

How our questions for ICAR AICE-JRF/SRF spread across the units of Forest Management & Yield Regulation. Difficulty: 6 easy, 9 medium, 12 hard.

Yield regulation by volume and increment (e.g. Von Mantel, Hufnagl, Austrian formula)4
Yield regulation in uneven-aged forests by number of trees and diameter limits3
Harvest scheduling and optimisation (linear programming)3
Multiple-use and ecosystem management3
Objectives and principles of forest management2
Sustained yield and the normal forest2
Rotation: physical, silvicultural, technical, financial, maximum volume2
Growing stock, density and normal growing stock2
Increment and the felling cycle2
Yield regulation by area2
Management of even-aged and uneven-aged forests2

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

1 · Rotation: physical, silvicultural, technical, financial, maximum volume · medium

Compared with the rotation of maximum volume production, the financial rotation at a positive interest rate is usually:

  1. Longer, because interest makes older trees more valuable each year
  2. Identical, because both maximise the same quantity over time
  3. Shorter, because waiting has a cost when money earns interest
  4. Longer at high interest rates and shorter at low interest rates
Answer and working

C. Shorter, because waiting has a cost when money earns interest

Discounting penalises delay, so the age maximising land expectation value is earlier than the culmination of MAI. Higher rates shorten it further.

2 · Growing stock, density and normal growing stock · hard

Why is the triangle approximation of normal growing stock biased for most species?

  1. Real forests always contain more age classes than the rotation allows
  2. The approximation ignores bark, which is half of all stem volume
  3. The approximation counts each age class twice in the calculation
  4. Real stand volume rises along a sigmoid curve, not in proportion to age
Answer and working

D. Real stand volume rises along a sigmoid curve, not in proportion to age

Gn ≈ A V_r/2 assumes volume rises linearly with age; with a sigmoid curve, young classes carry less than linear and middle classes more, so the true sum differs.

3 · Increment and the felling cycle · medium

Shortening the felling cycle in a selection forest generally means:

  1. Heavier, less frequent fellings in each coupe
  2. No change in felling intensity in each coupe
  3. Lighter, more frequent fellings in each coupe
  4. Fellings only in years with high timber prices
Answer and working

C. Lighter, more frequent fellings in each coupe

Yield per felling is roughly the increment accumulated since the last one; a shorter cycle accumulates less, so fellings are lighter but more frequent.

4 · Yield regulation by area · hard

Why does area control guarantee a normal series of age classes after one rotation regardless of the starting structure?

  1. Volume per hectare becomes equal everywhere after the first felling of each coupe
  2. Every part of the forest is felled and regenerated exactly once, in equal annual areas
  3. Area control fells the oldest stands first, which leaves only young ones
  4. Increment equals yield from the first year, which fixes the structure
Answer and working

B. Every part of the forest is felled and regenerated exactly once, in equal annual areas

With A/r regenerated every year for r years, the forest ends with equal areas aged 1 to r. Volume per hectare may still vary with site.

5 · Yield regulation by volume and increment (e.g. Von Mantel, Hufnagl, Austrian formula) · medium

The check method (méthode du contrôle), developed by Gurnaud and Biolley, regulates the cut in selection forests by:

  1. Felling a fixed area each year in strict rotation, roughly equal in size
  2. Applying Von Mantel's formula to the oldest trees only
  3. Repeated full inventories of growing stock and increment, cutting roughly the measured increment
  4. Clear felling whenever the stock exceeds normal
Answer and working

C. Repeated full inventories of growing stock and increment, cutting roughly the measured increment

The check method measures growing stock and increment repeatedly in each compartment and adjusts the cut and structure; it led to modern continuous-cover management.

6 · Yield regulation in uneven-aged forests by number of trees and diameter limits · medium

The yield-regulation method developed by Brandis for the teak forests of Burma is an example of:

  1. An area method using equal annual coupes in clear-felling systems
  2. A linear-programming model maximising net present value
  3. A number-of-trees method based on girth classes and passage times
  4. A volume formula based on normal growing stock
Answer and working

C. A number-of-trees method based on girth classes and passage times

Brandis enumerated trees by girth classes, estimated how long the next class took to reach exploitable size, and set the number of trees removable each year.

7 · Yield regulation in uneven-aged forests by number of trees and diameter limits · easy

In a BDq-managed stand, the yield taken over a felling cycle is approximately:

  1. The entire basal area above the maximum diameter plus all small trees
  2. The growth of the stand back up to its pre-harvest structure
  3. Half the stand basal area, whatever the target structure
  4. The volume of trees below the exploitable diameter
Answer and working

B. The growth of the stand back up to its pre-harvest structure

The stand is cut back to the residual target and grows back over the cycle; the surplus above target is the yield.

8 · Yield regulation in uneven-aged forests by number of trees and diameter limits · hard

Why is area control by age class not possible in a true selection forest?

  1. Trees of all ages grow intermixed on the same ground
  2. Selection forests are too small to divide into coupes
  3. Selection forests have no measurable increment at all
  4. Selection forests are always on slopes too steep to map
Answer and working

A. Trees of all ages grow intermixed on the same ground

Age classes are not separate areas, so yield is regulated through the felling cycle with diameter, number or structure rules.

9 · Harvest scheduling and optimisation (linear programming) · easy

In Johnson and Scheurman's Model I formulation, each decision variable is:

  1. The area regenerated in one period and harvested in a later one, pooled across stands
  2. The price of timber in a given period of the planning horizon
  3. The area of an initial stand assigned to a complete regime over the horizon
  4. The volume of increment in each age class in each year
Answer and working

C. The area of an initial stand assigned to a complete regime over the horizon

Model I uses whole-regime variables per initial stand; Model II uses regeneration-to-harvest variables with pooling.

10 · Multiple-use and ecosystem management · hard

Ecosystem management differs from traditional output-based management mainly by:

  1. Maximising timber yield first and adding conservation only if budgets allow
  2. Abandoning all monitoring so that ecosystems can manage themselves
  3. Managing each stand in isolation without regard to the landscape
  4. Sustaining ecosystem composition, structure and function, from which outputs follow
Answer and working

D. Sustaining ecosystem composition, structure and function, from which outputs follow

Ecosystem management works at landscape scale, emulates natural processes and uses adaptive management.

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Read the subject

Forest Management & Yield RegulationThe full study manual, free ICAR AICE-JRF/SRFFormat, sections and how it has changed

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Forest Management & Yield Regulation for other exams

Indian Forest Service Examination · IndiaRange Forest Officer recruitment · IndiaState Forest Service · India

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