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ASRB NET Instrumentation, Sensors & Process Control: practice questions

ASRB NET — Farm Machinery & Power / Land & Water Management Engineering / Agricultural Structures & Process Engineering · India · Agricultural Scientists Recruitment Board (ICAR)

Original practice questions written to the published syllabus · not past papers
10worked here, free
29written to this exam in this subject
10syllabus units

About ASRB NET

ASRB NET — Farm Machinery & Power / Land & Water Management Engineering / Agricultural Structures & Process Engineering is a specialist certification exam run by Agricultural Scientists Recruitment Board (ICAR), for candidates in India. NET: 150 MCQs, 150 marks, 2 hours, −1/3 per wrong answer, English/Hindi, PG level. Combined NET/ARS/SMS/STO recruitment runs prelims, mains and interview.

Official site: pw.live.

We have not been able to confirm these details against the exam body's own specification, so fees, dates and pass marks are left out on purpose. Check the current format, eligibility, fees and dates on the official site.

Instrumentation, Sensors & Process Control in ASRB NET

Instrumentation for tractor and implement testing (drawbar and PTO dynamometers, torque transducers), grain moisture meters, dryer and store control, data acquisition.

Measuring temperature, pressure, flow, force and moisture, logging the data, and controlling processes automatically.

Our 29 ASRB NET questions in this subject: 8 easy, 16 medium, 5 hard, across 10 units.

10 practice questions, worked

Choose an answer, then open the working. Each explanation says why the right answer is right and why the others are not.

These 10 were written to ASRB NET and are not shown on any other exam's page.

Question 1 · easy

A greenhouse air-temperature sensor mounted in direct sunlight reads several degrees higher than the true air temperature. What is the standard remedy?

  1. Mount it in a ventilated radiation shield at crop height
  2. Replace it with a thermocouple, which is not affected by solar radiation
  3. Move it to the coldest corner of the greenhouse near the side wall
  4. Paint the sensor black so that it absorbs and emits radiation evenly
Answer and working

A. Mount it in a ventilated radiation shield at crop height

The error is radiation heating of the sensor. A shaded, ventilated shield keeps the sensor at air temperature. Any contact sensor in sun has this error; a black sensor absorbs more; a corner position is unrepresentative of the crop.

Question 2 · easy

Why is an electromagnetic flow meter unsuitable for measuring diesel fuel flow to a tractor engine on a test bed?

  1. Diesel is too viscous for the magnetic field to pass through the pipe
  2. The magnetic field would heat the fuel and change its density reading
  3. Diesel does not conduct electricity, so no measurable emf is induced
  4. Electromagnetic meters only work on gases, not on liquids of any kind
Answer and working

C. Diesel does not conduct electricity, so no measurable emf is induced

The meter relies on Faraday induction in a conductive liquid; water, slurries and milk work, but hydrocarbon fuels are non-conducting. Positive-displacement or Coriolis-type mass meters are used for fuel. Viscosity and heating are not the issue.

Question 3 · medium

A submersible pressure sensor at the bottom of a fertiliser tank reads 12.0 kPa gauge. The solution has a specific gravity of 1.2. What is the liquid depth?

  1. 1.02 m
  2. 1.22 m
  3. 1.47 m
  4. 12.0 m
Answer and working

A. 1.02 m

h = p/(ρg) = 12000/(1200 × 9.81) = 1.02 m. 1.22 m assumes water density, the usual error when a level transmitter is set up for water; 1.47 m multiplies by the specific gravity instead of dividing. 12.0 m reads the kPa figure directly as metres.

Question 4 · easy

A hopper load cell has a rated output of 2 mV/V at its 500 kg capacity and is excited at 10 V. What output is expected with 200 kg in the hopper?

  1. 8 mV
  2. 20 mV
  3. 0.8 mV
  4. 4 mV
Answer and working

A. 8 mV

Full-scale output = 2 mV/V × 10 V = 20 mV at 500 kg; at 200 kg, 20 × 200/500 = 8 mV. 20 mV is the full-load value; 4 mV forgets the excitation and multiplies 2 by 200/100; 0.8 mV leaves out the 10 V excitation.

Question 5 · medium

1000 kg of maize is dried from 20% to 14% moisture (wet basis). How much water is removed?

  1. 60.0 kg
  2. 930.2 kg
  3. 69.8 kg
  4. 87.2 kg
Answer and working

C. 69.8 kg

Dry matter is conserved: 1000 × 0.80 = 800 kg. Final mass = 800/0.86 = 930.2 kg; water removed = 1000 − 930.2 = 69.8 kg. 60.0 kg subtracts the percentages directly on the initial mass, the most common error; 930.2 kg is the final mass, not the water removed; 87.2 kg applies the dry-basis drop to the whole 1000 kg instead of to the 800 kg of dry matter.

Question 6 · medium

Two laboratories report different moisture contents for the same grain lot, both using correctly operated ovens. What is the most likely reason?

  1. Oven methods are always random to about ±5%, so any two laboratory results on one lot will disagree
  2. One laboratory reported the moisture on a wet basis and the other did too
  3. They used different standard oven methods: temperature, time, ground or whole grain
  4. Oven drying measures only free water, which changes daily in stored grain
Answer and working

C. They used different standard oven methods: temperature, time, ground or whole grain

There is no single oven method: national and international standards differ in temperature, time and whether the sample is ground, and the results differ systematically. A moisture value should name its method. Both labs using wet basis would not explain the difference.

Question 7 · easy

The wet bulb of a psychrometer in a seed store is not ventilated. How does this affect the relative humidity calculated from it?

  1. The wet bulb reads too low, so the RH comes out too low
  2. The dry bulb reads too high, so the RH comes out too low
  3. The wet bulb reads too high, so the RH comes out too high
  4. Nothing changes, because the wet bulb does not need airflow
Answer and working

C. The wet bulb reads too high, so the RH comes out too high

Without adequate air speed, evaporation from the wick is limited and the wet bulb does not cool fully; a smaller wet-bulb depression is interpreted as moister air, so RH is overestimated.

Question 8 · easy

What is the correct order of a PLC scan cycle?

  1. Execute program, read inputs, update outputs, then housekeeping
  2. Update outputs, read inputs, execute program, then housekeeping
  3. Read inputs, update outputs, execute program, then housekeeping
  4. Read inputs, execute program, update outputs, then housekeeping
Answer and working

D. Read inputs, execute program, update outputs, then housekeeping

The PLC copies all inputs into the input image, executes the program using that image, writes results to the outputs, then does communication and diagnostics. Because inputs are frozen during execution, the program sees a consistent snapshot.

Question 9 · hard

During start-up of a cold grain dryer, the burner valve sits at 100% for 20 minutes while the PI controller's error stays large. Once air temperature reaches setpoint, it overshoots badly. What is the cause and remedy?

  1. Derivative kick from the setpoint step; move the derivative action from the error signal onto the measurement
  2. Too wide a proportional band; narrow it until the loop oscillates and leave it at that setting
  3. Integral windup during saturation; add anti-windup that limits integration while the valve is saturated
  4. Sensor time constant too short; fit a thicker thermowell so the reading changes more slowly
Answer and working

C. Integral windup during saturation; add anti-windup that limits integration while the valve is saturated

With the output saturated, the integral term keeps accumulating error it cannot act on; when the process arrives, the stored integral holds the valve open and causes overshoot. Anti-windup (clamping or back-calculation) stops this. Slowing the sensor would make control worse.

Question 10 · hard

A continuous-flow dryer controls outlet grain moisture by adjusting discharge rate. The moisture sensor at the outlet sees a change about 40 minutes after the rate changes, and the loop oscillates. Which approach is most appropriate?

  1. Raise the proportional gain so the controller reacts more strongly to each reading
  2. Add strong derivative action on the delayed outlet-moisture measurement signal
  3. Detune the loop and add model-based prediction or feedforward from inlet moisture
  4. Replace the PI loop with on-off control of the discharge auger motor speed
Answer and working

C. Detune the loop and add model-based prediction or feedforward from inlet moisture

Long dead time makes high-gain feedback oscillate. The usual cures are lower gain, feedforward from measured inlet moisture and air temperature, or a model that predicts outlet moisture. More gain or derivative action on a delayed signal worsens the oscillation, and on-off control would cycle.

A study plan for Instrumentation, Sensors & Process Control in ASRB NET

This plan follows where our questions actually fall, so the time goes where the marks are likely to be. It is our reading of the syllabus, not the exam body's weighting.

  1. First, the heavy units (66% of the 29 questions): Programmable logic controllers (6, 21%); Force, torque and strain: strain gauges and load cells (5, 17%); Moisture measurement (4, 14%); Pressure, flow and level measurement (4, 14%).

    Read the manual chapters for these first and do every worked question you can find on them.

  2. Then the middle band: Control modes: on-off, P, PI and PID (3, 10%); Data acquisition and data loggers (2, 7%); Temperature transducers (2, 7%); IoT sensor networks (1, 3%).

    Aim for one sitting per unit, then mixed questions across them.

  3. Then the lighter units: Signal conditioning (1, 3%); Static and dynamic characteristics of instruments (1, 3%).

    Learn the definitions, classifications and standard numbers; these units are more often recalled than worked.

  4. Leave time for the hard ones: Control modes: on-off, P, PI and PID (2 hard of 3), Data acquisition and data loggers (1 hard of 2), Force, torque and strain: strain gauges and load cells (1 hard of 5).

    Come back to these after a first pass, untimed, and read every explanation, including for the options you rejected.

  5. Bank the easy marks: Pressure, flow and level measurement (2 easy of 4); Temperature transducers (1 easy of 2).

    Do these early in revision so they are fast on the day.

  6. Finish timed. Sit the subject as a timed set without notes, mark it, and send each wrong answer back to its unit above.

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